C :: Count Characters In A File And Define How Many Times Each One Occurs
Feb 16, 2013
My problem is to count the characters in a file and define how many times each one occurs.Characters who are not found must not be included in the table; The output must be a table - like that -
”| character | ASCII- DEC | ASCI – HEX | how many times it occurs |”
This my function:
Code:
int f2(FILE *p1)
{
FILE *g3;
int char_count[256]={0};
char ch;
int n=0;
if(!(g3=fopen("D:zz.txt", "w"))){
[Code] ....
It must look like this:
| D | 68 | 44 | 2 |
| 2 | 50 | 32 | 1 | and so on...
I am writing this program that is supposed to read a file, put the data into an array, alphabetize, count how many times each word appears and print to an output function. I posted before on how my program had an error when I ran it but I have fixed that. Now my outputArray file is empty. It gets created but there's nothing in it.
I'm supposed to write a program to read a text file and display the following:
a) alphabetic letters //finished with b) digits // finished with c) other characters that are not alphabetic letters and not digits //finished with d) total characters read
The bold part above confused me, by total characters, does it mean the alphabetic letters + other characters? how would I put that in my code?
Code: #include <stdio.h> int main (void) { int curCh; int countCh = 0;
Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...).
For every char of the given alphabet, count how many times in the string
1----- the char is preceded by its predecessor in the alphabet (consider that the predecessor of 'a' is '9') 2----- the char is followed by its successor in the alphabet (consider that the successor of '9' is 'a') 3----- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition) 4----- what is the longest substring of characters strictly rising (the following is greater (>) of the previous) 5----- what is the longest substring of successive characters (i.e.: fhkjshdfruytyzABCDEfglsj => 7) 6----- the frequencies of any char (if in the string the character 'g' occurs 12 times, its frequency is 12)
I have program that is supposed to read in a story from an input file and separate the words and output the lines on which the word occurs. It needs to read in another input file that has a list of words (1 per line) to ignore. i.e. skip them when running through the story. This is what I have so far, I've changed multiple things trying to get it running....
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words #include<iostream> using namespace std; int main() { int num; cout << "Enter a number between 0 and 9999: ";
My goal is to create a program that reads a string and counts how many Uppercase, Lowercase, Spaces, and digits there are in the string. Right now this the output i get.
#include <stdio.h> #include <stdlib.h> #include <ctype.h> int main() { int iochar; char string;
In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.
int buscarNumOrdenado (int x [MAX]) //MAX is the define { int num,d, LimiteInferior, LimiteSuperior,mitad; d=0; LimiteInferior = 0; LimiteSuperior = MAX-1;
I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.
Here's what the code looks like:
Code: #include <iostream> #include <ctime> #include <cstdlib> using namespace std; int Generate() { int r= rand(); int s= r%7; [Code] ....
The thing is, when I don't create a prototype of count and straightaway define it before void main() my program runs, but it gives error in this program that "extra parameter in call to count()" But what to do then?
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had: Alphabetical characters...: 0 Numbers...................: 0 Blanks....................: 3 Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream> #include <string> #include <iomanip> #include <cctype> #include <sstream> using namespace std; int main() { string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I was doing a side project from my textbook about finding the mode, which is the number that occurs most often in a sequence of numbers. I racked my brain on this for an embarrassing amount of time and finally came up with this, which I think works but for some reason I still feel like I'm not done.
#include "stdafx.h" #include <iostream> using namespace std; void mode(int *, int); void main() { const int NUMBERS = 15; int list[NUMBERS] = {99,73,56,14,28,42,93,64,51,26,56,16,38,81,98}; mode(list,NUMBERS);
[Code] ....
Console Output:
Final Mode 56 Press any key to continue . . .
There it is, I would have commented more but I couldnt think of the right words to explain everything.
so i have to read a text file with an unknown number of lines and allocate memory to for the number of items in the text file.currently i read the entire file(counting the number of lines). i allocate memory according to the number of lines read and then use fseek() with an offset of zero to allow for the second read .
Is it possible to define and write your own file extension. if so is it an easy process or a complex waste of time. All I want to do is define a source file for a programming language I write.
I program unix sokcet programming , and part of my code is ti open file from server and open it , but i surprised with this wierd error i dont have any reason for it ?
I'm trying to make program that will read text from a file and show what words occur how many times. I'm trying to make it so that if a new string comes, it saves it into wlist[], and counts 1 to wcount[]. If the same word is there, it will just add 1 to wcount[]. The program will end when it gets to the end of a file.
I don't know the reason, but I can't get strcmp and strcpy to work. I had to put a pointer in curword, just to make it compile.
When you have to write data on a file in binary mode multiple times (without closing the file), is the put pointer left where you ended writing the last time, or do you have to use tellp() or seekp() again and again to make sure you write at the right place?
I would have the same question about the get pointer, does he stay in place after you're done reading something (without closing the file, of course), or do you have to set it back at the right place with seekg() ??
