I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words
#include<iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number between 0 and 9999: ";
[Code] ....
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had:
Alphabetical characters...: 0
Numbers...................: 0
Blanks....................: 3
Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cctype>
#include <sstream>
using namespace std;
int main() {
string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
I wrote a function to count the number of characters in a string. Curious as to why I have to return x-1 and why x isn't the number of characters.
Code:
int count(char *string){
55 int x = 0;
56 char *p;
57 p = string;
58
[Code] .....
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
void count();
void main() {
char c[100];
cout<<"Enter a string upto 99 characters(spaces included):"<<endl;
[Code] ....
The thing is, when I don't create a prototype of count and straightaway define it before void main() my program runs, but it gives error in this program that "extra parameter in call to count()" But what to do then?
My program reads a string of characters. Prints all occurrences of letters and numbers, sorted in alphabetical and numerical order. Letters will be converted to uppercase.Other characters are filtered out, while number of white spaces are counted.
the problem is it crushes when i run the program
Here is my code
#include <iostream>
const int SIZE = 100;
using namespace std;
int main() {
char *pStr, str[SIZE] = "", newStr[SIZE] = "", ch;
int count = 0, i = 0, j;
[Code] .....
In this assignment, you must enter a file and get out of it this:
Summary
Total characters: 8282
Vowels: 2418
Consonants: 3970
Letters: 6388
Digits: 174
Left parentheses: 17
Right parentheses: 17
Single quotes: 17
Double quotes: 14
Other: 1655
Here is my code:
#include <iostream>
#include <fstream>
#include <cctype>
using namespace std;
char ch;
bool isVowel (char);
[Code] .....
My goal is to create a program that reads a string and counts how many Uppercase, Lowercase, Spaces, and digits there are in the string. Right now this the output i get.
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
int main() {
int iochar;
char string;
[Code] .....
I'm supposed to write a program to read a text file and display the following:
a) alphabetic letters //finished with
b) digits // finished with
c) other characters that are not alphabetic letters and not digits //finished with
d) total characters read
The bold part above confused me, by total characters, does it mean the alphabetic letters + other characters? how would I put that in my code?
Code:
#include <stdio.h>
int main (void)
{
int curCh;
int countCh = 0;
[Code]....
#include <stdio.h>
#include <string.h>
int main() {
char string[100];
int c= 0, count[26] = {0};
printf("Enter a string: ", string);
[Code]...
This is the output I receive:
I need counting the Uppercase Letters.
My problem is to count the characters in a file and define how many times each one occurs.Characters who are not found must not be included in the table; The output must be a table - like that -
”| character | ASCII- DEC | ASCI – HEX | how many times it occurs |”
This my function:
Code:
int f2(FILE *p1)
{
FILE *g3;
int char_count[256]={0};
char ch;
int n=0;
if(!(g3=fopen("D:zz.txt", "w"))){
[Code] ....
It must look like this:
| D | 68 | 44 | 2 |
| 2 | 50 | 32 | 1 | and so on...
I'm writing a program that reads and counts all the printable characters (ASCII 32-126)found in a text file.
For example if the text file read: Why so serious?
The output to the screen would display(in order of ascii value however):
Character-----Total
W--------------1
h--------------1
y--------------1
s--------------3
o--------------2
etc...
However, I don't think it's reading any of the characters.
#include <iostream>
#include <iomanip>
#include <fstream>
#include <cmath>
#include <string>
using namespace std;
int main() {
int i, count[127];
[Code] .....
so my question is i want to print characters,no string just an array of characters,i do this but it s not working,maybe i have to put the '' at the end?
Code:
int main() {
int i;
char ch[5];
for(i = 0; i < 5; i++) {
scanf("%c",&ch[i]);
[Code]...
Im supposed to find the common characters between two string characters, assuming that the user wont input duplicate letters like ddog. When I run my code I get an output of a question mark upside down. Here is my code with comments on what each part is supposed to do
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main(){
char str1[20], str2[20],remp = ' ';
int size1,i,j,temp;
printf ("Input the first string");
[Code]...
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I wrote a program which sends a starting and ending range to other processes and the processes calculate the prime numbers in that range and return the count of prime numbers to the head process, process 0. But this is not working properly at the moment. I realize I still have to split up the range based on how many processes I have...I still have not figured out how I want to set that up. I
Code:
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
int isPrime(int num);
int main(int argc, char **argv){
}
[code]....
I have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream>
#include <conio.h>
using namespace std;
int main ()
[Code] ....
This could be non contiguous. As an example
string1: "Hello"
string2: "Heelblloo"
occurrences of string 1 in string2 is 2*3c2*2=12
among 2 e's in string 2, we can select only one and thus 2 possible ways.similarly for l and o.
I am using this code that to check a set of values from a text file and show it on the output.
Code: void MatchNumber(int b) {
vector<Rect> rects;
ifstream theFile("CheckNumber.txt");
double x1,y1,x2,y2;
while(theFile >> x1 >> y1 >> x2 >> y2 ){
rects.push_back(Rect(x1,y1, x2,y2));
}
int num=0;
[code]....
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5
The 5 repeated = 1 times
The common number is = 6
The 6 repeated = 1 times
The common number is = 4
The 4 repeated = 1 times
The common number is = 5
The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5
The common number is = 6
The common number is = 4
The common number is = 5
The common number is = 5
The common number is = 8
The common number is = 9
The common number is = 6
The common number is = 6
[code]....
How can I do that?
iam trying to count the same numbers in an array just once like
38
38
40
38
40
37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream>
using namespace std;
int main(){
[Code].....
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
int IntegerArray::countBelowAverage(int numBelowAvg) {
avg=IntegerArray::getAvg();
for(int ct=0; ct<avg; ++ct) {
numBelowAvg=ct;
}
return numBelowAvg;
}
My output from this is always 0 and I know that there are numbers below the avg.
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int inputs[30];
int numofloops;
int maxvalue = inputs[0];
[Code]...
I must count the number of occurrence of all numbers in array , i wrote a code but it does not work properly
#include <iostream>
int main (){
int i,n,tmp,counter=0;
std::cout<<"Enter the size of the array:"<<std::endl;
std::cin>>n;
int *Array=new int [n];
int *counterArray=new int [n];
[Code] .....
the text file looks like: one hello hi twenty-five billion fifty maths three thousand and two
output: count the number of text numbers: 4
i have read a lot of about lists but i dont understand this. I know its something like dogs on leash where we have
dog1->dog2->dog3->....
and
Code:
struct DOG
{char* (name of a dog of first leash)
DOG* (next dog ) } I have written something like this but this doesnt work as i wanted Code: #include <iostream>
using namespace std;
struct line {
[Code]....
I wanted to make program where i can type XX numbers , then cout those numbers without changing the order, and my next exercise is to change order in this programme from end to start.
I am stuck in this program, Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...). For every char of the given alphabet, count how many times in the string
1-- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
Code:
#include<stdio.h>
#include<conio.h>
#include<string.h>
[Code]...
2-what is the longest substring of characters strictly rising interm of ASCII code(the following is greater (>) of the previous)
3- what is the longest substring of successive characters interm of given string rannge (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
I'm having trouble with how to find the count and sum of all numbers.
The file, called question1.txt, contains numbers:
1
2
3
4
5
0
0
0
-2
-2
Here's my code:
Code:
#include <stdio.h>
#include <stdlib.h>
int main (void)
{
FILE* spIn;
FILE* spOut; //for output file
int numIn;
[Code]...