I have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream>
#include <conio.h>
using namespace std;
int main ()
[Code] ....
Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...).
For every char of the given alphabet, count how many times in the string
1----- the char is preceded by its predecessor in the alphabet (consider that the predecessor of 'a' is '9')
2----- the char is followed by its successor in the alphabet (consider that the successor of '9' is 'a')
3----- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
4----- what is the longest substring of characters strictly rising (the following is greater (>) of the previous)
5----- what is the longest substring of successive characters (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
6----- the frequencies of any char (if in the string the character 'g' occurs 12 times, its frequency is 12)
This could be non contiguous. As an example
string1: "Hello"
string2: "Heelblloo"
occurrences of string 1 in string2 is 2*3c2*2=12
among 2 e's in string 2, we can select only one and thus 2 possible ways.similarly for l and o.
I'm trying to "tokenize" a string using std::string functions, but I stored the text in a char array. When I try to convert it to a string, the string has the first character right but the rest is garbage.
// Get value from ListBox.
char selectedValue[256];
memset(selectedValue, NULL, 256);
SendMessage(GetDlgItem(hWnd, IDC_LB_CURRENTSCRIPT), LB_GETTEXT, selectedIndex, (LPARAM)selectedValue);
// Convert to string.
string val(selectedValue);
[Code] ....
A string class that finds a char in the string?
View 1 Replies View RelatedHow you would overload an operator for Common Data-types like "char" and "int".
I often use bool arrays to create a multilevel-trigger-systems, when iterating over multiple containers or waiting for two events to occur at the same time.
For example:
I would define..
bool trigger[2] = {0, 0};
And when doing work via a loop, I use it like so:
while(trigger[0] != 1 && trigger[1] != 1)
You can probably see where I'm going with this. I want to be able to use my bool array with the "!" operator.
So if "trigger == 0" (as a whole), it returns false.
How can I achieve this?
Can you create custom operators? Say if I wanted to create "or-gates" or "xor-gates" etc.
i couldn't count the 2d string. my string is list[100][100] = {"Batuhan","Jeyhun","Tashtanbek"} this is a food line in cafeteria. i want to add a person to this list but i couldnt do it because i dont know the length of my list. it will be more than 3 after i add a person but what if i would add another person after that ? In that case i couldnt be able to tell how long is my line.And after i add people to my list i want to print that list. here is where i came so far:
case 1:
printf("Enter the name of the person to be added
");
printf(">>");
k=0;
[Code].....
I am creating a program where I count all the letters of the alphabet from a user submitted string.
How would I go about this?
I am completely new, so simplicity is best. I am suppose to use arrays.
I am writing a program that counts the number of sentences in a string. I count the number of '.' '?' '!'. However, there are Mr. Mrs. PhD. Dr. .
int number_of_sentences = 0;
for(unsigned int i=0; i <= text.length()-1; i++){
if(text[i] == '.' || text[i] == '?' ||text[i] == '!'){
++number_of_sentences;
}
}
return number_of_sentences;
I'm looking for a program to read a file to look for strings and add a count.
kill.log in the same folder as program
player1 was killed by player2
player2 was killed by player1
4 strings
player1 was for "d1" add count
player2 was for "d2" add count
by player1 for "k1" add count
by player2 for "k2" add count
cout << Player 1 kills: << k1 << deaths << d1;
cout << Player 2 kills: << k2 << deaths << d2;
add up each time.
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words
#include<iostream>
using namespace std;
int main() {
int num;
cout << "Enter a number between 0 and 9999: ";
[Code] ....
#include <fstream>
#include <iostream>
#include <string>
[Code].....
When I try to run my program I get:
1>LINK : error LNK2001: unresolved external symbol _mainCRTStartup
1>C:UsersDocumentsVisual Studio 2010ProjectsCS 111Lab10Lab10DebugLab10.exe : fatal error LNK1120: 1 unresolved externals
What I'm trying to do is get my program to count the number of words in an inputted data file. I've attached the assignment directions
Attached File(s) : lab10_data_.zip (9.27K)
I have designed a class called matrixType that has some overloaded operators (+, -, *, and <<); the arithmetic operator functions of which are overloaded as member functions of the class. As an alert mechanism, I want a message displayed when two matrices of dissimilar sizes are added/subtracted OR when two incompatible matrices are being multiplied. Displaying this error message is not the problem. However, I want a scheme where on detecting two matrices’ incompatibility, the operator function returns the error message (a string datatype) instead of what would be an erroneous result (the expected matrixType object).
In other words, what I may be essentially asking is: Is it possible for a function, say,
matrixType matrixType::operator+(const matrixType& otherMatrix) const
{
.
.
.
}
to return a dataType (like a string) other than the expected matrixType?
I wrote a function to count the number of characters in a string. Curious as to why I have to return x-1 and why x isn't the number of characters.
Code:
int count(char *string){
55 int x = 0;
56 char *p;
57 p = string;
58
[Code] .....
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
void count();
void main() {
char c[100];
cout<<"Enter a string upto 99 characters(spaces included):"<<endl;
[Code] ....
The thing is, when I don't create a prototype of count and straightaway define it before void main() my program runs, but it gives error in this program that "extra parameter in call to count()" But what to do then?
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had:
Alphabetical characters...: 0
Numbers...................: 0
Blanks....................: 3
Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream>
#include <string>
#include <iomanip>
#include <cctype>
#include <sstream>
using namespace std;
int main() {
string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
I have this problem that I don't know how to sort out. I have a feeling it's really simple
#include <iostream>
#include <string>
void main () {
char test[10] = "gorilla";
char try = test[1];
cout << try;
}
I get the error:
lab4.cpp:6: error: expected primary-expression before "char"
lab4.cpp:6: error: expected `;' before "char""
how can I find ASCII value (0..255) of a character char in a string?
I have an array of char:
Code: char myarray[50]; and I need to have ASCII value of character eg myarray[10]. How can I do that?
I have some code:
char cHomeTeamFaceOffsPercentageWon[100];
memcpy(cHomeTeamFaceOffsPercentageWon,cSqlHomeTeamFaceOffsPercentageWon,100);
After this, for example, cHomeTeamFaceOffsPercentageWon is, "29%".
Then, I use
std::string szwPercentageWon = std::string(cHomeTeamFaceOffsPercentageWon);
szwPercentageWon is then, "2". Shouldn't this convert correctly, to "29%" as well.
Or is there something I'm missing? Maybe the termination character, or something.
Is there anyway to convert std::string to char*?
Like:
std::string x="hello world";
char* y=x;
I have had quite a head spinner on trying to transform a string into a char. I've been trying to do this for the project below.
[URL] ....
std::string str = "string";
const char* chr = str.c_str();
cout << *chr << endl;
Above is the code I have tried using and it stores data under *chr, it however only stores one letter rather than the entire word like for example string.
I have this code working:
char tmp_wku[3];
tmp_wku[0]=0x01;
tmp_wku[1]=0x9D;
tmp_wku[2]=0x62;
char tmp_com[11];
[Code] ....
This sends the buffer to a LIN modem. My question is: can this be done better. If I have a astring of hex numbers like "09 98 88 55 42 FF 00 00 FF BD 89". How could I send this without manually makng a char with hex numbers?
Is there a way to replace 3 char's in a string. For example i have a string containing
s = "The school is called 7x8"
I want to replace the "7x8" with "LSU". But the "x" can be any letter or number.
Is there a way to do that ?
I've to do a function that removes char(input by user) from string , only if it appeared and to reduce spaces.
for instance: string = abcabcd ; and the char= c/
the return string is : ababd
void removeChar(char string2[SIZE], char ch) {
//---NOTE--- its not completely works - there is a problem i.
int read = 0, write = 0;
[Code].....
I have a question on conversion between char & string. I have cut & pasted the part of the code from my C++ code and my function "decryptPwd" uses C style code with "char" etc.
I need to pass a string (mypwd) somehow to this function after conversion & then compare it to another string (newmypwd).
I tried - "decryptPwd(mypwd.c_str())==newmypwd.c_str()" but it did not work.
..
#include <string>
..
char* decryptPwd(char hash[64]);
main () {
string mypwd;
string newmypwd;
if (decryptPwd(mypwd)==newmypwd)
[Code] ...
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
char states [6][10]={"start","InNum","InID","Done","InASG","InCOM"};
char state[] = "start";
[Code] .....
I am trying to take each character from a file and put it in a string and print this string but when i write this code , it doesn't give any output.