C :: For Every Char Of Given Alphabet - Count How Many Times In The String
Feb 1, 2013
Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...).
For every char of the given alphabet, count how many times in the string
1----- the char is preceded by its predecessor in the alphabet (consider that the predecessor of 'a' is '9')
2----- the char is followed by its successor in the alphabet (consider that the successor of '9' is 'a')
3----- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition)
4----- what is the longest substring of characters strictly rising (the following is greater (>) of the previous)
5----- what is the longest substring of successive characters (i.e.: fhkjshdfruytyzABCDEfglsj => 7)
6----- the frequencies of any char (if in the string the character 'g' occurs 12 times, its frequency is 12)
I have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream> #include <conio.h> using namespace std; int main ()
My problem is to count the characters in a file and define how many times each one occurs.Characters who are not found must not be included in the table; The output must be a table - like that -
”| character | ASCII- DEC | ASCI – HEX | how many times it occurs |”
This my function:
Code: int f2(FILE *p1) { FILE *g3; int char_count[256]={0}; char ch; int n=0; if(!(g3=fopen("D:zz.txt", "w"))){
[Code] ....
It must look like this: | D | 68 | 44 | 2 | | 2 | 50 | 32 | 1 | and so on...
I am writing this program that is supposed to read a file, put the data into an array, alphabetize, count how many times each word appears and print to an output function. I posted before on how my program had an error when I ran it but I have fixed that. Now my outputArray file is empty. It gets created but there's nothing in it.
In this program what i'm doing is to search for a number when the vector is in order, and count how many times that number appears, the problem is that count how many times the number does not appear, but when its appear the program stays in an "standby mode" and the cursor does not move.
int buscarNumOrdenado (int x [MAX]) //MAX is the define { int num,d, LimiteInferior, LimiteSuperior,mitad; d=0; LimiteInferior = 0; LimiteSuperior = MAX-1;
I'm running a game online and designing a program to generate Enemy Stats. Basically, it's supposed to generate 25 numbers between 0 and 7(to represent 8 Attributes on a 25 Point Buy system) and count how many times each number shows up.
Here's what the code looks like:
Code: #include <iostream> #include <ctime> #include <cstdlib> using namespace std; int Generate() { int r= rand(); int s= r%7; [Code] ....
I am trying to keep a count on a variable name stored within a structure as char*'s. They are of the same field and I do not know how many there will be so I would like to keep a standard name and append the count.
So say I have a variable name such as "desk", but as I have many of these said desks so I would like to call them "desk1", "desk2", "desk3" and so forth. Any recommendations on how I could do this?
Also since this is somewhat relevant is there an easy way to convert from an integer to a string, something that would work like atoi() in reverse? I wouldn't mind writing a method to do so myself but haven't a clue as to how.
Write a count controlled loop than can print "i" char. The user is supposed to input a integer and that integer is how many asterisks there is on the blade, in this case it is 5.
* * ** ** **--------------- ******* ** ** ** * ** * -10 Rows high ** -blade always connects on second row of handle ** ** ** **------------------
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I'm trying to determine the number of times I have to change each specific character in a string to make it a palindrome. You can only change a character one at a time from the end.
Example: "abc" -> "abb" -> "aba" should print 2. "aba" will print 0 because it's already a palindrome. "abcd" -> "abcc" -> "abcb" -> "abca" -> "abba" will print 4 because it took 4 changes to make a palindrome.
I'm not too sure how to approach this - I figured out the case where if it's a palindrome (if reversed string is the same) then it'll print out a 0.
int main() { int number; cin >> number; //expecting a number for first line user input for (int i = 0; i < number; i++) { string str;
i couldn't count the 2d string. my string is list[100][100] = {"Batuhan","Jeyhun","Tashtanbek"} this is a food line in cafeteria. i want to add a person to this list but i couldnt do it because i dont know the length of my list. it will be more than 3 after i add a person but what if i would add another person after that ? In that case i couldnt be able to tell how long is my line.And after i add people to my list i want to print that list. here is where i came so far:
case 1: printf("Enter the name of the person to be added "); printf(">>"); k=0;
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words #include<iostream> using namespace std; int main() { int num; cout << "Enter a number between 0 and 9999: ";
I'm currently working on a project that utilitzes a Caesar Cipher. Basically, it reads input from a file and then, depending upon the input file, requires encrypting or decrypting. The cipher used to encrypt/decrypt simply adds/subtracts an integer from each character in the input file. All input is lowercase alphabetic characters (ASCII 97-122). My problem is trying to figure out how to wrap the ciphered characters, e.g., if the cipher require a shift of +5 and the character read was 'x', a shift of +5 to the right would produce 'c' (beginning with 'x' and counting up 5 letters: 'y', 'z', 'a', 'b', 'c').
I've written some crude and cumbersome loops that will work, but there has to be a better way. It is my understanding that it can be done using the modulus operation, %, but I cannot figure out how. I spent several hours trying to figure out the modulus approach, but no luck.
im working on our project and this part of the project which says to add a new a room.
Details:
Open the file (ROOMS) that maintains all the ROOMS records.
Ask the user to enter the required data Room_Type and Room_Rate, then save it.
Keep asking the user (Do you want to continue?) until the user enters (N OR n), this should stop the data entry and get the user back to the main menu.
Myproblem :: i keep getting error at the bottom says my while statement is wrong " IntelliSense: no operator "!=" matches these operands"
My other problem:: how do i get back to the main menu?
so what ive done till now is.
#include <iostream> #include <fstream> #include <string> using namespace std; int main() { int choice,i=1,Room_rate; string alphabet; string Room_type;
The thing is, when I don't create a prototype of count and straightaway define it before void main() my program runs, but it gives error in this program that "extra parameter in call to count()" But what to do then?
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had: Alphabetical characters...: 0 Numbers...................: 0 Blanks....................: 3 Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream> #include <string> #include <iomanip> #include <cctype> #include <sstream> using namespace std; int main() { string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
I'm trying to make an alphabet soup on C programming, and I'm stuck with a problem.I need to make a function able to automatically find all the words that exist in alphabet soup.
I know how to store numeric data using keywords int, long, float, and so on. I'm making my own program called "Who is your soul-mate".The only question I want to ask is what's the keyword for storing alphabet data? As you can see below on my source file. I want to replace "int" keyword with another keyword that can store alphabet data. It's all in standard C.
#include <stdio.h> int soulm01, soulm02, soulm03; int year_of_birth; int main(void)
