Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...).
For every char of the given alphabet, count how many times in the string
1----- the char is preceded by its predecessor in the alphabet (consider that the predecessor of 'a' is '9') 2----- the char is followed by its successor in the alphabet (consider that the successor of '9' is 'a') 3----- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition) 4----- what is the longest substring of characters strictly rising (the following is greater (>) of the previous) 5----- what is the longest substring of successive characters (i.e.: fhkjshdfruytyzABCDEfglsj => 7) 6----- the frequencies of any char (if in the string the character 'g' occurs 12 times, its frequency is 12)
I'm just trying to find out if the way I've setup my code currently allows me to count the letters as they occur? I don't yet see how to do it but I need clarification. Ideally the function letterCounter would do the counting but atm I'm just trying to figuring it out in the display function.
I have to count the letters from a text file into an array so the first spot is the number of A's second spot number of B's and so on then take the array and sort it in decending order how could i do this without loosing track of where the numbers go so if there are more b's than a's they switch but how will i know where each letter has moved in the array after it has been sorted?
I try to use "rand" to create 100 string, I'm happy I succeed, but next step i wanna know how to count each number of letters and the frequency it shows.
Here is the code:
#include <stdlib.h> #include <string.h> #include <time.h> #include <iostream> // using namespace std; int main() { const char *c = "abcdefghijklmnopqrstuvwxyz";
I'm doing error checks in C and I'd like to know how to restrict the input of a string to 2 letters and if it is exceeded, i'd like to loop and ask for the code to be re-entered.
Code:
for (i = 0; i < code7; i++) { printf("Enter number of items: "); scanf("%d", &item_qty[i]);
My problem says: Have the user enter a number from 1-80 then print out a string of random letters(a to z lowercase) of that length.
I have been able to enter the number and output the correct amount of letters but i can't figure out how to get them to be in a random order and not in alphabetical. Here is what I have so far.
#include <iostream> using namespace std; int main() { int i=0; int num; cout<<"How many letters do yu want in your random string?";
I'm having trouble trying to turn a word into letters. I've seen other posts but they deal with a sentence and it only outputs the words only. What I want to know is how do they take a word (Ex: "word") and break it into individual letters, where I want to store them in a vector of string?
If it's not too much trouble, I would prefer without using pointers or "std:: " marks, since I am trying to avoid pointers and I'm using "using namespace std" all the time.
Ex:
In the example "word", it should output into:
"w" "o" "r" "d"
and I will push them back into a vector of string where each vector element contains a letter.
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.