i couldn't count the 2d string. my string is list[100][100] = {"Batuhan","Jeyhun","Tashtanbek"} this is a food line in cafeteria. i want to add a person to this list but i couldnt do it because i dont know the length of my list. it will be more than 3 after i add a person but what if i would add another person after that ? In that case i couldnt be able to tell how long is my line.And after i add people to my list i want to print that list. here is where i came so far:
case 1:
printf("Enter the name of the person to be added
");
printf(">>");
k=0;
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
I have the codes for such a problem where, to create a program that counts how many times the second string appears on the first string. Yes it counts if you put 1 letter only, but if you put 2, it is an error. As an example. If the first string is Harry Partear, and the second string is ar, it must count as 3. Here's the code:
Code:
#include <iostream> #include <conio.h> using namespace std; int main ()
I have a upcoming C++ exam. I would like to write a program to convert INDIVIDUAL digits into words.
E.g 678 = six seven eight[/size][/b]
I have the following code:
//Program to print individual digits in words #include<iostream> using namespace std; int main() { int num; cout << "Enter a number between 0 and 9999: ";
Be given a string of chars, where each single char belongs to the following alphabet: a..zA..Z0..9 (So, in the string there are only lowercases, uppercases and digits. No blank, no comma, ...).
For every char of the given alphabet, count how many times in the string
1----- the char is preceded by its predecessor in the alphabet (consider that the predecessor of 'a' is '9') 2----- the char is followed by its successor in the alphabet (consider that the successor of '9' is 'a') 3----- the char belong to a sequence of identical chars whose length is at least three (i.e.: in the string cc74uyrpfccc348fhsjcccc3848djccccc484jd for three times the character 'c' satisfies this condition) 4----- what is the longest substring of characters strictly rising (the following is greater (>) of the previous) 5----- what is the longest substring of successive characters (i.e.: fhkjshdfruytyzABCDEfglsj => 7) 6----- the frequencies of any char (if in the string the character 'g' occurs 12 times, its frequency is 12)
The thing is, when I don't create a prototype of count and straightaway define it before void main() my program runs, but it gives error in this program that "extra parameter in call to count()" But what to do then?
I'm trying to create a program that counts the amount of alphabetical characters, numbers, blanks and total amount of characters in a string a user gets to enter. The user also quits the program manually by pressing CTRL + D (in linux terminal).
These are the results I get from the code so far by typing in "hello cplusplus 123 c++" CTRL + D.
The string had: Alphabetical characters...: 0 Numbers...................: 0 Blanks....................: 3 Total amount of characters: 20
So I can't seem to find a way to count the amount of alphabetical characters and numeric characters.
Here's my code:
#include <iostream> #include <string> #include <iomanip> #include <cctype> #include <sstream> using namespace std; int main() { string tecken;
[Code] ....
The reason why I declared cctype is that I think I should use the isalpha, isdigit and isblank functions but how I am supposed to do that.
I am using a for loop to count down from 10 to 0 it's working to count down from 10 to 1 but when the program cames to the 0 then the program freezes by any reason.
Code: #include <iostream> using namespace std; int main() { int number[2]; cout << "Enter number: "; cin >> number[0]; if (number[0] == 1)
I'm just trying to find out if the way I've setup my code currently allows me to count the letters as they occur? I don't yet see how to do it but I need clarification. Ideally the function letterCounter would do the counting but atm I'm just trying to figuring it out in the display function.
I have the following code to print a string to the LCD using my PIC32 Starter Kit; I have made this code work with success. I cannot, however, make the LCD print numbers.
#include<p32xxxx.h> #define LCD_PRT PORTE //LCD DATA PORT //#define LCD_DDR DDRE//LCD DDR //#define LCD_PIN PINE//LCD PIN
[Code].....
I want to change the original code as little as possible, don't worry about my header files - they are fine.
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5 The 5 repeated = 1 times The common number is = 6 The 6 repeated = 1 times
The common number is = 4 The 4 repeated = 1 times
The common number is = 5 The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5 The common number is = 6 The common number is = 4 The common number is = 5 The common number is = 5 The common number is = 8 The common number is = 9 The common number is = 6 The common number is = 6
I am new to c++. I am writing a program that reads in a text file and gives a count of how many times each letter appeared in the file. I got it to read the text file and do the letter count. B
X = 102 Y = 126 Z = 165 etc...
THAT IS WORNG
The sample output should be E = 165 T = 126 A = 102 O = 93 etc...
I got it to sort from lowest to highest for the frequency, but cant seem to get the appropriate letter assigned to it.
iam trying to count the same numbers in an array just once like
38 38 40 38 40 37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream> using namespace std; int main(){
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
