C/C++ :: Print To LCD - Count Up To 100 Then Down To 1
Feb 12, 2014
I have the following code to print a string to the LCD using my PIC32 Starter Kit; I have made this code work with success. I cannot, however, make the LCD print numbers.
#include<p32xxxx.h>
#define LCD_PRT PORTE //LCD DATA PORT
//#define LCD_DDR DDRE//LCD DDR
//#define LCD_PIN PINE//LCD PIN
[Code].....
I want to change the original code as little as possible, don't worry about my header files - they are fine.
4.1 Write a program that will count from 1 to 12 and print the count, and its square, for each count.
4.2 Write a program that counts from 1 to 12 and prints the count and its inversion to 5 decimal places for each count. This will require a floating point number.
4.3 Write a program that will count from 1 to 100 and print only those values between 32 and 39, one to a line. Use the incrementing operator for this program.
Write a count controlled loop than can print "i" char. The user is supposed to input a integer and that integer is how many asterisks there is on the blade, in this case it is 5.
* * ** ** **--------------- ******* ** ** ** * ** * -10 Rows high ** -blade always connects on second row of handle ** ** ** **------------------
I have to write a c++ program to read html code and do bunch of stuff. One thing that i have to do is to count the no of attributes and sort them in descenting out and print out only first 10 frequently used attributes. I counted them using maps and sorted them using multimaps but now dnt knw how to print only 10 elements
for(std::map<string, int>::iterator it = Element.begin(); it != Element.end(); ++it) Elements.insert(pair<int, string>(it->second, it->first)); for(std::multimap<int, string>::reverse_iterator it = Elements.rbegin(); it != Elements.rend(); ++it) { cout << "Element: " << it->second << " : " << it->first << endl; }
This is how i did it . How to display only 10 elements and not all the elements.
write a c++ program that reads an unknown number of integer values and then print count, sum and average of odd values, even values, positive values, negative values!!
I am making a program where the user enters numbers into an array and then a number,x. The array is sorted, then x is inserted into the appropriate place. I wrote my selection sort
Code:
void Sort(int ary[], int size) { int temp; int smallest; int current; int move; }
[code]....
put it wont print the numbers sorted when I use my print function, just the unsorted numbers.
I am using a for loop to count down from 10 to 0 it's working to count down from 10 to 1 but when the program cames to the 0 then the program freezes by any reason.
Code: #include <iostream> using namespace std; int main() { int number[2]; cout << "Enter number: "; cin >> number[0]; if (number[0] == 1)
I'm just trying to find out if the way I've setup my code currently allows me to count the letters as they occur? I don't yet see how to do it but I need clarification. Ideally the function letterCounter would do the counting but atm I'm just trying to figuring it out in the display function.
i couldn't count the 2d string. my string is list[100][100] = {"Batuhan","Jeyhun","Tashtanbek"} this is a food line in cafeteria. i want to add a person to this list but i couldnt do it because i dont know the length of my list. it will be more than 3 after i add a person but what if i would add another person after that ? In that case i couldnt be able to tell how long is my line.And after i add people to my list i want to print that list. here is where i came so far:
case 1: printf("Enter the name of the person to be added "); printf(">>"); k=0;
I want to calculate how many times the common number is repeated . So I have used freq[num] in that function. But I am getting the output like this-
Code:
The common number is = 5 The 5 repeated = 1 times The common number is = 6 The 6 repeated = 1 times
The common number is = 4 The 4 repeated = 1 times
The common number is = 5 The 5 repeated = 1 times
[code]....
So the freq[num] is only returning 1 instead of counting the total number of repeating which is wrong!! I would like to have somthing like this in my output -
Code:
The common number is = 5 The common number is = 6 The common number is = 4 The common number is = 5 The common number is = 5 The common number is = 8 The common number is = 9 The common number is = 6 The common number is = 6
I am new to c++. I am writing a program that reads in a text file and gives a count of how many times each letter appeared in the file. I got it to read the text file and do the letter count. B
X = 102 Y = 126 Z = 165 etc...
THAT IS WORNG
The sample output should be E = 165 T = 126 A = 102 O = 93 etc...
I got it to sort from lowest to highest for the frequency, but cant seem to get the appropriate letter assigned to it.
iam trying to count the same numbers in an array just once like
38 38 40 38 40 37
the output should be 2 since 38 is repeated and 40 too but for my code the output is 3 thats an example of how it should be in a nutshell i want same number to be counted just once in the whole array
and here's my code :
#include <iostream> using namespace std; int main(){
I have loaded and 1d array from a .dat file, calculated the average of all the numbers. Now I need to count every number in the array that is below the average and cout that number. This is the method in the class I have so far:
I am trying to keep a count on a variable name stored within a structure as char*'s. They are of the same field and I do not know how many there will be so I would like to keep a standard name and append the count.
So say I have a variable name such as "desk", but as I have many of these said desks so I would like to call them "desk1", "desk2", "desk3" and so forth. Any recommendations on how I could do this?
Also since this is somewhat relevant is there an easy way to convert from an integer to a string, something that would work like atoi() in reverse? I wouldn't mind writing a method to do so myself but haven't a clue as to how.
I need a way to count lines in a .dat file using fscanf. I must use a regex to check that the characters in the file are alphanumeric. In essence I need to count the ' ' character. I know fscanf ignores this character. I need to exit if it detects anything other than alphanumeric with the digit that is "problem" along with the line number. My .dat file is:
Code: howard jim dave joe ( Maggie My fileCheck.c is: Code: #include "main.h" int fileCheck(FILE *fp) { int ret_val; int line_count = 0; char file[BUFF];
[Code]...
The output I am getting is:
Code: file opened Digit: ( is not an alphanumeric character on line: 5 Program will exit! File closed As you can see, the character "(" is not on the 5th line but the 3rd. It is the 5th "string."
So I already gave this a go and will post my code below. The question is about the last loop before the program cout's. i thought the count would keep track of the repeated numbers so i could display them but it does not. I italicized the loop i am referring to. or at least i tried to xD
#include <iostream> #include <iomanip> using namespace std; int main() { int inputs[30]; int numofloops; int maxvalue = inputs[0];