is there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c
", m, ' ',*);
}
This is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
is there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c
", m, ' ',*);
}
this is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
This is supposed to output t=m and then m is plugged into a function say for -3, plugging it into function f gives 23, well i want 22 blank spaces and then a asterik and go to next line. that is why i put -1 after %'f(m)-1's i
The asterisk appear right next to the t value here but they are way to the right of it when i made this post.
i am trying to write a program to print a statement without spaces in it.For example, if the statement is "Hello, i am Solidsnake", then it should print it as "Hello,iamsolidsnake".
View 4 Replies View RelatedI am having some trouble tokenizing some strings in C. I am trying to take in a string dynamically and spit print it to the console tokenized using the spaces as delimiters. I have tried using frets() and scant() as well as playing around with pointer values to no avail.
#include <stdio.h>
#include <unistd.h>
#include<string.h>
#include <stdlib.h>
#define MAX_LINE 80
//function prototypes
void printArgs(int argc, char* args[]);
[Code] .....
I wanted to take the averages of the whole week and output a print statement. I've tired few ways this like assigning "temp" a pointer, or in each if statement assigning temp to a new variable like a, b , c etc. Then adding them all up at the end and dividing by 7. My issue is I am unclear how to store the number typed for each if statement while the program is running, then have it compute the simple equation. The code in question is below:
Code:
#include <stdio.h>
int main(int argc, const char * argv[]) {
int i, j = 0, temp = 0;
for (i=1; i<=7; i++) {
j++;
[Code] ....
I have an exercise that asks me to print numbers at random from the following set (using only a single statement):
2, 4, 6, 8, 10
Here's my statement:
Code:
cout << (2 + rand() % 9) << " ";
which prints numbers at random between 2 and 10, now I can use the modulus operator in an if...else statement to print only even numbers but the exercise specifically requires using only one statement, can that be done using the conditional operator? and if not then how?
Community Hospital needs a program to compute and print a billing statement for each patient. Charges for each day are as follows:
a. room charges: private (P) room = $125.00; semi-private (S) room = $95.00; or ward (W) = $75.00
b. telephone charge = $1.75
c. television charge = $3.50
Write a program to get data from the keyboard, compute the patient’s bill, and print an appropriate statement. Typical input (nut yours do not have to be identical to this) is the following:
How many days was the room occupied? 5
What type of room? P
Telephone used during the stay? N
Television used during the stay? Y
Keep in mind that the user needs to know that the input can be any integer number of days for the length of stay, either (P, S, or W) for the room type, and either (Y or N) for both telephone and television options.
A statement (which yours MUST be identical to) for the data given follows:
Community Hospital Patient Billing Statement
Number of days in hospital: 5
Type of room: Private
Room charge:$ 625.00
Telephone charge:$ 0.00
Television charge:$ 17.50
TOTAL DUE = $642.50
I am working on a small simple program my program fills up a air plane with customers there is 2 levels 1 and 2 and it will put that person in the spot depending on being picked.
So far i made a boolean airplane with 10 spots I can enter 1 person into the airplane with no problem but then after he sits down i get a infinite loop? I assume i maybe have to use the continue statement I feel like there is something simple that im missing i want to add more people. here is what i have
class Program
{
static void Main(string[] args)
{ bool[] planeSeats = {false, false, false, false, false, false, false, false, false, false };
[Code]......
Write a for loop statement to print the numbers from 1 to 10 in reverse order separated by star :
10*9*8*7*6*5*4*3*2*1
i try to do it but it show me like this :
10*9*8*7*6*5*4*3*2*1*
how do i write to show me like the first one ?
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");
I have a problem who must print the sentences who have lenght more than 20 characters. I dont know why, but it prints just the first words. Look what i made.
#include<stdio.h>
#include<conio.h>
int main()
[Code]....
For instance :
Give the number of sentences : 3
First sentence : I like the website bytes.com
Second sentence : I like more the website bytes.com
Third sentence : bytes.com
After I compile the program it should print the first two sentences.
I am making a program where the user enters numbers into an array and then a number,x. The array is sorted, then x is inserted into the appropriate place. I wrote my selection sort
Code:
void Sort(int ary[], int size)
{
int temp;
int smallest;
int current;
int move;
}
[code]....
put it wont print the numbers sorted when I use my print function, just the unsorted numbers.
How to reserved int number and print as float number ?
View 1 Replies View RelatedHow can i print out the SECOND MIN number and MAX number without using array?
cout << "Please input a positive integer: ";
cin >> input;
min = input, max = input, secondmin = input;
do {
cout << "Please input a positive integer: ";
cin >> input;
[Code] .....
#include<stdio.h>
#define TRUE 1
int formOddInt(int n);
[Code]....
i just started learning programming and i just wanna know how come when i try to print the last digit of a number the output always become 6?
View 4 Replies View Relatedi want to print Largest number from any 5 rows.Th number printed should be any one of the largest in the five rows of 2d arrays.I have created code for largest number in each row but how to pick and print them randomly?.
Code:
#include<conio.h>
main( )
{
int a,b,c,d,e,x;
int arr[] = {a,b,c,d,e};
int Matrix[5][5] ={ /*Initializing array*/
2,4,3,5,9,
6,8,2,2,10,
[Code]...
Print the inverse number. Ex: 2178*4=8712
Write down a program which can satisfy the prerequisite and print out the screen.
The answer is:
Code:
void inverse2 ()
{
int i,j;
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
if (i*j==inverse (i))
printf("%5d%2d",i,j);
}
I can't understand the double for loop.
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
And The meaning for
i*j==inverse (i)
when i compile and run it it gives me the number 0 and not the proper number stored in array.
Code:
#include <stdio.h>
int main()
{
int myArray[11] = { 5, 5, 5, 5, 5, 5, 5, 5, 5, 5 };
}
[code]....
Basically i want to input a number for example 123456 and get back how many 7's are in the input number and also to print out that same number with stars in between like this *1*2*3*4*5*6*. Here is what i have so far:
#include <iostream>
using namespace std;
int countSeven(int x){
if(x == 7)return 1;
int c = 0;
while(x/10 > 9)c++;
return countSeven(x/10)+1;
when i compile it does not do what i tell it it just tells me there are 0 7's in the input number no matter how many there really are...
My objective is to check to see if a number is odd or even and print it to the screen just to make sure its working correctly.
The data file contains:
138
402 2 485
9
43
98 805
58
421
948 7 97
48
67
35
42
948
579 39 12
700 20 500 210
98
I can get the numbers to print fine using:
fstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
while(infile1.get(listNum))
cout << listNum;
}
However, when I check for odd or even numbers it will check each and every number.
printed like this (partial list):
1 is odd 3 is odd 8 is even
9 is odd
But it should print:
138 is even
9 is odd
I tried using getline, but it keeps giving me the errors:
invalid conversion from 'void*' to 'char**'
invalid conversion from 'char' to 'size_t*'
too few arguments to function 'ssize_t getline(char**, size_t*, FILE*)'
Here is the getline code, what am I doing wrong? I have tried switching things around, adding things. Just nothing works.
ifstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
getline(infile1, listNum);
cout << listNum;
}
The program works, but the rational number doesn't print as reduced. I guess i have to call the reduction function, but i'm not sure where
the output that i get is:
2/6 + 7/8 = 58/48
58/48 = 1.20833
2/6 - 7/8 = -26/48
-26/48 = -0.541667
2/6 x 7/8 = 14/48
14/48 = 0.291667
2/6 / 7/8 = 16/42
16/42 = 0.380952
the output that i suppose to get is:
1/3 + 7/8 = 29/24
29/24 = 1.20833
1/3 - 7/8 = -13/24
-13/24 = -0.541667
1/3 x 7/8 = 7/24
7/24 = 0.291667
1/3 / 7/8 = 8/21
8/21 = 0.380952
here is my header file
//Prevent multiple inclusions of header
#ifndef RATIONAL_H
#define RATIONAL_H
//Rational class definition
class Rational {
[Code] .....
Write a program to print out the binary value of a 16 bit number.
Create integers i, count, and mask.
Set 'i' to a hex value of 0x1b53.
Set mask to a value of 0x8000. Why?
print a line to show the hex value of i and then the leader for the binary value like this: Hex value = 1b53 Binary=
Use a for loop to loop 16 times and print 16 digits, using count as the loop counter
To test for each digit value, bitwise and 'i' with 'mask'
when the result for the bitwise and is true, print the number '1'
when the result for the bitwise and is false, print the number '0'
then shift mask one place to the right
print a new line and then quit
Use prtscrn and make a hard copy of the code with the console output.
Extra: use the modulus of count and print a space after every 4th digit to make the binary easier to read
The output should look like this: Hex value = 1b53, Binary= 0001 1011 0101 0011
so far this is what i have
#include <stdio.h>
#include <stdlib.h>
int main() {
int i, count, mask;
// 1B53 0001 1011 0101 0011
// 8000 1000 0000 0000 0000
i = 0x1b53;
[Code] ....
it is telling me that there is an "else" without previous "if", also is the program that I wrote correct?
I created a richtextbox to input the text that I want to print, the command for printing which is the button and instead of printdialog box((PrintDialog1.ShowDialog() == System.Windows.Forms.DialogResult.OK)) to be display, I created combobox which will display the available printers and then print.
Like this code bellow .
To get the available printers:
foreach (String printer in PrinterSettings.InstalledPrinters)
{
cbox.Items.Add(printer.ToString());
}
And the button for printing :
PrintDocument1.PrinterSettings.PrinterName = cbox.SelectedItem.ToString();
PrintDocument1.Print();
Now what I want to do is I will add some textbox to input the page number to be printed . For example the current pages in the richtextbox are 12pages when I'm going to run the program I will input in the textbox the page/s that I want like (3-7pages). How could it be ?
C programming, make it use a function call to print the smallest number? this is a program which prints out the smallest of three numbers within the main function that I was asked to write.Now the other question i am asked,5. Re-write the program, uses a function call to print the smallest number?
Code:
# include <stdio.h>
main()
{
int a,b,c;
int temp, min;
a = 100;
b = 23;
c = 5;
}
[code]....
I've written a program which takes a character string and then prints each character vertically so that for instance the string 123 can be written as
1
2
3
no what i need is for all the numbers from zero to the inputted number to print the numbers digits vertically but each number to be printed horizontally so that for instance an input of 11 prints
1 2 3 4 5 6 7 8 9 1 1
0 1
i've made it so that i can print all numbers up to the inputted number vertically; however, i am stuck with a method for making each number print horizontally as described above.
