C++ :: Print Statement Without Spaces
Apr 13, 2013i am trying to write a program to print a statement without spaces in it.For example, if the statement is "Hello, i am Solidsnake", then it should print it as "Hello,iamsolidsnake".
View 4 Repliesi am trying to write a program to print a statement without spaces in it.For example, if the statement is "Hello, i am Solidsnake", then it should print it as "Hello,iamsolidsnake".
View 4 Repliesis there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c", m, ' ',*);
}
This is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
is there a to use printf to print certain number of blank spaces, where the number is derived from the output of a function?
for(m=low; m<=high;m++)
{
printf("t=%2d %'f(m)-1's %3c
", m, ' ',*);
}
this is suppose to output
t=-3 *
t=-2 *
t=-1
.
.
.
This is supposed to output t=m and then m is plugged into a function say for -3, plugging it into function f gives 23, well i want 22 blank spaces and then a asterik and go to next line. that is why i put -1 after %'f(m)-1's i
The asterisk appear right next to the t value here but they are way to the right of it when i made this post.
I am having some trouble tokenizing some strings in C. I am trying to take in a string dynamically and spit print it to the console tokenized using the spaces as delimiters. I have tried using frets() and scant() as well as playing around with pointer values to no avail.
#include <stdio.h>
#include <unistd.h>
#include<string.h>
#include <stdlib.h>
#define MAX_LINE 80
//function prototypes
void printArgs(int argc, char* args[]);
[Code] .....
I wanted to take the averages of the whole week and output a print statement. I've tired few ways this like assigning "temp" a pointer, or in each if statement assigning temp to a new variable like a, b , c etc. Then adding them all up at the end and dividing by 7. My issue is I am unclear how to store the number typed for each if statement while the program is running, then have it compute the simple equation. The code in question is below:
Code:
#include <stdio.h>
int main(int argc, const char * argv[]) {
int i, j = 0, temp = 0;
for (i=1; i<=7; i++) {
j++;
[Code] ....
I have an exercise that asks me to print numbers at random from the following set (using only a single statement):
2, 4, 6, 8, 10
Here's my statement:
Code:
cout << (2 + rand() % 9) << " ";
which prints numbers at random between 2 and 10, now I can use the modulus operator in an if...else statement to print only even numbers but the exercise specifically requires using only one statement, can that be done using the conditional operator? and if not then how?
Community Hospital needs a program to compute and print a billing statement for each patient. Charges for each day are as follows:
a. room charges: private (P) room = $125.00; semi-private (S) room = $95.00; or ward (W) = $75.00
b. telephone charge = $1.75
c. television charge = $3.50
Write a program to get data from the keyboard, compute the patient’s bill, and print an appropriate statement. Typical input (nut yours do not have to be identical to this) is the following:
How many days was the room occupied? 5
What type of room? P
Telephone used during the stay? N
Television used during the stay? Y
Keep in mind that the user needs to know that the input can be any integer number of days for the length of stay, either (P, S, or W) for the room type, and either (Y or N) for both telephone and television options.
A statement (which yours MUST be identical to) for the data given follows:
Community Hospital Patient Billing Statement
Number of days in hospital: 5
Type of room: Private
Room charge:$ 625.00
Telephone charge:$ 0.00
Television charge:$ 17.50
TOTAL DUE = $642.50
I am working on a small simple program my program fills up a air plane with customers there is 2 levels 1 and 2 and it will put that person in the spot depending on being picked.
So far i made a boolean airplane with 10 spots I can enter 1 person into the airplane with no problem but then after he sits down i get a infinite loop? I assume i maybe have to use the continue statement I feel like there is something simple that im missing i want to add more people. here is what i have
class Program
{
static void Main(string[] args)
{ bool[] planeSeats = {false, false, false, false, false, false, false, false, false, false };
[Code]......
Write a for loop statement to print the numbers from 1 to 10 in reverse order separated by star :
10*9*8*7*6*5*4*3*2*1
i try to do it but it show me like this :
10*9*8*7*6*5*4*3*2*1*
how do i write to show me like the first one ?
I have a problem who must print the sentences who have lenght more than 20 characters. I dont know why, but it prints just the first words. Look what i made.
#include<stdio.h>
#include<conio.h>
int main()
[Code]....
For instance :
Give the number of sentences : 3
First sentence : I like the website bytes.com
Second sentence : I like more the website bytes.com
Third sentence : bytes.com
After I compile the program it should print the first two sentences.
How to make if else code below into SWITCH STATEMENT?
cout << "Enter the temperature: ";
cin >> temp;
cout << "Enter the pressure: ";
cin >> pressure;
cout <<endl;
[Code]....
How can I extract the number out of the string:
string my_sting = "item code = 9";
I want to get the '9' out of the string and store it in a separate int variable. I tried using sstream library and was having trouble.
I am practicing with C++ since I done most of C already and I have a problem with reading spaces from a .txt file.
I created a little program that creates a wannabe Cube in wannabe 3D xd, well to appear as 3D like:
Code:
cout << " O------O" << endl;
cout << " / /|" << endl;
cout << " / / |" << endl;
cout << " / / |" << endl;
[Code] .....
The actual code is a bit longer since it offers you to input the size and then it draws the pic. Now that wasn't so hard and I've done that but now I wanted to implement the "MessageBox" func for output.
I managed to write the cube in file cube.txt but when I'm reading from it 1 char at a time since I need to output as char array it avoids all spaces and new lines and just puts all symbols in the same row.
I didn't have that issue with C and I've found on stackoverlow a solution using strings & getline but I need it to be in "char" form.
How to actually read spaces and newlines? This is my current code for reading from file:
Code:
ifstream di("kocka.txt", ios_base::in);
char c[5000];
int br=0;
while( di >> c[br])
{
br++;
}
MessageBox(NULL, c, "Kocka", MB_ICONHAND);
di.close(); P.S kocka = cube (in croatian )
I'm unable to print out or return the inputted string modified.
Code:
//ch11_9.c
//remove_spaces(char* given_string)
#include <stdio.h>
#include <ctype.h>
#include <string.h>
#include <stdlib.h>
char* remove_spaces(char *given_string){
[Code]...
Basically, the task is to replace tabs with spaces, ensuring that the number of spaces is appropriate to get you to the next tab stop (i.e. if you were only 4 spaces away from a tab stop, don't replace the tab with 8 spaces).i've seen have included character arrays, and many have included multiple functions. I realize the text says "these exercises suggest programs of somewhat greater complexity than the ones earlie in this chapter," but it seemed like a very straightfortward task.Have i oversimplified or something?
Code:
#include <stdio.h>
#define TAB_STOP 8
int main()
{
int c, i;
}
[code]....
i want to replace tabs with spaces but i didn't get it. I also tried to count all the chars that i read from a file but that does also not work.
Here's what i have so far (fP is just a file)
Code:
void ReplaceTab(FILE *fP) {
int char_ = 0;
if (fP != NULL)
[Code]....
Is there a way in which i can add sentences with spaces in c++ ... Tell me both ways with string and without it ...
View 2 Replies View RelatedI want to store the address of a customer (with spaces) in a char variable (say cadd). First I tried to use "cin", as we know it reads until it sees any whitespace. So it reads only first word before a white space. So, I used "getline()" function. But when I used it, It didn't wait for the I/P (it skipped it).
char cadd[20];
std::cout<<"Enter Customer Address:
";
std::cin>>cadd;
std::cout<<"Enter Customer Address:
";
std::cin.getline(cadd,20);
How to solve this (for cycle)?
View 12 Replies View RelatedI was wondering about the function strcmp(), does the function compare word with spaces? eg: If I have two same words "Harith Javed"; will it match both words??
View 8 Replies View RelatedHow I can manipulate certain strings. This program here is supposed to randomly scramble any word/sentence input. However, I notice that even the empty spaces get moved; is there any way to stop that from happening? I would want the empty spaces to stay in their input positions.
#include <iostream>
#include <string.h>
#include <ctime>
#include <cstdlib>
#include <fstream>
#include <string>
using namespace std;
[Code] ....
This is about reading a "txt file" and storing the contents in a variable. But i've got problems with it because normally, it is space delimited, that is, values separated by spaces are considered different values. How am I going to make C++ read the whole line including spaces?
View 14 Replies View Relatedi wonder how does any os address file having spaces in their names.Even cmd.exe in windows can't access such file but windows explorer can. How is it so?
View 4 Replies View Relatedas i am doing an encryption program on a playfair cipher. I am now stuck on a problem on decryption.If my string is helloworld (without a space), it will decrypt normally.However , if my string has a space in between it. Let`s say Hello World, it will not decrypt normally.How do i take into account the space that is in between hello & world?
example: hello world
So I want to do the following, I want to input 150 1 digit integers, from 0-9 and I don't want to put spaces between them while inputing, like if I input a 150 digit integer, the compiler should take it as 150 1 digit integers. I'm not sure how to accomplish that.
int a[150];
for(int i=0;i<150;i++)
cin>>a[i];
If I try to do it with above code, the compiler needs a space to know when the value of i is incremented. But I want to avoid spaces for my task.
This is my program and i dont know what is the better strategy to display the output perfectly align with the title, when i input a long variable or short the variable move and it does not align with its title. what can i do.
#include <iostream>
#include <string>
#include <string.h>
#include <cstdlib>
#include <cstring>
#include <iomanip>
using namespace std;
struct book {
[Code] ....