C/C++ :: Print Dynamic String To Console Tokenized Using Spaces As Delimiters
Feb 26, 2014
I am having some trouble tokenizing some strings in C. I am trying to take in a string dynamically and spit print it to the console tokenized using the spaces as delimiters. I have tried using frets() and scant() as well as playing around with pointer values to no avail.
This is part of a bigger program im working on that deals with data structures, but I'm trying to figure out a way to tokenize a long file of purchases that is being read to my program. I rewrote the program to pinpoint my problem. I need to get the name, cost, item and quantity from this string. I figured out how to look for the cost, but what about the name and item(shirts)? How can I do this all in one loop because there are multiple strings and i'm gonna eventually send all the info to a data structure for each person(name)? I'm only asking about the tokenizing part, but this code works for the cost.
Code:
int main(void) { char myString[] = "Angela bought 9 shirts for $6 each." ; char * del = " " ; char * token ;
i am trying to write a program to print a statement without spaces in it.For example, if the statement is "Hello, i am Solidsnake", then it should print it as "Hello,iamsolidsnake".
General Purpose: Delete all "white spaces" in text file, until the read-in char is _not_ a whitespace (mark as start of text file).
Problem: Cannot seem to shift char's over properly. (I think my problem is the inner loop - however other code may lead to this problem - I do not know)
Code:
#include <fstream> #include <iostream> using namespace std;
bool trimWhiteSpace(fstream &file, char * charMemoryBlock) { if (!file.is_open()) {
This is supposed to output t=m and then m is plugged into a function say for -3, plugging it into function f gives 23, well i want 22 blank spaces and then a asterik and go to next line. that is why i put -1 after %'f(m)-1's i
The asterisk appear right next to the t value here but they are way to the right of it when i made this post.
as i am doing an encryption program on a playfair cipher. I am now stuck on a problem on decryption.If my string is helloworld (without a space), it will decrypt normally.However , if my string has a space in between it. Let`s say Hello World, it will not decrypt normally.How do i take into account the space that is in between hello & world?
So i have this program that's supposed to count all the characters including the spaces without using strlen but it only counts the number of the first word's characters and it does not include the rest of the words after the first space. how do i include spaces in the count?
Suppose I have a txt file that I want the contents printed to the console in such a way that every five words are colored blue and the following five are red. How do I accomplish such a task? I am currently only able to print the contents of the file in regular color using ifstream.
I have been trying to read a comma separated .txt file into an array and print it to console in C++. The txt file consists of two columns of double type data. For some reason the program runs, but gives blank output in the console. I want to know if I am doing something wrong. So far this is what I have:
#include <iostream> #include <fstream> #include <string> using namespace std; int main() { int i=0; double x[10]; double y[10]; string line;
I'm new to programming and i'm trying to do a certain task. I want to use a for loop to read certain data from a txt file and print them to a console. I'm trying to read student names and their grades.
Something like 3 // 3 represents the number of students. George 97 Sarah 70 Maya 88
I want to separate this binary string every 4 characters..I am trying to get a better understanding of how variables are stored in memory and I am looking at their binary address for a pattern..I see a pattern for the last 4 bits
#include <iostream> #include <bitset> int main() { using namespace std; int x[100];
I have a problem who must print the sentences who have lenght more than 20 characters. I dont know why, but it prints just the first words. Look what i made.
#include<stdio.h> #include<conio.h> int main()
[Code]....
For instance :
Give the number of sentences : 3
First sentence : I like the website bytes.com Second sentence : I like more the website bytes.com Third sentence : bytes.com
After I compile the program it should print the first two sentences.
In this code, i declared a string constant and trying to print the length of string. I know that if i write char a1[7] or char a1[] than it runs and give aggregate output, but in this case it is giving double length of string.
So, this is the code i have problem with, as far as i can see, function form actually does the same thing that printf does.It probably puts all of the arguments sent to the function together into one string.
I have a little problem with one of my functions. The function purpose is to get a number (n) and create an array (size n) with pointers to strings (each string length is 20 chars) and i don't know why but during the debugging i get a <bad ptr> message and this message :
CXX0030: Error: expression cannot be evaluated
This is my function:
Code: char** getlist(int n) { int i=0; char **arr; arr=(char**)malloc(sizeof(char)*n); if (arr==NULL)
The snippet below (or similar) compiles and runs OK but I am using Visual Studio C++ compiler. Are the lines where .nameFirst and .nameLast assigned kosher in ANSI C?
Also I am concerned about the memory allocation for these string constants. Does the runtime system put them on the heap? It doesn't seem that they are really constants since they are not defined before runtime.
I coded a program that takes some strings and lexicographically orders the strings and its substrings. I have used dynamic memory allocation technique and its working fine for all strings without consecutive same alphabets.I use a list in which a string is placed in its exact position by moving the others right.
