C/C++ :: Print More Strings (the Strings May Contain Spaces)?
Feb 12, 2014
I have a problem who must print the sentences who have lenght more than 20 characters. I dont know why, but it prints just the first words. Look what i made.
#include<stdio.h>
#include<conio.h>
int main()
[Code]....
For instance :
Give the number of sentences : 3
First sentence : I like the website bytes.com
Second sentence : I like more the website bytes.com
Third sentence : bytes.com
After I compile the program it should print the first two sentences.
How I can manipulate certain strings. This program here is supposed to randomly scramble any word/sentence input. However, I notice that even the empty spaces get moved; is there any way to stop that from happening? I would want the empty spaces to stay in their input positions.
This is my program and i dont know what is the better strategy to display the output perfectly align with the title, when i input a long variable or short the variable move and it does not align with its title. what can i do.
#include <iostream> #include <string> #include <string.h> #include <cstdlib> #include <cstring> #include <iomanip> using namespace std; struct book {
I am making a program that takes the user's family names, their ages, and where they live. At the end I will be eventually averaging out their age and also printing the names of anyone who lives in Kansas.
I can't seem to get the Kansas part to work properly though.. When I execute the code, everything else works perfectly, but the Kansas part doesn't even print. Is there something different I need to do when strings are involved rather than integers/floats?
Code:
#include <stdio.h> int main () { /* variable definition: */
I am making a program that takes the user's family names, their ages, and where they live. At the end I will be eventually averaging out their age and also printing the names of anyone who lives in Kansas.
I can't seem to get the Kansas part to work properly though.. When I execute the code, everything else works perfectly, but the Kansas part doesn't even print. Is there something different I need to do when strings are involved rather than integers/floats?
#include <stdio.h> int main () { /* variable definition: */
This program is supposed to compare 2 strings and print out a 1 if the characters match and a 0 if they dont. It compiles but doesnt give me the correct output.
Code: #include <stdio.h> #include <string.h> void func(); int main () { func(); return 0;
I need access to the string using the int and the int using the string. Or just direct access to one or the other. . . It's just confusing that they're technically mapped to one another but I can't really access either of them.
I am programming a translator, and I have it so that it detects words with spaces both in front of and behind them, so I did "string.append(space);" where space equals " ". That added a space to the end, but I still need a space added to the front.
Just working up for the google coding contest to start soon and have been practising some of the test questions however i make correct algorithms but my output is rejected because of the fact that my strings are printed on a new line so i wish to know a method to print strings using a printf statement or any other function on the same line ...
i am trying to write a program to print a statement without spaces in it.For example, if the statement is "Hello, i am Solidsnake", then it should print it as "Hello,iamsolidsnake".
This is supposed to output t=m and then m is plugged into a function say for -3, plugging it into function f gives 23, well i want 22 blank spaces and then a asterik and go to next line. that is why i put -1 after %'f(m)-1's i
The asterisk appear right next to the t value here but they are way to the right of it when i made this post.
I am having some trouble tokenizing some strings in C. I am trying to take in a string dynamically and spit print it to the console tokenized using the spaces as delimiters. I have tried using frets() and scant() as well as playing around with pointer values to no avail.
1. I finished reading a beginning C book, and in the section about arrays, it says that one string can fit in a character array (char arrayname[]) but there cannot be a string array (string arrayname[]) that have multiple strings. Is
Code: string arrayname[4] = {"one", "two", "three"}; not valid?
My compiler lets me run it and it works, but why is the book saying it's wrong?
2. I know you can represent multiple strings in a character array by:
because [10][4] indicates that there should be four newarrays created with a max of 10 characters each, but is
Code: string multiplestrings[10][4] = ("i love you", "hello come to me", "i don't get C"; "hello world", "what are arrays"; "i am happy", "I am learning how to code"); valid?
Does multiplestrings[10][4] basically create 4 string arrays that have a maximum of 10 different strings within each string array?
How join two strings? basic reason is add given filename little text to end. I try do by hobby not school project program which converts files format x to format y.i dont say which formats becouse reading and writing is almost done. (only little amount code is needed).'
if (letter3==" "){ letter3==letter; PrintCharacterLineEnd();
This is a code. the string "letter3" contains the string " ". What I want to happen is when, letter3 contains the text " " I want to go to the function PrintCharacterLineEnd.
I need to make a small program with a function with this prototype: void f(char *a,char *b) that adds two numbers represented as strings without using conversion operators or other tricks.
I have a vector I want to add book titles to, then i want to print my updated vector. This is best I have come up with but the program fails at the getline line. why?
string book; cout << "Enter book to add: "<< endl; getline(cin, book); books.push_back(book); for(int i = 0; i < books.size(); ++i) { cout << i+1 << ". " << books[i] << endl; }
The problem with this code is that there are no errors showing, but when i compile the program, the if else statements do not carry out as they should do. Both if statements show the same answer, for example the second if statement. If I type Y or N then I get the same thing, 'You will now choose an event'. How do i get rid of this problem? Is char supposed to be used or string?
