C++ :: Print Hexadecimal Strings From Binary

Aug 19, 2013

How to search in C or C++ a hexadecimal patterns within a binary file.

For example:

String1:

Code: 0x44 0x65 0x07

Then, once found, extract those 3 bytes and the next 11 bytes (14 bytes in total).

Finally, from those 14 bytes, print without spaces "bytes 1 to 6", "bytes 6 to 12", and byte "13 to 14".

Then I would like to print last 2 bytes (13 to 14) joined in decimal format.

The output without any conversion would be:

Code:
446507c90688 888000800005 0015
4465072ec918 059173495269 002C
44650700cc01 01811bc90b00 00AB

But the output converting to decimal the last 2 bytes would be:

Code:
446507c90688 888000800005 21
4465072ec918 059173495269 44
44650700cc01 01811bc90b00 171

The sample file is attached, and looks like this:

Code:

06 00 00 80 00 00 00 80 09 3c c9 06 88 88 80 00
80 00 44 65 07 c9 06 88 88 80 00 80 00 05 00 15
37 06 01 00 00 01 00 65 00 00 00 02 00 00 02 00
18 00 00 00 03 00 00 03 00 17 00 00 00 04 00 00

[Code] .....

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i need to code a function that converts an array of 64 bits into a hexadecimal value, the one is tested gives me correct value except for the last hexadecimal letter.

Code:
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#include <stdio.h>
#include <conio.h>
#include <fstream>
#include <cstdlib>
#include <string>
typedef unsigned __int64 Ebyte;
#define length 64

[Code] .....

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Code:

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[Code]...

So this is my current code, is there anyway I can reduce the size and use a main function to ask for input and a call function to do all the conversion and return it? I am confused for the past few days trying to figure it out and finally ended up here. Anyway can I write it as a something like this

Code:

int main()
{
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}

int hex2binary(...)
{
//an array with dynamic memory, malloc? and convert it and return values
}

I don't really need the full code, just a simple instruction on how and where to start.

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long int i=0;
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[Code] ....

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[Code].....

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Code:
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Set mask to a value of 0x8000. Why?

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#include <stdlib.h>  
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[Code] .....

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Apr 21, 2014

Write the function itob(n,s,b) that converts the integer n into a base b character representation in the string s . In particular, itob(n,s,16) formats n as a hexadecimal integer in s .

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Code:

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[Code] ....

Why does digits array hold the full alphabet when the maximum digit for a hex number is f?

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