C :: Use Main Function To Ask For Input To Convert Hexadecimal To Binary
Mar 15, 2013
Code:
#include<stdio.h>#define MAX 1000
int main(){
char binaryNumber[MAX],hexaDecimal[MAX];
long int i=0;
printf("Enter any hexadecimal number: ");
scanf("%s",hexaDecimal);
[Code]...
So this is my current code, is there anyway I can reduce the size and use a main function to ask for input and a call function to do all the conversion and return it? I am confused for the past few days trying to figure it out and finally ended up here. Anyway can I write it as a something like this
Code:
int main()
{
//ask for user input hexadecimal into here and call a let's say hex2binary() function
}
int hex2binary(...)
{
//an array with dynamic memory, malloc? and convert it and return values
}
I don't really need the full code, just a simple instruction on how and where to start.
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void findBinary(int num) { int remainder = 0; while ( num > 0) { remainder = num % 2; cout << remainder; num = num / 2;
The program is supposed to convert a two digit hexadecimal number to its binary representation. My code runs without any problems but I do not know how to limit the user's input to two digits only. For example the person can input "1ABC" and the program will give the binary representation and I need it to only accept two digit only like for example "1A".
#include<stdio.h> #define MAX 1000 int main(){ char binaryNumber[MAX],hexaDecimal[MAX]; long int i=0; printf("Enter a two digit hexadecimal number: ");
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void myKeyboardFunction(unsigned char key, int x, int y) { switch ( key ) {
[Code].....
But when I try to call it, trying to copy my previous method,
glutKeyboardFunc(Player1.playerControls);
I get an error
error C3867: 'Player::playerControls': function call missing argument list; use '&Player::playerControls' to create a pointer to member
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Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
using namespace std; void Conversion (int n); int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
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I am new to programming and have written the code for the following program.
PROGRAM: Input 2 arrays => arrays 1 and 2 from the user each containing 5 elements. Sum is another array which is sum of elements of array 1 and array 2. Convert each of the elements of the sum array into binary. Count number of 1's in each binary element and output it to another array "arr".
Example: arr1 = {1,2,3,4,5} arr2 = {6,7,8,9,10} sum = {7,9,11,13,15} binary of 7 [111], 9[1001], 11[1011], 13[1101], 15[1111] No of 1's in 7 [3], 9 [2], 11 [3], 13 [3], 15 [4] arr array will be {3, 2, 3, 3, 4}
I am not getting the desired output. My code is:-
include <iostream> using namespace std; int main() { int array1[5];
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example:
input from user: ABC output to monitor: 41 42 43 a
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int example (int [], int, *int,*int,*int,*int); int main () { My code will be here example (int array[], int size, &a,&b,&c,&d); // Like this??? I try it didnt work
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
