I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){
char* binNum = decToBin(25);
int i = 0;
while(binNum != NULL){
[Code].....
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111
Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010
Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102
Number entered is not a binary number
#include <iostream>
using namespace std;
int main()
{
int num;
[code]....
I want to convert a decimal number to binary and store it in a string so that I can use that binary output for later computation. Here is what I did
Code:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void main()
[Code] ....
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
Here's the part of the codes where I tried to use boolean expression:
Code:
#include <iostream>
using namespace std;
int main() {
int num;
cout << "8-bit Binary Number=";
cin >> num;
[Code] .....
How can I get started with the body?
Here's the part of the codes where I tried to use boolean expression:
#include <iostream>
using namespace std;
int main()
[Code].....
May I know that how can I get started with the body?
What is the difference between the two functions below? I created the function in the top and my friend created the function in the bottom. I just want to know why the function with the while loop prints the binary numbers backwards. And the recursive function prints the binary numbers correctly.
void findBinary(int num) {
int remainder = 0;
while ( num > 0) {
remainder = num % 2;
cout << remainder;
num = num / 2;
[Code] .....
I had an exercise to convert from decimal to binary with base 2, it was simple simple i did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
[Code] .....
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ......
The code should convert binary numbers to decimal but it doesn't..
Code:
#include <stdio.h>
#include <math.h>
#include <string.h>
int main()
{
[Code] ....
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
Code:
#include <stdio.h>
#include <stdlib.h>
#define MAX_LEN 20
void translate_dec_bin(char s[]){
char st[sizeof(unsigned)*20] = { 0 };
}
[code]....
I am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3
10110101
11111111
10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
#include "stdio.h"
#include <stdarg.h>
#include <math.h>
// Main Function
int main(void){
int number;
printf(" Please enter a number from 1-10? ");
scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h>
#include <math.h>
char* ReverseString (char _result[]) {
int start, end, length = strlen(_result);
char swap;
for (start = 0, end = length-1; start < end; start++, end--)
[code]....
I have a code and am asked to modify it so that it will take as input as unsigned binary number up to 16 digits in length and convert it into its equivalent decimal number and output that decimal number.
All I know is that I use library function strlen() in <cstring> to calculate the length of the input string.
I also know I have to use something called pow(2,4);
//pow (); is found in cmath
I was told to use sum = sum >>16-l; (l is the length of />/>
#include <iostream>
using namespace std;
int main() {
[Code]....
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
#include <iostream>
#include <math.h>
using namespace std;
void main() {
double numOfDig, num, newNum;
[Code] ....
I tried to convert byte array with hex to equivalent decimal value as follows but it gives me unexpected results:
byte hex_arr[] = { 0x00, 0x01, 0xab, 0x90};
unsigned long i=0;
i = hex_arr[3] + (hex_arr[2] << 8) + (hex_arr[1] << 16) + (hex_arr[0] << 24);
the output is 4294945680
Correct output should be 109456
but when I try with byte hex_arr[]={0x00,0x00,0x0f,0xff};
it gives correct out put 4095
the correct output works until the hex values is {0x00,0x00,0x7f,0xff}
My size of binary file is 1920 KB and my struct size is 124 kb. now to find number of records in file I divided 1920/124 and it gives me 15.4.... do I add 1 to 15.4 and make it 16 or do i take it as 15?
View 9 Replies View Related#include <iostream>
#include <stdlib.h>
using namespace std;
[Code]....
Write a C++ program that adds three binary numbers of 8-bit each. Every number is stored into an array of 8 elements.
Example:
Array A
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array B
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
+
Array C
0 1 2 3 4 5 6 7
0 1 1 0 1 1 1 0
Store the result into an array D of 8 elements. Your program should show the decimal numbers for every binary number. Print screen of 6 answers. This means you should try your program six times with different numbers in every run and show the printed screen result.
This was an exercise from a book (convert a character string into a floating point value). It seems to work with both negative and positive decimal numbers.
It basically get each digit from the string multiplies by 10 to hold the place, and then adds the next to the result, if that makes sense.
Then determines where the decimal and null character are to figure out what to multiply by (1/1000 or whatever) to determine where the decimal should go. The variable names dealing with this part of the program aren't accurate names right now.
My question is, the output, is always putting 6 zero's. So if the argument is .95, Ideally the output should say .95 and not .950000, even though the value is still correct.
I know there the %.2f to determine the amount of decimals, but the amount of decimals in these instances would be varying depending on the argument sent to the function.
So, if 600.158 was sent as an argument, only 3 decimals would be displayed, as opposed to two from the previous example. Is there a way to do this?
Code:
// Function to convert a string to an integer
#include <stdio.h>
double strToFloat (const char string[])
[Code].....
I had an exercise that required me to convert a number to binary (base 2) which as simple enough.
Code:
#include <iostream>#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ....
I have this simple code here:
Code:
#include <iostream>
int multiply (double x, double y) {
double result = x*y;
return (result);
[Code] ....
I get the answer 5.94 (which is what I'm looking for). I can't work out why the first example is not outputting a decimal number. I have set the variables as a double so I just can't see why this is not working for me.
Code:
#include<stdio.h>#define MAX 1000
int main(){
char binaryNumber[MAX],hexaDecimal[MAX];
long int i=0;
printf("Enter any hexadecimal number: ");
scanf("%s",hexaDecimal);
[Code]...
So this is my current code, is there anyway I can reduce the size and use a main function to ask for input and a call function to do all the conversion and return it? I am confused for the past few days trying to figure it out and finally ended up here. Anyway can I write it as a something like this
Code:
int main()
{
//ask for user input hexadecimal into here and call a let's say hex2binary() function
}
int hex2binary(...)
{
//an array with dynamic memory, malloc? and convert it and return values
}
I don't really need the full code, just a simple instruction on how and where to start.
How would you go about converting a decimal value to hex and then do math? Every example of converting decimal to hex that I have seen creates an array and I wouldn't be able to do math if I did that. Something like this.
15 decimal to hex F
17 decimal to hex 11
F hex + 11 hex = 20
I have written this function.
void intToBase(unsigned int val,char *buff, unsigned int base) {
int digit = val%base;
if(val == 0)
return;
intToBase((val / base), buff + 1, base);
if(digit >= 0 && digit <= 9)
*buff = (digit + '0');
if(digit >= 10 && digit <= 15)
*buff = (digit + 'A' - 10);
}
This function is suppose to convert a decimal number (val) to any other base number and put it into a string (buff).
But the function puts the value in a opposite way, like if the answer is suppose to be "123" i get this "321".
Note: the function must be recursive and i can't use loops.
So I am trying to write a program that converts roman numerals into decimal numbers. I so far have come up with:
Code:
#include <stdio.h>
#include <ctype.h> // importing the tolowerfunction
//variables
int decimal, total;
char numeral[];
[Code] .....
But each time I compile it, it times out as if it were hitting an infinite loop. I have a feeling that I am not passing an individual character to the roman_to_decimal function but am unsure why.
I understand most of program below. Essentially, we have strings that we want to convert from hex values to decimal equivalents. We check if first two characters of string are 0x or 0X, which signifies hex format. If our hex string consists of solely digits like 0x25, then the processing is simple. We take the digit assign it to answer variable, and for each additional position in the hex base-16 system, we multiply the digit by 16.
Now if the hex string is something like 0x2A, then for 'A', the hexalpha_to_int() function is called, since we are able to find 'A' in the hexalpha string, we take the value of 'A', which is ascii 65 divide it by 2 and add 10 to it: 65/2+10=42.5. This doesn't make sense. What is the purpose of this logic right here: 10 + (i / 2).
Code:
#include <stdio.h>
#include <stdlib.h>
int hexalpha_to_int(int c){
char hexalpha[] = "aAbBcCdDeEfF";
[Code] ....