I got this algorithm of conversion and now I'm stuck at how to code it.
"Algorithm to Convert From any Base to Base 10 Decimal."
Let 'n' be the number of digits in the number. For example, 104 has 3 digits, so 'n'=3. Let 'b' be the base of the number. For example, 104 is decimal so 'b' = 10. Let 's' be a running total, initially 0.
For each digit in the number, working left to right do:
Subtract 1 from 'n'. Multiply the digit times b^n and add it to 's'.
When done with all the digits in the number, the decimal value should be 's' .
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
I've been trying to write some code to do what I mentioned in the title, but I haven't had much luck. I get very confused when I deal with bitwise operators, so it's hard for me to write this kind of encoding on my own. I need this encodement so I can login to an email account using smtp.
This was an exercise from a book (convert a character string into a floating point value). It seems to work with both negative and positive decimal numbers.
It basically get each digit from the string multiplies by 10 to hold the place, and then adds the next to the result, if that makes sense.
Then determines where the decimal and null character are to figure out what to multiply by (1/1000 or whatever) to determine where the decimal should go. The variable names dealing with this part of the program aren't accurate names right now.
My question is, the output, is always putting 6 zero's. So if the argument is .95, Ideally the output should say .95 and not .950000, even though the value is still correct.
I know there the %.2f to determine the amount of decimals, but the amount of decimals in these instances would be varying depending on the argument sent to the function.
So, if 600.158 was sent as an argument, only 3 decimals would be displayed, as opposed to two from the previous example. Is there a way to do this?
Code: // Function to convert a string to an integer #include <stdio.h> double strToFloat (const char string[])
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
I need to convert an integer, for example 10, to its base 16 equivalent, 16. I found this code that converts a base 16 number to base 10, but I need the opposite. Plus, this code doesn't seem to work properly with input values under 32.
I had the idea to write a program that would convert a decimal integer into any base up to 36 (there are no letters after that) so I decided to give it a try.
Code: #include <stdio.h> #include <stdlib.h> char letters(int r); // prototypes function for converting 10's to A's and so on, base 11+ will work int main() {
int base; int d; //declares decimal integer int d_clone; // clones d for a loop
I need to create a generic function that changes from any starting base, to any final base. I have everything down, except my original function took (and takes) an int value for the number that it converts to another base. I decided to just overload the function. I am Ok with changing between every base, but am slightly off when using my new function to take in a string hex value.
The code below should output 1235 for both functions. It does for the first one, but for the second, I am currently getting 1347. Decimal to Hex works fine - It's just the overloaded function (Hex to anything else) that is slightly off.
void switchBasesFunction(stack<int> & myStack, int startBase, int finalBase, int num); void switchBasesFunction(stack<int> & myStack, int startBase, int finalBase, string s);
You enter decimal number into the program and what base you want. The integer part of the decimal is being handled fine, but the decimal is not.
For example, I enter 15.6847 and base 10, which means I'm going from base 10 to base 10. It spits out 68469999999999 for the decimal part. (Do not worry about the first block of numbers. The second block seperated from the first by a space is where the decimal will appear in order.)
#include <iostream> #include <string> #include <math.h> using namespace std; int baseConverter(int, int, int *, int *);
How would you go about converting a decimal value to hex and then do math? Every example of converting decimal to hex that I have seen creates an array and I wouldn't be able to do math if I did that. Something like this.
15 decimal to hex F 17 decimal to hex 11 F hex + 11 hex = 20
I'm working on a program and I need to convert big numbers to radix 64. I would like to shorter them whit conversion that's why I choosed base 64. I have two problems:
1. The conversion works only for not so big numbers. Untill about 2^32. I would like to convert bigger numbers. Is there any solution? (I thought on GMP/MPIR library, but I can't managed it.)
2. The conversion back to decimal base doesn't works, because I use 'strtoul()' which doesn't support bigger bases like 36.
using namespace std; void Conversion (int n); int main () {
[Code] .....
I now have a follow on exercise that requires me to convert to binary from ant base up to 10, i thought this would just be replacing the 2 with a variable obtained form the user, but i am having problems as within the function i am getting an error that i haven't passed enough arguments and i cant see why i get this. I did the following:
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
What is the difference between the two functions below? I created the function in the top and my friend created the function in the bottom. I just want to know why the function with the while loop prints the binary numbers backwards. And the recursive function prints the binary numbers correctly.
void findBinary(int num) { int remainder = 0; while ( num > 0) { remainder = num % 2; cout << remainder; num = num / 2;
#include "stdio.h" #include <stdarg.h> #include <math.h> // Main Function int main(void){ int number; printf(" Please enter a number from 1-10? "); scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
So I am trying to write a program that converts roman numerals into decimal numbers. I so far have come up with:
Code: #include <stdio.h> #include <ctype.h> // importing the tolowerfunction //variables int decimal, total; char numeral[];
[Code] .....
But each time I compile it, it times out as if it were hitting an infinite loop. I have a feeling that I am not passing an individual character to the roman_to_decimal function but am unsure why.
I understand most of program below. Essentially, we have strings that we want to convert from hex values to decimal equivalents. We check if first two characters of string are 0x or 0X, which signifies hex format. If our hex string consists of solely digits like 0x25, then the processing is simple. We take the digit assign it to answer variable, and for each additional position in the hex base-16 system, we multiply the digit by 16.
Now if the hex string is something like 0x2A, then for 'A', the hexalpha_to_int() function is called, since we are able to find 'A' in the hexalpha string, we take the value of 'A', which is ascii 65 divide it by 2 and add 10 to it: 65/2+10=42.5. This doesn't make sense. What is the purpose of this logic right here: 10 + (i / 2).
Code: #include <stdio.h> #include <stdlib.h>
int hexalpha_to_int(int c){ char hexalpha[] = "aAbBcCdDeEfF";
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){ char* binNum = decToBin(25); int i = 0; while(binNum != NULL){
I am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3 10110101 11111111 10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
