C :: Function To Convert String To Floating Decimal
Dec 24, 2014
This was an exercise from a book (convert a character string into a floating point value). It seems to work with both negative and positive decimal numbers.
It basically get each digit from the string multiplies by 10 to hold the place, and then adds the next to the result, if that makes sense.
Then determines where the decimal and null character are to figure out what to multiply by (1/1000 or whatever) to determine where the decimal should go. The variable names dealing with this part of the program aren't accurate names right now.
My question is, the output, is always putting 6 zero's. So if the argument is .95, Ideally the output should say .95 and not .950000, even though the value is still correct.
I know there the %.2f to determine the amount of decimals, but the amount of decimals in these instances would be varying depending on the argument sent to the function.
So, if 600.158 was sent as an argument, only 3 decimals would be displayed, as opposed to two from the previous example. Is there a way to do this?
Code:
// Function to convert a string to an integer
#include <stdio.h>
double strToFloat (const char string[])
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
What is the difference between the two functions below? I created the function in the top and my friend created the function in the bottom. I just want to know why the function with the while loop prints the binary numbers backwards. And the recursive function prints the binary numbers correctly.
void findBinary(int num) { int remainder = 0; while ( num > 0) { remainder = num % 2; cout << remainder; num = num / 2;
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){ char* binNum = decToBin(25); int i = 0; while(binNum != NULL){
I'm trying to convert 4 hex register into floating point value using IEEE 754 floating point format. My device will reply 4 register value. The problem is that it always reply for example 0x10 as 10 when i use getc() hence using char variable to store it is not ideal.
Having an issue with the following code. I read in a decimal value from a text file, use atof (or strtod, either gives the same error) to convert the read value into a floating point number. When putting the output of atof in a double, it works fine. However when putting the output of atof into a float, the decimal places get lost. Putting the result in a double, then into a float gives the same result. This only happens when using getline.
I've tried using temp arrays to put the result of pch in, sprintfs and such to try and work around it, but whenever a value originates from the getline command, the float value always loses decimal places. I've also tried varying the precision in the printf statement, but its always the same. When I write the float result to a file via FILE.write in binary mode, the result comes out without the decimal places when I read it back in later.
The simple solution is to not use float and use double, but there are a number of reasons I'm using float to begin with and don't want to change that.
Side note, this code works fine on a windows machine, the error is coming from using g++ on a mac.
In short I'm converting a floating point bilinear image resampling routine into one that only uses fixed point arithmetic. I've gotten rid of nearly all the floats now, in fact all but one and the results at the moment are in distinguishable from the floating point version. It's a maths issue really. Some pseudocode goes like this.
Code: for( int xx=0; xx<ow; xx++ ) { int_center = (ccx >> 16); int temp = xx * 2; for (j = int_center; j <= int_center + 1; j++)
[Code] ....
Where ccx is and integer error accumulator that gives me a scaled integer. Shifting down buy 16 gives me the relative pixel I need to be working on. The line just after where the inner loop begins is where I have the last remaining float. FILTER_FACTOR is essentially a percentage by which I scale the error accumulator to the correct amount.
For example.
ccx = 98303. Which is a value of 1.5 when shited down by 16 bits. Obviously I can shift it because it will round and I lose the precision. Lets say FILTER_FACTOR is 39321. Which is 60% of 1 (65535) So what I'd like to know is, is it possible to use the FILTER_FACTOR as an integer and do some fancy integer math to scale the result from (ccx - (j<<16)) by the representative amount that is FILTER_FACTOR. In this example 60%. Effectively getting 40% of (ccx - (j<<16)) At the moment FILTER_FACTOR is still a float and therefore 0.6, which of course works just fine.
How would you go about converting a decimal value to hex and then do math? Every example of converting decimal to hex that I have seen creates an array and I wouldn't be able to do math if I did that. Something like this.
15 decimal to hex F 17 decimal to hex 11 F hex + 11 hex = 20
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code: #include <iostream> #include <iomanip> #include <cmath> using namespace std; float Conversion (int n, int b);
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
#include "stdio.h" #include <stdarg.h> #include <math.h> // Main Function int main(void){ int number; printf(" Please enter a number from 1-10? "); scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
I'm VERY new in programming and I'm having trouble converting an integer to string. I need to create a function for a programme I'm working on for my school. My problem is that i am only allowed to use the libraries stdio.h, time.h and stdlib.h as well as printf, scanf, system, srand, time and rand. If I was allowed to use itoa or pointers it would be easier but i am not.
So I am trying to write a program that converts roman numerals into decimal numbers. I so far have come up with:
Code: #include <stdio.h> #include <ctype.h> // importing the tolowerfunction //variables int decimal, total; char numeral[];
[Code] .....
But each time I compile it, it times out as if it were hitting an infinite loop. I have a feeling that I am not passing an individual character to the roman_to_decimal function but am unsure why.
I understand most of program below. Essentially, we have strings that we want to convert from hex values to decimal equivalents. We check if first two characters of string are 0x or 0X, which signifies hex format. If our hex string consists of solely digits like 0x25, then the processing is simple. We take the digit assign it to answer variable, and for each additional position in the hex base-16 system, we multiply the digit by 16.
Now if the hex string is something like 0x2A, then for 'A', the hexalpha_to_int() function is called, since we are able to find 'A' in the hexalpha string, we take the value of 'A', which is ascii 65 divide it by 2 and add 10 to it: 65/2+10=42.5. This doesn't make sense. What is the purpose of this logic right here: 10 + (i / 2).
Code: #include <stdio.h> #include <stdlib.h>
int hexalpha_to_int(int c){ char hexalpha[] = "aAbBcCdDeEfF";
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
I am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3 10110101 11111111 10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
Function is not returning a decimal point value. Here is my function
int meanValueFunction(vector<int> arrayValues){ int sum = 0; sum = sumFunction(arrayValues); float meanValue = sum/arrayValues.size(); cout<< meanValue << endl; return meanValue;
I want result in decimal point i.e 27.2 for the values (2 4 20 10 100) but it returns 27 instead.
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111 Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010 Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102 Number entered is not a binary number
#include <iostream> using namespace std; int main() { int num;
I'm stuck on the last part of my program. The directions are the following~
Expand the program to add an overloaded function to handle floating point numbers (i.e., doubles). Include output for one list of integers and one list of doubles. Use this function prototype: double avgx(double&, double&, int, ...);
Compile and run. You should have one function named avg, one named davg, and two functions named avgx
My code does not compile and I think I'm not declaring my function prototype correctly?
#include <iostream> using std::cout; using std::endl; #include <cstdarg> // function prototype(s) int avg(int, ...);
