How would you go about converting a decimal value to hex and then do math? Every example of converting decimal to hex that I have seen creates an array and I wouldn't be able to do math if I did that. Something like this.
15 decimal to hex F
17 decimal to hex 11
F hex + 11 hex = 20
I had an exercise to convert from decimal to binary with base 2, it was simple simple i did the following:
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
void Conversion (int n);
[Code] .....
I then had an follow up exercise which was to replicate but for any base up to 10, i thought i would just have to replace 2 with a variable obtained from the user, however this did not work as i got an error saying too few arguments function but i cannot see why i am getting this.
Code:
#include <iostream>
#include <iomanip>
#include <cmath>
using namespace std;
float Conversion (int n, int b);
[Code] ......
The code should convert binary numbers to decimal but it doesn't..
Code:
#include <stdio.h>
#include <math.h>
#include <string.h>
int main()
{
[Code] ....
The goal of my program is to convert a decmial number to a binary number.First, the program gets an input to an array of chars, and the function translate_dec_bin converts this array to a decimal number through the strtoul function.The problem is that my program prints the binary number with an additional "0".For exmaple, for the input 1 - the program prints 01 instead of 1, for the input 3 - the program prints 011 instead of 11.
Code:
#include <stdio.h>
#include <stdlib.h>
#define MAX_LEN 20
void translate_dec_bin(char s[]){
char st[sizeof(unsigned)*20] = { 0 };
}
[code]....
What is the difference between the two functions below? I created the function in the top and my friend created the function in the bottom. I just want to know why the function with the while loop prints the binary numbers backwards. And the recursive function prints the binary numbers correctly.
void findBinary(int num) {
int remainder = 0;
while ( num > 0) {
remainder = num % 2;
cout << remainder;
num = num / 2;
[Code] .....
#include "stdio.h"
#include <stdarg.h>
#include <math.h>
// Main Function
int main(void){
int number;
printf(" Please enter a number from 1-10? ");
scanf("%d", &number);
[Code] ....
I took the while statement out didn't want that in there.
I have written this function.
void intToBase(unsigned int val,char *buff, unsigned int base) {
int digit = val%base;
if(val == 0)
return;
intToBase((val / base), buff + 1, base);
if(digit >= 0 && digit <= 9)
*buff = (digit + '0');
if(digit >= 10 && digit <= 15)
*buff = (digit + 'A' - 10);
}
This function is suppose to convert a decimal number (val) to any other base number and put it into a string (buff).
But the function puts the value in a opposite way, like if the answer is suppose to be "123" i get this "321".
Note: the function must be recursive and i can't use loops.
This was an exercise from a book (convert a character string into a floating point value). It seems to work with both negative and positive decimal numbers.
It basically get each digit from the string multiplies by 10 to hold the place, and then adds the next to the result, if that makes sense.
Then determines where the decimal and null character are to figure out what to multiply by (1/1000 or whatever) to determine where the decimal should go. The variable names dealing with this part of the program aren't accurate names right now.
My question is, the output, is always putting 6 zero's. So if the argument is .95, Ideally the output should say .95 and not .950000, even though the value is still correct.
I know there the %.2f to determine the amount of decimals, but the amount of decimals in these instances would be varying depending on the argument sent to the function.
So, if 600.158 was sent as an argument, only 3 decimals would be displayed, as opposed to two from the previous example. Is there a way to do this?
Code:
// Function to convert a string to an integer
#include <stdio.h>
double strToFloat (const char string[])
[Code].....
So I am trying to write a program that converts roman numerals into decimal numbers. I so far have come up with:
Code:
#include <stdio.h>
#include <ctype.h> // importing the tolowerfunction
//variables
int decimal, total;
char numeral[];
[Code] .....
But each time I compile it, it times out as if it were hitting an infinite loop. I have a feeling that I am not passing an individual character to the roman_to_decimal function but am unsure why.
I understand most of program below. Essentially, we have strings that we want to convert from hex values to decimal equivalents. We check if first two characters of string are 0x or 0X, which signifies hex format. If our hex string consists of solely digits like 0x25, then the processing is simple. We take the digit assign it to answer variable, and for each additional position in the hex base-16 system, we multiply the digit by 16.
Now if the hex string is something like 0x2A, then for 'A', the hexalpha_to_int() function is called, since we are able to find 'A' in the hexalpha string, we take the value of 'A', which is ascii 65 divide it by 2 and add 10 to it: 65/2+10=42.5. This doesn't make sense. What is the purpose of this logic right here: 10 + (i / 2).
Code:
#include <stdio.h>
#include <stdlib.h>
int hexalpha_to_int(int c){
char hexalpha[] = "aAbBcCdDeEfF";
[Code] ....
I nead to write a program that convert an octal number to decimal number, I thought I did it right but it doesn't work.. I have to use in the first for loop as it is because it is part of the instructions (student homework).
#include <iostream>
#include <math.h>
using namespace std;
void main() {
double numOfDig, num, newNum;
[Code] ....
I want to convert a decimal number to binary and store it in a string so that I can use that binary output for later computation. Here is what I did
Code:
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
void main()
[Code] ....
Now as you can see that all the binary output is in a[] but how do I get it into a string so that I can use something like printf("%s",string) and get the binary output ?
I'm trying to pass a decimal number to a function and convert it to binary and return it and print it out in main. But it prints out 1011 and then seg faults...not sure where it's tripping up
Code: int main(){
char* binNum = decToBin(25);
int i = 0;
while(binNum != NULL){
[Code].....
I tried to convert byte array with hex to equivalent decimal value as follows but it gives me unexpected results:
byte hex_arr[] = { 0x00, 0x01, 0xab, 0x90};
unsigned long i=0;
i = hex_arr[3] + (hex_arr[2] << 8) + (hex_arr[1] << 16) + (hex_arr[0] << 24);
the output is 4294945680
Correct output should be 109456
but when I try with byte hex_arr[]={0x00,0x00,0x0f,0xff};
it gives correct out put 4095
the correct output works until the hex values is {0x00,0x00,0x7f,0xff}
I am trying to make a program that will convert a list of binary numbers from a file into decimal and print the decimal to the screen. I have no problem doing the conversion, the problem comes up when our teacher wants the input file in a format as such:
3
10110101
11111111
10101010
The first number is supposed to tell the program how many different 8bit strings it is going to have to convert, and then the following lines are those binary numbers.
I am not very experienced with file inputs, and I know how to open files and read lines in.. The problem is, how to say "ok the first line says 3, so now I have to convert the next 3 lines" . I am assuming it is just a simple loop that I am missing....
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111
Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010
Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102
Number entered is not a binary number
#include <iostream>
using namespace std;
int main()
{
int num;
[code]....
Here's the part of the codes where I tried to use boolean expression:
Code:
#include <iostream>
using namespace std;
int main() {
int num;
cout << "8-bit Binary Number=";
cin >> num;
[Code] .....
How can I get started with the body?
I got this algorithm of conversion and now I'm stuck at how to code it.
"Algorithm to Convert From any Base to Base 10 Decimal."
Let 'n' be the number of digits in the number. For example, 104 has 3 digits, so 'n'=3.
Let 'b' be the base of the number. For example, 104 is decimal so 'b' = 10.
Let 's' be a running total, initially 0.
For each digit in the number, working left to right do:
Subtract 1 from 'n'.
Multiply the digit times b^n and add it to 's'.
When done with all the digits in the number, the decimal value should be 's' .
Here's the part of the codes where I tried to use boolean expression:
#include <iostream>
using namespace std;
int main()
[Code].....
May I know that how can I get started with the body?
Code:
template<class T>
class Convert {
T data;
public:
Convert(const T& tData = T()) : data(tData)
[Code] ....
Why do we use operator? Is float and double function names below?
Code:
Convert<int>::operator<float> float();
Convert<int>::operator<double> double();
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h>
#include <math.h>
char* ReverseString (char _result[]) {
int start, end, length = strlen(_result);
char swap;
for (start = 0, end = length-1; start < end; start++, end--)
[code]....
How to do this program i can easily do it in a simple for loop but i have to do this program with the following directions:
1. Write a function called bitN() that returns the value of bit N in number, where number is the first parameter, and N is the second. Assume N of the least significant bit is zero and that both parameters are unsigned int's. (A simple one-liner will suffice)
2. Write a main() function that uses bitN() to convert a decimal integer into its binary equivalent. Obtain the integer to convert from the first command-line argument.
3. Use the expression
unsigned int numBits = sizeof(unsigned int)*CHAR_BIT;
to get the number of bits in an unsigned int. (Include limits.h to get the definition for CHAR_BIT.)
To one decimal place?
Code:
#include <stdio.h>
int main() {
double num, trunc, round;
printf("
Enter a Decimal:
}
[code]...
That's my code currently, I've gotten it to round as I want, but I want it to truncate to one decimal place as well.If i enter 4.157, It should truncate to 4.1, and round to 4.2.
I'm trying to make a program that takes up to a seven digit binary number and converts it to its decimal equivalent. I'm still a beginner, so this might be a simple question but how do I stop the user from entering anything but 1s and 0s? This means no decimals or numbers other than 1 or 0.I already made it so it won't accept anything below 0 or above 1111111.
View 1 Replies View RelatedI am trying to convert user inputted decimal to binary .
Code:
#include<stdio.h>
main() {
int a,b,c,d[30],i,j,e[30];
[Code].....
I just wrote code that is a program for a relativity calculator. However many of my outputs (because the values tend to be large) end up in scientific notation. Although useful, its not great for the laymen, or nice looking.
How can I change it so that output is not in scientific notation? here is the code:
// This program/converter is designed to find the desired 'real' values using Einstein's theory of relativity
#include<iostream>
#include<math.h>
#include<stdlib.h>
[Code]....