To one decimal place?
Code:
#include <stdio.h>
int main() {
double num, trunc, round;
printf("
Enter a Decimal:
}
[code]...
That's my code currently, I've gotten it to round as I want, but I want it to truncate to one decimal place as well.If i enter 4.157, It should truncate to 4.1, and round to 4.2.
how I would easily round a double or a float to the nearest cent. It was easy enough to do it in visual basic or java, But i cannot figure out how to do it in C.
View 6 Replies View RelatedI have a float values I'd like to round off to the nearest integer value.
That is to say, if the float value is 44.234533, the integer value should be 44. If the float value is 44.682101, the integer value should be 45.
How do I do this?
The problem says: Draw a box with rounded corners. Define a class Box, consisting of four lines and four arcs. So I wrote the below code for that exercise:
#include <Simple_window.h>
Simple_window win(Point(100,100), 600,400, "semi-ellipse");
struct Box: Shape{
Box(Point p, int ww, int hh): w(ww), h(hh)
{ add(Point(p.x-ww,p.y-hh)); }
[Code] ....
When I ran it I faced this exception:
Unhandled exception at 0x757FE9D7 (ole32.dll) in test.exe: 0xC0000005: Access violation reading location 0x00000004.
I know this refers to declaring "Simple_window win(Point(100,100), 600,400, "semi-ellipse");" in global state. But I did that because I had to do it. The problem is that how to attach lines and also object (here b) to Simple_window win in either parts (main() function and also Box struct).
I don't understand why my Do While loop skips over the input the second time round?
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <string>
using namespace std;
//prototype
string reverseInput(string *);
[Code] ....
I have a simple game loop.
while(true) {
//round initialization stuff
while(true) {
//capture input, make pieces move,
}
}
I am faced with the decision of what is the best way of restarting the game. The problem is, the condition for restarting a game is very, very deep inside the game's logic. So returning returning... is not an option, or at least, it ain't gonna be pretty.
So one of my considerations is to use a goto label, like so:
while(true) {
//round initialization stuff
while(true) {
//capture input, make pieces move,
} restart_round:
}
This seems to be the cleanest solution, since it allows me to fully reset the 'state' of the round, by first having all the destructors(pertaining to the round's objects) called, and then the constructors and other initialisation stuff.
Are there any subtleties that I am missing regarding this solution?
I am making a game of quiz and i want to play a small clip in one of the rounds, but i dont know how to do it in c++ ....
View 3 Replies View RelatedI've recently completed a fully functional round robin algorithm for a class, however upon running a myriad of test cases I found where mine fails. I think it best to show with an example:
Process-Burst-Arrival
P1 1 0
P2 1 1
P3 1 4
P4 3 8
P5 5 20
Currently what happens is this, it runs perfectly from process 1 through process 3. However once it reaches process 4 it does the appropriate thing and adjusts my total processing time (q variable) to the arrival time of process 4. Great! But then, it rolls over to check the queue again and it's bringing in process 5, changing q to it's arrival time. Then it proceeds to swap them in and out due to them both now being in the queue and time quantums/slices running out.
My question is this: How/where do I put a lock on the while loop that runs the simulated scheduler (round robin in this instance) to not grab the next process when there's a time gap in between each process.
This specifically is the two lines that I can't seem to get working as they should:
if(arrival[i]>q)
q=arrival[i];
FULL CODE BELOW
#include <iostream>
using namespace std;
void RR(int n, int burst[], int arrival[], int throughput)
{
[Code].....
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
I was told to use a round function to round a number to give an integer number that is closer to the real value. (for example if the number is 114.67 I need to print an int value of 115 instead of 114)
I am not exactly sure how a round function works, but I am told to include math.h library. What I try doesn't seem to work.
How would you go about converting a decimal value to hex and then do math? Every example of converting decimal to hex that I have seen creates an array and I wouldn't be able to do math if I did that. Something like this.
15 decimal to hex F
17 decimal to hex 11
F hex + 11 hex = 20
I am very new to programming and have been working on a program that can receive decimals or binary numbers and convert them. The decimal --> binary works fine. For some reason I cannot figure out I cannot get the "BinaryToDecimal" function to perform. By putting a "printf" into the for-loop.
Code:
#include <stdio.h>#include <string.h>
#include <math.h>
char* ReverseString (char _result[]) {
int start, end, length = strlen(_result);
char swap;
for (start = 0, end = length-1; start < end; start++, end--)
[code]....
How to do this program i can easily do it in a simple for loop but i have to do this program with the following directions:
1. Write a function called bitN() that returns the value of bit N in number, where number is the first parameter, and N is the second. Assume N of the least significant bit is zero and that both parameters are unsigned int's. (A simple one-liner will suffice)
2. Write a main() function that uses bitN() to convert a decimal integer into its binary equivalent. Obtain the integer to convert from the first command-line argument.
3. Use the expression
unsigned int numBits = sizeof(unsigned int)*CHAR_BIT;
to get the number of bits in an unsigned int. (Include limits.h to get the definition for CHAR_BIT.)
I'm trying to make a program that takes up to a seven digit binary number and converts it to its decimal equivalent. I'm still a beginner, so this might be a simple question but how do I stop the user from entering anything but 1s and 0s? This means no decimals or numbers other than 1 or 0.I already made it so it won't accept anything below 0 or above 1111111.
View 1 Replies View RelatedI am trying to convert user inputted decimal to binary .
Code:
#include<stdio.h>
main() {
int a,b,c,d[30],i,j,e[30];
[Code].....
I just wrote code that is a program for a relativity calculator. However many of my outputs (because the values tend to be large) end up in scientific notation. Although useful, its not great for the laymen, or nice looking.
How can I change it so that output is not in scientific notation? here is the code:
// This program/converter is designed to find the desired 'real' values using Einstein's theory of relativity
#include<iostream>
#include<math.h>
#include<stdlib.h>
[Code]....
I have to write a code that converts a hexadecimal value to a decimal value.So far I have
#include <iostream>
#include <cmath>
#include <string>
using namespace std;
int num;
char g;
int rem;
int main(){
cout << " input num: "; cin >> num;
[code]....
I think i need to put the g and rem value into a string... which I'm not sure how to do since g will be a char value and rem will be a int value... and after I believe i need to then flip the numbers in the string.. oh it has to be in the format of 0000
#include <iostream>
#include <math.h>
using namespace std;
int main() {
int N=0, counter=0, counter1=0,counter2=0, temp=0, temp1=0,dec=0,result=0, moder=0;
[Code] .....
This is Binary to Decimal Converter. It's not working. Although Dry Run of this program works fine.
My program needs to be adjusted to send out the numbers as 2 decimal , but nothing work.
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
int
number_ofstyle_American,
number_ofstyle_Modern,
[Code] .....
#include<iostream>
#include<conio.h>
using namespace std;
void main() {
int num1,num2,ans,rem;
[Code] .....
Question: A computer uses 10 bits to store integers with 1 bit for a sign. It stores an approximation of real numbers in 10 bits. The first bit of the first five is the sign of the mantissa and the other four bits are the mantissa. The first bit of the second five is the sign of the exponent and the other four the exponent.
1)What is the range of integers?
2)what is the range of real numbers(Float Type)
The first question was simple. I just found the smallest 10 digit binary number 1000000000 = -512 and then found the largest 10 digit binary number which would have to be 0111111111 = 511, therefore the range of integers is from -512 to 511.
For the second question - I am either making this harder than it is, or it really is a challenging question. So I followed the steps and first I was thinking I would take the number 1000000000 and convert this to a decimal (assuming its a 10 bit float)...But, can you even do this with a 10 bit float??
I ended up getting 1000000000 (after denormalizing) = .000100000 = 0.625.. would that be the minimum range? If so, then I know what I need to do to find the maximum , but if not - then I am really lost.
My Process was:
1.00000 X 2^(-4) = my final result of 0.625 after converting.
i am having issues converting a fraction to a decimal, i think the code would go in the istream because it is working with input data but i just cant figure it out.
#include <cstdio>
#include <string>
#include <iostream>
using namespace std;
[Code].....
I have a code and am asked to modify it so that it will take as input as unsigned binary number up to 16 digits in length and convert it into its equivalent decimal number and output that decimal number.
All I know is that I use library function strlen() in <cstring> to calculate the length of the input string.
I also know I have to use something called pow(2,4);
//pow (); is found in cmath
I was told to use sum = sum >>16-l; (l is the length of />/>
#include <iostream>
using namespace std;
int main() {
[Code]....
I am new at programming and I have some questions about converting decimal to hexadecimal WITHOUT using .net library. The problem is, that I don't know how to do vice versa. (if you type 1254, program returns 6,14,4. I want programm to return 4,14,6- this is almost hexadecimal number (14 is not converted to "E")). Also the task is, that program has to return value in string form.
static void Main(string[] args) {
int a = 0;
int result = 0;
int n=1000000;
int[] array = new int[n];
Console.WriteLine("Insert numbers");
a = int.Parse(Console.ReadLine());
[Code] ....
How do i get this with decimal part?:
for(i=1;i<=4;i++){
printf("%d
",m);
s = s + m/i
m = m + 2;
}
m/i?
So I tried debugging this program almost 10 times, each time finding a problem then making code to fix it, I used to get wrong values but then now after I changed the calculation from an infinity while loop to a for loop (because after some changes I realized that now I know the number of entries, meaning the start and the end of the loop) the program now displays no values at all. I checked it thoroughly and until the calculation process its functioning exactly the way it should but then the calculation breaks hell loose . Also the for loop that raises 2 to the power needed works fine too so it must be something with the other processes included in the calculation....
This used to be a function of a multiple value types conversion program, I isolated it for easier analysis as a lone standing program.
Code:
#include<iostream>
using namespace std;
int main() {
int d[10],e[10],anse=1,r,limit;
short int counterd=0,i,j;
float bind=0;
[Code] ....