C :: Round Up To Or Round Off To The Nearest Cent?
Nov 19, 2013how I would easily round a double or a float to the nearest cent. It was easy enough to do it in visual basic or java, But i cannot figure out how to do it in C.
View 6 Replieshow I would easily round a double or a float to the nearest cent. It was easy enough to do it in visual basic or java, But i cannot figure out how to do it in C.
View 6 RepliesI'm having trouble with rounding to the nearest cent in this program. It's the only thing that i need. The result i need is just off by one cent. I tried multiplying the interest amount by 100 and adding .5 then dividing all that by 100 but that just made it worse. Here's the code:
Code:
#include <stdio.h>
int main()
{
int count=0;
[Code]....
I have a float values I'd like to round off to the nearest integer value.
That is to say, if the float value is 44.234533, the integer value should be 44. If the float value is 44.682101, the integer value should be 45.
How do I do this?
To one decimal place?
Code:
#include <stdio.h>
int main() {
double num, trunc, round;
printf("
Enter a Decimal:
}
[code]...
That's my code currently, I've gotten it to round as I want, but I want it to truncate to one decimal place as well.If i enter 4.157, It should truncate to 4.1, and round to 4.2.
The problem says: Draw a box with rounded corners. Define a class Box, consisting of four lines and four arcs. So I wrote the below code for that exercise:
#include <Simple_window.h>
Simple_window win(Point(100,100), 600,400, "semi-ellipse");
struct Box: Shape{
Box(Point p, int ww, int hh): w(ww), h(hh)
{ add(Point(p.x-ww,p.y-hh)); }
[Code] ....
When I ran it I faced this exception:
Unhandled exception at 0x757FE9D7 (ole32.dll) in test.exe: 0xC0000005: Access violation reading location 0x00000004.
I know this refers to declaring "Simple_window win(Point(100,100), 600,400, "semi-ellipse");" in global state. But I did that because I had to do it. The problem is that how to attach lines and also object (here b) to Simple_window win in either parts (main() function and also Box struct).
I don't understand why my Do While loop skips over the input the second time round?
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <string>
using namespace std;
//prototype
string reverseInput(string *);
[Code] ....
I have a simple game loop.
while(true) {
//round initialization stuff
while(true) {
//capture input, make pieces move,
}
}
I am faced with the decision of what is the best way of restarting the game. The problem is, the condition for restarting a game is very, very deep inside the game's logic. So returning returning... is not an option, or at least, it ain't gonna be pretty.
So one of my considerations is to use a goto label, like so:
while(true) {
//round initialization stuff
while(true) {
//capture input, make pieces move,
} restart_round:
}
This seems to be the cleanest solution, since it allows me to fully reset the 'state' of the round, by first having all the destructors(pertaining to the round's objects) called, and then the constructors and other initialisation stuff.
Are there any subtleties that I am missing regarding this solution?
I am making a game of quiz and i want to play a small clip in one of the rounds, but i dont know how to do it in c++ ....
View 3 Replies View RelatedI've recently completed a fully functional round robin algorithm for a class, however upon running a myriad of test cases I found where mine fails. I think it best to show with an example:
Process-Burst-Arrival
P1 1 0
P2 1 1
P3 1 4
P4 3 8
P5 5 20
Currently what happens is this, it runs perfectly from process 1 through process 3. However once it reaches process 4 it does the appropriate thing and adjusts my total processing time (q variable) to the arrival time of process 4. Great! But then, it rolls over to check the queue again and it's bringing in process 5, changing q to it's arrival time. Then it proceeds to swap them in and out due to them both now being in the queue and time quantums/slices running out.
My question is this: How/where do I put a lock on the while loop that runs the simulated scheduler (round robin in this instance) to not grab the next process when there's a time gap in between each process.
This specifically is the two lines that I can't seem to get working as they should:
if(arrival[i]>q)
q=arrival[i];
FULL CODE BELOW
#include <iostream>
using namespace std;
void RR(int n, int burst[], int arrival[], int throughput)
{
[Code].....
This is a round robin execution. with gantt chart. arrival time and burst time. I think there is an error in my formula to get the right answer,i cant resolve it but my program is running. What is the code or the right formula??
#include<stdio.h>
int main(){
int i,j=0,n,time,remain,flag=0,ts;
int sum_wait=0,sum_turnaround=0,at[10],bt[10],rt[10];
int ganttP[50],ganttStartTime[50];
printf("Enter no of Processes : ");
scanf("%d",&n);
remain=n;
[Code] ....
I was told to use a round function to round a number to give an integer number that is closer to the real value. (for example if the number is 114.67 I need to print an int value of 115 instead of 114)
I am not exactly sure how a round function works, but I am told to include math.h library. What I try doesn't seem to work.
How do I round to the nearest half integer?
Example;
0 to 0.2 = 0
0.3 to 0.5 = 0.5
0.6-0.9 = 1
What's the formula for C++?
I found a way to do it in math but I want to know what I'd have to put in C++. It's (x*2+.5)remove decimal numbers and divide by 2. What do I put in place of "remove decimal"?
For ex; x = 8.4 using (x*2+.5)remove decimal then divide by 2.
8.4 * 2 = 16.8
16.8 + .5 = 17.3
17.3 - decimal = 17
17/2 = 8.5
I want to do something like;
cout << " Half number: << (x*2+.5)remove decimal/2 << endl;
What would I have to put in place of "remove decimal"?
Rounding a numerical figure up to the nearest hundred. E.G.:
256 >> 300
654 >> 700
15 >> 100
I would like to know the formula to enter into Visual Basic 2008. I'm making a calculator Program, and i need a function that rounds up to the nearest 100...
In this project you are asked to find K nearest neighbors of all points on a 2D space. The distance metric that you are going to use is simply the Euclidean distance example;
inputs:
10 2
3.57 3.18
84.91 27.69
93.40 4.62
67.87 9.71
75.77 82.35
74.31 69.48
39.22 31.71
65.55 95.02
17.12 3.44
70.60 43.87
Outputs:
1 9 7
2 10 3
3 2 4
4 2 3
5 6 8
6 5 10
7 10 9
8 5 6
9 1 7
10 2 6
Lets say that i have the coordinates of a 2D space (x and y), I want to store the coordinates as x and y in a vector to find the nearest neighbor of given points like i have:
#3.57 3.18#
#84.91 27.69
#93.40 4.62
#67.87 9.71
#75.77 82.35
#74.31 69.48
#39.22 31.71
#65.55 95.02
#17.12 3.44
#70.60 43.87
Each coordinates is like x y and it shows points 1 to 10 (like 3.57 3.18 is point 1 in 2D space ). My question is that how i add all x and y coordinates in vector? I started like this;
`struct point{
int x;
int y;
[Code] ....