Example;
0 to 0.2 = 0
0.3 to 0.5 = 0.5
0.6-0.9 = 1
What's the formula for C++?
I found a way to do it in math but I want to know what I'd have to put in C++. It's (x*2+.5)remove decimal numbers and divide by 2. What do I put in place of "remove decimal"?
For ex; x = 8.4 using (x*2+.5)remove decimal then divide by 2.
8.4 * 2 = 16.8
16.8 + .5 = 17.3
17.3 - decimal = 17
17/2 = 8.5
I'm having trouble with rounding to the nearest cent in this program. It's the only thing that i need. The result i need is just off by one cent. I tried multiplying the interest amount by 100 and adding .5 then dividing all that by 100 but that just made it worse. Here's the code:
Code: #include <stdio.h> int main() { int count=0;
Rounding a numerical figure up to the nearest hundred. E.G.:
256 >> 300 654 >> 700 15 >> 100
I would like to know the formula to enter into Visual Basic 2008. I'm making a calculator Program, and i need a function that rounds up to the nearest 100...
In this project you are asked to find K nearest neighbors of all points on a 2D space. The distance metric that you are going to use is simply the Euclidean distance example;
whats wrong with this code, I'm trying to parse a .js file and replace all the ";" with "; " i.e add a new line after each ";". So I load the file into a char[] buffer then assign a string to this contents of this buffer. Then loop char by char through using an iterator and check for a ";", if found use replace. So int i gets to about 85898 then crashes with unknown error, 'i' should reach about 175653. It does work up till it crashes. And, is this not a simpler way to load a file into a buffer, there is in C.
Lets say that i have the coordinates of a 2D space (x and y), I want to store the coordinates as x and y in a vector to find the nearest neighbor of given points like i have:
Each coordinates is like x y and it shows points 1 to 10 (like 3.57 3.18 is point 1 in 2D space ). My question is that how i add all x and y coordinates in vector? I started like this;
I want to round to the 2nd digit in a float. Such as 1.85458 to 1.85. How would i go about doing this. I currently keep rounding to the closest integer so the above would round to 2.
Code: #include <stdio.h> #include <math.h> int main(void){ float n;
was making a somewhat of a Binary to Hex convertor but only 10/15 cases work and the non working are in the middle; 0010, 0011, 0100, 0101, 0110, 0111;;
// Test Code.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <cmath> #include <conio.h> using namespace std; int main(void) {int A; cout << "Enter the binary starting with the MSB
it produces a correct number when called, but it is not a rounded number, the roundf((float)cel) does nothing. I get the same number with and without it.
I have an assignment for uni which requires the program to ask the user to input a number in for a variable to use in later equations. The assignment specifies that if the number that is input into the program is not an interger that it needs to be rounded UP to the nearest interger. e.g. 2.5 = 3, 5.00001 = 6 etc. i have identified this variable using "int" which i know makes it an interger however it also always rounds the number DOWN to the nearest interger. I was just wondering what the best way to approach this problem was. The only idea i have is to put + 0.99999 at the end of this variable when it is worked out so that if it is not a whole number it will be raised above the next interger and then rounded down however this will not work if there is too many decimal places.
Ok so I'm in a programming 1 class working with c++. I have the following assignment:
Write a C++ program that: asks for and accepts the Percentage earned with as a double (i.e. 75.45) rounds it to an integer (>= .5 rounds up, <.5 rounds down.) prints the original Percentage and the corresponding Grade and Points exactly as shown below. prints an error message for any input that is less than 0 or greater than 100.
For example, if user enters 89.4, the program prints out: Percentage: 89.4% Grade: B Points: 3.00 You must use an if-else statement to do this in your program. Use fixed and precision output manipulators (see Ch. 3) to display the values with the exact precision shown above.
IMPORTANT: Each if statement condition should contain only one comparison! read this again This means code that is similar to this is NOT okay: if (Percentage >= 80.00 && Percentage <90.00) This code is not acceptable because the if statement condition above has two comparisons. (Hint: If you order your if-else chain statements correctly, you will only need one comparison in each.)
I have the program working, but I'm pretty sure I'm not rounding how my professor would like it to. This is my code:
So my issue here is the rounding, and then theres the converting the double percetnage to an integer. In my next assignment I have to write the program with a switch statement.
I have made a random number generator to create a number between 1000 and 9000, but I always get numbers with many 10s and units. I want to round them 100s.
I made this dice simulator which basically throws the dice 1 million times and outputs the frequency and percentage average for each side (1 to 6).
Everything is working fine, except my averages (floats) seem to be rounding up, causing 4% being "unassigned" at the end of the million rolls. I'm outputting with a setprecision of 2, but I only get 0's and no fractional numbers.
How would I be able to round a number in multiples of another...
Let's say width is 150 And multiple to be 64... I want 150 to become 128... if it was 160 to become 192...
The width number will change and I want to covert it in multiples of the other number example 64... The minimum value will always be the multiple number used...
In short: 1. Input is an N x N grid with a non-negative integer in each cell. 2. We can move from one cell to any of its adjacent cell in all four directions. 3. The 'cost' needed to move from one cell to another is the positive difference of their values. 4. We have to find the minimum cost such that we can visit atleast half of the cells with that cost;
I am not being able to think of any solution that runs in time O(N2) or better (N2 because of the size of N, any algorithm worse than it will not run within the time limit) for this problem.
So I need a hint on how to solve this problem optimally.
how I would easily round a double or a float to the nearest cent. It was easy enough to do it in visual basic or java, But i cannot figure out how to do it in C.
