The output should be something like:
5
45
543
5432
54321
How to make triangles using c++, in nested while loops.
The triangles were:
*
**
***
****
*****
******
*******
********
*********
**********
I have made a code for this:
int counter=1;
while (counter<=10){
int counter2=1;
while (counter2<counter){
[Code] .....
I was not quite sure about this one.
What output would you expect from this program?" The output was not what I expected. I've psuedo-coded this out and I'm still missing something.
Code:
#include <stdio.h>
int main () {
int numbers[10] = { 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
int i, j;
}
[code]....
The output: Code: 1 1 2 4 8 16 32 64 128 256 So when I look at this first loop I see that j = 0, which is less than 10, so then the program statement should commence, which is another for loop. So in this inner for loop I see that i = 0, which is not less than j, so this loop should terminate. Then the value of j increments by 1 and the first go around of the loop has completed.
Now I see that j = 1, so this is less than 10, and the inner for loop commences once again. This time though, i actually is less than j, so numbers[1] = numbers[1] + numbers [0], or numbers[1] = 0 + 1. Now the value of i is incremented by 1 and the first go around of this inner loop has completed. Then the value of j increments by 1 and another go around of that loop has completed.
So now j = 2, i = 1, and numbers[2] ( which is 0 ) = numbers[2] + numbers[1], or numbers[2] = 0 + 1. I was expecting the output to be an array full of 1's. However this is not the case..
Howi can made nested loops?
Code:
for (yax=0; yax<10; yax=yax+1) {
for (xax=0; xax<100; xax=xax+1) {
printf("%d
",yax);
}
}
way what i tired dont work. or maybe works but why this prints only zeros ?
So in class our teacher assigned us a program where we have to use nested for loops to creates triangles. How does the 2nd for loop print more than 1 star? since the for loop will only run the cout 1 time until it gets to the escape sequence, how does it print more than 1 star on a line? this is what is confusing me. I feel like if i can grasp the understanding of that and what the for loops are doing i can finish the rest of this program with ease
#include<iostream>
using namespace std;
int main()
[Code].....
Getting close but I think I am stuck on the second loop. The input you put in will be doubled (and it's not supposed to).
Code:
int main() {
int n, i, j, k;
printf("What would you like the height to be? (Positive odd integer)
");
scanf("%d", &n);
[Code] .....
The user will enter the number of '*'s on the 1st row (ntop) and then the number of rows forming the trapezoid (nrows). (using <iostream>, cout)
For instance, an inverted trapezoid with 7 '*"s in the 1st row and 3 rows forming the inverted trapezoid looks like:
1*******
2 *****
3 ***
(this pyramid is centered, in case it isnt when its posted). Also, each descending row has two less asteriks than the above row.
I am having trouble with the four loop displaying the number of "*" and " ". I know its a relationship with variables in the for loops, my output is just never doing what i want it to.
THis is the guideline for the for loop:
Use for loops to display the inverted trapezoid. Your outer for loop will iterate the total number of rows times. For each row use one nested for loop to display blanks (the 1st row contains no blanks) and another nested for loop to display the characters '*'.
Heres my for loops so far:
for (i = nrows; i >= 1; i--) {
for (j = 0; j >= nrows; j++) {
cout << " ";
} for (k=ntop; k >= 2; k--) {
cout << "*";
} }
The ouput is just blank as of now.
Write a program that prints a multiplication table using nested loops. In main ask the user for the smallest column number , the largest column number and the size of the increment. Ask the user for the same information for the row values.
In the example the column values entered are: 5, 15 and 2 and the row values 3, 6 and 1.
Given those numbers you would generate the following table.
Multiplication Table
| 5 7 9 11 13 15 ___|___________________________________ | 3 |
15 21 27 33 39 45 4 | 20 28 36 44 52 60 5 | 25 35 45 55 65 75 6 | 30 42 54 66 78 90
Print the 24 values with the grey background. The other numbers show the values to be multiplied.
Code:
#include<stdio.h>
main() {
int a,b,c,d,e,f;
int i,j,total;
printf("Please enter smallest column number: ");
scanf("%i",&a);
printf("
[Code] ....
Challenge:
As an added challenge try to print out the column
headings (5 7 9 11 13 15) and the row headings (3 4 5 6)
For each quarter, calculate and display the beginning principal balance, the interest earned, and the final principal balance for the quarter.For example: The user entered 1000.00 for the beginning principal balance, 5.25 for the interest rate, and 8 for the number of quarters. The output from this part of the program should be similar to the following:
Q| Beginning Principle| Interest Earned| End Principle
1| $1,000.00 | $13.13 | $1,013.13
2| $1,013.13 | $13.30 | $1,026.42
3| $1,026.42 | $13.47 | $1,039.89
etc
Here is the code I have so far, and I just am not quite sure where to go next.
Code:
{
cout << "Quarters" << " " << "Beginning Principles" << " " <<"Interest Earned" << " " <<"End Principal" << endl;
endprin = balance + (quarter * interest);
interest = quarter * interest;
cout << endprin << endl;
}
This is a test program that takes a number of arguments from the command prompt and concatenates them into a string object. I was looking into the possibility of using the range-based for loop for this purpose. Can it be done with pointer based arrays? I am mainly doing this because I want to have a firm understanding of range-based for, but also would like to do this with least amount of code possible.
This is my working program:
#include <string>
#include <iostream>
int main(int argc, char *argv[]) {
if (argc > 1) {
std::string concatenatedArgs;
[Code] ....
Can I somehow replace my while-loop with a range-based for? I tried the following but the compiler points out that begin and end were not declared in the scope of the range-based for loop.
#include <string>
#include <iostream>
int main(int argc, char *argv[]) {
if (argc > 1) {
std::string concatenatedArgs;
[Code] ....
Have an assignment due in a few weeks and I'm 99% happy with it My question is is there a method or process for reducing redundant code in nested loops. Ie my code compiles and runs as expected for a period of time and after a few goes it omits a part or prints an unexpected out ext so basically how to find when the redundancy occurs with out posting my code so I can learn for my self?
View 3 Replies View RelatedI just started learning the basics of programming. While encountering one of the practice problems in the book by Alex Allain I got a little confused. The question is as follows:
Write a menu program that lets the user select from a list of options, and if the input is not one of the options, reprint the list.
The author assumes you can answer this question only using if statements and/or loops (while, for and do).
This is the code I've written thus far:
Code: #include <iostream>
using namespace std;
int main()
{
int option;
char reset;
[Code] ....
For some reason, the nested while loop keeps repeating even when you input a valid option (1, 2 or 3). I can't seem to figure out why this happens.
I wrote this code, and everything was working well, but part of the assignment is that it must include nested loops. Once I added the nested while loop, which is basically an if statement, my life was ruined. I am trying to nest a loop in the code that will basically tell the compiler that if the value "loopVol" were to exceed the value of "final" after adding an increment, to run the program for the "final". How can I do that?
Example:
initial = 10
final = 123
increment = 10
as of now, the program would stop at 120, but I want to nest a loop that will tell the compiler to calculate at the final if this happens.
#include <iostream>
#include <iomanip>
#include <stdio.h>
[Code]......
whats wrong with this code, I'm trying to parse a .js file and replace all the ";" with "; " i.e add a new line after each ";". So I load the file into a char[] buffer then assign a string to this contents of this buffer. Then loop char by char through using an iterator and check for a ";", if found use replace. So int i gets to about 85898 then crashes with unknown error, 'i' should reach about 175653. It does work up till it crashes. And, is this not a simpler way to load a file into a buffer, there is in C.
Code:
#include <iostream>
#include <fstream>
#include <algorithm>
#include <vector>
#include <stdlib.h>
int main()
[code]....
how to display the other half of the box's border? where should i put the printf? or is there any other method that you can show me using arrays?
Code:
#include <stdio.h>
#define ROW 15
#define COLUMN 15
void disp_box (char b[ROW][COLUMN])
[Code].....
For example if we have 101010 First half is 101 which you get by multiplying 101010 * 10 ^-3
now how do you get the second half (010) ??
How do I round to the nearest half integer?
Example;
0 to 0.2 = 0
0.3 to 0.5 = 0.5
0.6-0.9 = 1
What's the formula for C++?
I found a way to do it in math but I want to know what I'd have to put in C++. It's (x*2+.5)remove decimal numbers and divide by 2. What do I put in place of "remove decimal"?
For ex; x = 8.4 using (x*2+.5)remove decimal then divide by 2.
8.4 * 2 = 16.8
16.8 + .5 = 17.3
17.3 - decimal = 17
17/2 = 8.5
I want to do something like;
cout << " Half number: << (x*2+.5)remove decimal/2 << endl;
What would I have to put in place of "remove decimal"?
was making a somewhat of a Binary to Hex convertor but only 10/15 cases work and the non working are in the middle; 0010, 0011, 0100, 0101, 0110, 0111;;
// Test Code.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include <cmath>
#include <conio.h>
using namespace std;
int main(void)
{int A;
cout << "Enter the binary starting with the MSB
[code]....
This is a program to print upper half of the matrix.
#include <iostream>
using namespace std;
int upperhalf(int n, int apu[n][n]) {
cout<<"The upper half of the matrix is :
[Code] ....
the compiler is giving these errors:-
sh-4.2# g++ -o main *.cpp
main.cpp:4:31: error: use of parameter outside fun
ction body before ']' token
int upperhalf(int n, int apu[n][n])
[Code] ....
I dont know where i am wrong.
I am trying solve this a problem: [URL] .....
In short:
1. Input is an N x N grid with a non-negative integer in each cell.
2. We can move from one cell to any of its adjacent cell in all four directions.
3. The 'cost' needed to move from one cell to another is the positive difference of their values.
4. We have to find the minimum cost such that we can visit atleast half of the cells with that cost;
I am not being able to think of any solution that runs in time O(N2) or better (N2 because of the size of N, any algorithm worse than it will not run within the time limit) for this problem.
So I need a hint on how to solve this problem optimally.
What the heck is wrong with my logic? I just print a rectangle!!! I have played with thing for ever it seems. I thought the rotating part would be hard but now I find myself stuck.
Code:
#include <istream>
#include "triangle.h"
using namespace std;
void triangle::create_triangle() {
[Code] ....
I originally had the user input three different lengths and then used this to determine whether or not it was a right triangle.
if(c==sqrt(a*a+b*b)||a==sqrt(b*b+c*c)||b=sqrt(a*a+b*b))
Now it has to be modified in order to accept the input 2,2 4,4 and 6,8(only an example) and be able to find out if it is a right triangle. I was told that arrays were not necessarily the only way to go about it.
I need to find out neighbors of a triangle and loop it over entire unstructured grid. How to do it?. Cell numbers are random so I am unable to loop over all cells.
View 9 Replies View RelatedI intended to compute perimeter of a triangle. The problem is the initial value for the triangle.
#include <iostream>
#include <cmath>
using namespace std;
struct Point{
double x;
double y;
[Code] ......
I expect to get 0 for triangle1, but I get some strange value...
Here is the result
Type x for point1 : 1
Type y for point1 : 1
Type x for point2 : 3
Type y for point2 : 1
Type x for point3 : 1
Type y for point3 : 3
The perimeter of the triangle1 is : 2.82843
The perimeter of the triangle2 is : 6.82843
After trying to understand the problem i finally gave up. The problem requires me to calculate the sum of the biggest numbers in a triangle.
For example: 5
4 0
3 8 2
2 7 9 6
Here is the solved problem from the book(It uses recursion, but i do not get it at all)
#include <iostream>
#include <fstream>
using namespace std;
int triunghi[50][50], n, sum=0;
int suma_max(int i, int j);
[Code] .....
I doesn't give me the same result(26) if a change the order of the numbers in the triangle.
Similar to Pascal’s triangle, the difference triangle has some interesting properties that find applications in various fields of the natural and applied sciences. In simple terms, a difference triangle is a set of integers arranged in an inverted triangle where each inverted triangle triad has its lower element equal to the difference (absolute value) of the two elements in the upper row. A difference triangle can be created from a sequence of integers forming the uppermost row by iteratively taking differences between consecutive terms to form the next row until a single-element row is created.
Example Consider the sequence 5, 8, 13, 21, 34, 55 from the Fibonacci series as the uppermost row of the difference triangle. The difference between successive elements form a new set: 3 (= 8 – 5), 5 (= 13 – 8), 8 (= 21 – 13), 13 (= 34 – 21), and 21 (= 55 – 34). The process can then be repeated until there is only one element left giving the following difference triangle:
5 8 13 21 34 55
3 5 8 13 21
2 3 5 8
1 2 3
1 1
0
Problem Write a program that forms a difference triangle using a given series of numbers as topmost row.