Getting close but I think I am stuck on the second loop. The input you put in will be doubled (and it's not supposed to).
Code:
int main() {
int n, i, j, k;
printf("What would you like the height to be? (Positive odd integer)
");
scanf("%d", &n);
[Code] .....
I feel as if I'm so close and I'm just messing up a value somewhere, but I am at a loss as to what I should change. Here is my code:
#include "stdafx.h"
#include <iomanip>
#include <iostream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[]) {
[Code] ....
What output would you expect from this program?" The output was not what I expected. I've psuedo-coded this out and I'm still missing something.
Code:
#include <stdio.h>
int main () {
int numbers[10] = { 1, 0, 0, 0, 0, 0, 0, 0, 0, 0 };
int i, j;
}
[code]....
The output: Code: 1 1 2 4 8 16 32 64 128 256 So when I look at this first loop I see that j = 0, which is less than 10, so then the program statement should commence, which is another for loop. So in this inner for loop I see that i = 0, which is not less than j, so this loop should terminate. Then the value of j increments by 1 and the first go around of the loop has completed.
Now I see that j = 1, so this is less than 10, and the inner for loop commences once again. This time though, i actually is less than j, so numbers[1] = numbers[1] + numbers [0], or numbers[1] = 0 + 1. Now the value of i is incremented by 1 and the first go around of this inner loop has completed. Then the value of j increments by 1 and another go around of that loop has completed.
So now j = 2, i = 1, and numbers[2] ( which is 0 ) = numbers[2] + numbers[1], or numbers[2] = 0 + 1. I was expecting the output to be an array full of 1's. However this is not the case..
Howi can made nested loops?
Code:
for (yax=0; yax<10; yax=yax+1) {
for (xax=0; xax<100; xax=xax+1) {
printf("%d
",yax);
}
}
way what i tired dont work. or maybe works but why this prints only zeros ?
So in class our teacher assigned us a program where we have to use nested for loops to creates triangles. How does the 2nd for loop print more than 1 star? since the for loop will only run the cout 1 time until it gets to the escape sequence, how does it print more than 1 star on a line? this is what is confusing me. I feel like if i can grasp the understanding of that and what the for loops are doing i can finish the rest of this program with ease
#include<iostream>
using namespace std;
int main()
[Code].....
The user will enter the number of '*'s on the 1st row (ntop) and then the number of rows forming the trapezoid (nrows). (using <iostream>, cout)
For instance, an inverted trapezoid with 7 '*"s in the 1st row and 3 rows forming the inverted trapezoid looks like:
1*******
2 *****
3 ***
(this pyramid is centered, in case it isnt when its posted). Also, each descending row has two less asteriks than the above row.
I am having trouble with the four loop displaying the number of "*" and " ". I know its a relationship with variables in the for loops, my output is just never doing what i want it to.
THis is the guideline for the for loop:
Use for loops to display the inverted trapezoid. Your outer for loop will iterate the total number of rows times. For each row use one nested for loop to display blanks (the 1st row contains no blanks) and another nested for loop to display the characters '*'.
Heres my for loops so far:
for (i = nrows; i >= 1; i--) {
for (j = 0; j >= nrows; j++) {
cout << " ";
} for (k=ntop; k >= 2; k--) {
cout << "*";
} }
The ouput is just blank as of now.
The output should be something like:
5
45
543
5432
54321
Write a program that prints a multiplication table using nested loops. In main ask the user for the smallest column number , the largest column number and the size of the increment. Ask the user for the same information for the row values.
In the example the column values entered are: 5, 15 and 2 and the row values 3, 6 and 1.
Given those numbers you would generate the following table.
Multiplication Table
| 5 7 9 11 13 15 ___|___________________________________ | 3 |
15 21 27 33 39 45 4 | 20 28 36 44 52 60 5 | 25 35 45 55 65 75 6 | 30 42 54 66 78 90
Print the 24 values with the grey background. The other numbers show the values to be multiplied.
Code:
#include<stdio.h>
main() {
int a,b,c,d,e,f;
int i,j,total;
printf("Please enter smallest column number: ");
scanf("%i",&a);
printf("
[Code] ....
Challenge:
As an added challenge try to print out the column
headings (5 7 9 11 13 15) and the row headings (3 4 5 6)
For each quarter, calculate and display the beginning principal balance, the interest earned, and the final principal balance for the quarter.For example: The user entered 1000.00 for the beginning principal balance, 5.25 for the interest rate, and 8 for the number of quarters. The output from this part of the program should be similar to the following:
Q| Beginning Principle| Interest Earned| End Principle
1| $1,000.00 | $13.13 | $1,013.13
2| $1,013.13 | $13.30 | $1,026.42
3| $1,026.42 | $13.47 | $1,039.89
etc
Here is the code I have so far, and I just am not quite sure where to go next.
Code:
{
cout << "Quarters" << " " << "Beginning Principles" << " " <<"Interest Earned" << " " <<"End Principal" << endl;
endprin = balance + (quarter * interest);
interest = quarter * interest;
cout << endprin << endl;
}
This is a test program that takes a number of arguments from the command prompt and concatenates them into a string object. I was looking into the possibility of using the range-based for loop for this purpose. Can it be done with pointer based arrays? I am mainly doing this because I want to have a firm understanding of range-based for, but also would like to do this with least amount of code possible.
This is my working program:
#include <string>
#include <iostream>
int main(int argc, char *argv[]) {
if (argc > 1) {
std::string concatenatedArgs;
[Code] ....
Can I somehow replace my while-loop with a range-based for? I tried the following but the compiler points out that begin and end were not declared in the scope of the range-based for loop.
#include <string>
#include <iostream>
int main(int argc, char *argv[]) {
if (argc > 1) {
std::string concatenatedArgs;
[Code] ....
Have an assignment due in a few weeks and I'm 99% happy with it My question is is there a method or process for reducing redundant code in nested loops. Ie my code compiles and runs as expected for a period of time and after a few goes it omits a part or prints an unexpected out ext so basically how to find when the redundancy occurs with out posting my code so I can learn for my self?
View 3 Replies View Relatedwrite a code that draw a block and diamond each in a single run by using '*' in recursion.
Below are one 10X10 rectangle and 6X4 diamond.
**********
**********
**********
**********
**********
**********
**********
**********
**********
**********
**
* *
* *
* *
* *
* *
* *
* *
**
Note: I couldn't write the diamond here appropriately somehow.
I have been tasked with making a diamond out of asterisks based on a given odd integer input. For some reason the bottom half of my diamond will not print. I'm not sure as to why.
Here is my code:
#include "stdafx.h"
#include <iomanip>
#include <iostream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[]){
[Code] ....
#include <iostream>
using namespace std;
int main(){
return 0;
}
this is my main functions. I have problem making a program that prints in asterisks an oval, arrow and a diamond using for loop and if statements.
I wrote this code, and everything was working well, but part of the assignment is that it must include nested loops. Once I added the nested while loop, which is basically an if statement, my life was ruined. I am trying to nest a loop in the code that will basically tell the compiler that if the value "loopVol" were to exceed the value of "final" after adding an increment, to run the program for the "final". How can I do that?
Example:
initial = 10
final = 123
increment = 10
as of now, the program would stop at 120, but I want to nest a loop that will tell the compiler to calculate at the final if this happens.
#include <iostream>
#include <iomanip>
#include <stdio.h>
[Code]......
I encounter this from a library:
( *(reg8 *)(pinPC) |= CY_PINS_PC_DATAOUT)
From my understand the cast (reg8 *) applies to the result of the bitwise OR. But what is the left most asterisk doing?Is it just dereferencing the casted pointer?
i have to make a programs that prompts the user to enter quiz grades and add them up. For examples the user enters 6 test grades they are out of 5 so he enters 0-5 and i store them in the array. This part works great but now i have to print out a bar of vertical asterisks for every part too. So if at the end we have one test grades that are 2 grades of 1 points, 1 grade of two point, 2 grades of three point and 1 grade of 5 point it will have to display them as this
There are 2 grades of 1
There are 1 grades of 2
There are 2 grades of 3
There are 1 grades of 5
i need to do for loops but i am stuck on what to count too and what to print i know i will need cout << "*" and a couple of spaces.
#include <iostream>
using namespace std;
int main (){
int size;
int tests;
int a[6]={0};
cout << "How many quiz scores will you enter: ";
cin >> size;
[code]....
i have my basic C program here (i'm new to C language):
Code:
#include <stdio.h>
int main()
{
int grade;
int A=0;
int B=0;
int C=0;
int D=0;
int E=0;
[Code]....
As you can see, it's only for counting how many students got the grades from A to E, but the problem is that i need to change it from numbers into asterisk
for example: 4 students got the grade A, and 3 students got the grade B
instead of displaying
A=4
B=3
i want it to display
A=****
B=***
Code:
#include <iostream>
#include <string>
using namespace std;
int main()
[Code] ....
I have to place two asterisk triangles on top of each other BUT only using 3 for statements. I have gotten the first one:
for(int a=1;a<=10;a++) {
for(int b=1;b<=a;b++)
cout << "*";
cout << endl;
}
I need the output to look like this:
*
**
***
****
*****
******
*******
********
*********
**********
*
**
***
****
*****
******
*******
********
*********
**********
The only kicker is I can have a total of 3 nested for loop statements.
void Log_In() {
system("cls");
gotoxy(30, 30);
time_t now;
time(&now);
[Code] .....
How to produce a password field with asterisk ****** .....
The assignment is to plot the functions, by implementing a function having the following prototype:
void plotPoint(double y);
This function should print a single "*" symbol, in a position determined by the value of y, and then a newline. The position of the * symbol can span over 80 columns: each column should represent a delta of length 0.1 in the value of y, and the zero should be placed on the 40-th column.
For example:
• placePoint(0) should print the * symbol on the 40th column
• placePoint(0.1) should print the * symbol on the 41st column
• placePoint(1) should print the * symbol on the 50th column
• placePoint(-1) should print the * symbol on the 30th column
Here is what I have so far:
#include <iostream>
#include <cmath>
int a;
int b;
int x;
int y;
int Func1(double a, double b )/>
[Code] ....
I'm lost now as to where to go to plot. I know that depending on the option chosen I call the corresponding function to return a value for y which is just then plugged into a function to plot it on columns of y.
So, I'm going to write a recursive function for a asterisk pattern but I'm stuck figuring out how to create a stopping case for it, better yet, I'm unable to describe the pattern completely.
*
**
-*
****
--*
--**
---*
********
-----*
-----**
------*
-----****
-------*
-------**
--------*
( - represent white spaces )
What I've been thinking:
* Every odd row has 1 * with 1 incremented white space
* Every "pair" of asterisks equals 8 total (EX. 8 one pair *'s, 4 two pair *'s, 2 four pair *'s)
Unfortunately, that's all I got. how I can represent this as I function. Once I figure out what my stopping case should be, I think I can do the coding on my own.
When i try to compile this code it gives me a error during run-time saying "*program name* has stopped working"
Code:
#include <iostream>
#include <memory>
using std::cout;
using std::endl;
using std::unique_ptr;
[Code] .....
Why is this happening? Also why do you need the asterisk on smart pointers to assign them a value? Is it just because, or is there a reason.
This program needs to display a vertical graph of asterisks showing production for each plant in the company ...
Here is what I have so far:
***********************************
This program will read data and
display a vertical graph showing
productivity for each plant.
Reference Display 7.8 pg. 401-3
***********************************
*/
#include <iostream>
[Code].....
#include<stdio.h>
#include<conio.h>
#include<string.h>
char str1[20], str2[20]="kent";
main() {
printf("Enter your Username: ");
scanf("%s",str1);
[Code] ...