C :: How To Change The Numbers Into Asterisk

Oct 10, 2014

i have my basic C program here (i'm new to C language):

Code:

#include <stdio.h>
int main()
{
int grade;
int A=0;
int B=0;
int C=0;
int D=0;
int E=0;

[Code]....

As you can see, it's only for counting how many students got the grades from A to E, but the problem is that i need to change it from numbers into asterisk

for example: 4 students got the grade A, and 3 students got the grade B

instead of displaying

A=4
B=3

i want it to display

A=****
B=***

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Code:
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int main()

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I encounter this from a library:

( *(reg8 *)(pinPC) |= CY_PINS_PC_DATAOUT)

From my understand the cast (reg8 *) applies to the result of the bitwise OR. But what is the left most asterisk doing?Is it just dereferencing the casted pointer?

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Feb 12, 2014

i have to make a programs that prompts the user to enter quiz grades and add them up. For examples the user enters 6 test grades they are out of 5 so he enters 0-5 and i store them in the array. This part works great but now i have to print out a bar of vertical asterisks for every part too. So if at the end we have one test grades that are 2 grades of 1 points, 1 grade of two point, 2 grades of three point and 1 grade of 5 point it will have to display them as this

There are 2 grades of 1
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There are 2 grades of 3
There are 1 grades of 5

i need to do for loops but i am stuck on what to count too and what to print i know i will need cout << "*" and a couple of spaces.

#include <iostream>
using namespace std;
int main (){
int size;
int tests;
int a[6]={0};

cout << "How many quiz scores will you enter: ";
cin >> size;

[code]....

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Jul 11, 2013

Getting close but I think I am stuck on the second loop. The input you put in will be doubled (and it's not supposed to).

Code:
int main() {
int n, i, j, k;
printf("What would you like the height to be? (Positive odd integer)
");
scanf("%d", &n);

[Code] .....

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I have to place two asterisk triangles on top of each other BUT only using 3 for statements. I have gotten the first one:

for(int a=1;a<=10;a++) {
for(int b=1;b<=a;b++)
cout << "*";
cout << endl;
}

I need the output to look like this:
*
**
***
****
*****
******
*******
********
*********
**********
*
**
***
****
*****
******
*******
********
*********
**********

The only kicker is I can have a total of 3 nested for loop statements.

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The assignment is to plot the functions, by implementing a function having the following prototype:

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This function should print a single "*" symbol, in a position determined by the value of y, and then a newline. The position of the * symbol can span over 80 columns: each column should represent a delta of length 0.1 in the value of y, and the zero should be placed on the 40-th column.

For example:
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• placePoint(0.1) should print the * symbol on the 41st column
• placePoint(1) should print the * symbol on the 50th column
• placePoint(-1) should print the * symbol on the 30th column

Here is what I have so far:

#include <iostream>
#include <cmath>
int a;
int b;
int x;
int y;
int Func1(double a, double b )/>

[Code] ....

I'm lost now as to where to go to plot. I know that depending on the option chosen I call the corresponding function to return a value for y which is just then plugged into a function to plot it on columns of y.

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So, I'm going to write a recursive function for a asterisk pattern but I'm stuck figuring out how to create a stopping case for it, better yet, I'm unable to describe the pattern completely.

*
**
-*
****
--*
--**
---*
********
-----*
-----**
------*
-----****
-------*
-------**
--------*

( - represent white spaces )

What I've been thinking:

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Unfortunately, that's all I got. how I can represent this as I function. Once I figure out what my stopping case should be, I think I can do the coding on my own.

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Code:
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#include <memory>
using std::cout;
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using std::unique_ptr;

[Code] .....

Why is this happening? Also why do you need the asterisk on smart pointers to assign them a value? Is it just because, or is there a reason.

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Code:
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***********************************
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Example:

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