ignoring negative numbers when I am trying to add up only positive numbers.
SAMPLE:
if (num>=0) {
sum= sum + num;
}
else
how would the else in this case being a negative number not be included in the sum
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
View 4 Replies View Related#include <iostream>
using namespace std;
int initialization (int []);
int identifying (int [],int);
[Code].....
im supposed to create a program that reads in a list of integers from the terminal and writes the negative numbers to one file and the positive numbers to another file.
i got most of it doen but for some reason its not writting the negative numbers. on what im doing wrong?
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(){
int pos_num = 0;
int neg_num = 0;
int positive_numbers = pos_num % 5;
[Code]...
I am trying to average the negative numbers and positive number and of course the total average.
This will read in a list of n values, where n is not known ahead of time. The number of values read into the array will be saved in n.
vector<int> readList() {
std::vector<int> result;
ifstream inFile;
inFile.open("setA.txt");
for (int x; inFile >> x; ) {
result.push_back(x);
[code]....
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) {
int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0;
for (auto i : array) {
sum += i;
if (i > 0) { pos_sum += i; ++pos_count; }
[code]....
Write a program which reads a stream of numbers from a file, and writes only the positive numbers to a second file. The user should be prompted to enter the names of both the input file and output file in main(), and then main() will open both files. Another function named process() must then be called to read all the numbers from the input file and write the positive numbers to the output file. Note that you must pass the open stream variables for each file as arguments to the process() function, and that you need to (always) double check that the files opened successfully before using them.
This is what I have so far but its not working out!
#include <iostream>
#include <fstream>
#include <stdlib.h>
using namespace std;
int process(ifstream &inf, ofstream &outf);
[Code] ....
I need to ignore negative values in an array, but not exit the function.
For example if the user enters:
1,2,3,4,-1,-2,0
the array would be
[1,2,3,4]
Is there a way to ignore these values?
I have a program where the user inputs a line of numbers, and the two highest ones are displayed. It works fine, until negative values are entered at which point it shows 0 as the result.
Code: #include <iostream>
using namespace std;
int main( ) {
int num = 0;
int highest = 0;
[Code].....
I have task to make program.. To enter 10 positive numbers in an array. Find three numbers that stand near each other and that have the maximum sum.
I understand how to make array, enter 10 number i find only one biggest number from 10.. How to find three max number sum that stand near each other..
I am having an error at line 21. Specifically the code where it says "list[num]=x"
How am I able to fix this code to do what I want? The purpose of my program is to enter in positive numbers in an array (and having it end when 0 is typed) My program also accepts negative values but will ignore them when it is outputted. I believe I have all the code right except for line 21.
#include<iostream>
using namespace std;
const int ARRAY_SIZE(25);
void read_list(const int list[],const int ARRAY_SIZE);
int main() {
int list[ARRAY_SIZE];
read_list(list, ARRAY_SIZE);
[Code] ....
So i have this program that takes in user input and stores them into an array and then prints them, removes duplicates, and sorts in ascending order. The user can also stop by inputting a sentinel value (in this case -1). But i am also supposed to ignore any negative value besides -1. When i input any other negative value into the program it messes up. How would i go about ignoring the negative values?
Code:
#include<stdio.h>
int main()
{
int input, nums[20], i, j, k, temp, count=0, count2=0;
for(i=0;i<20;i++)
[Code] .....
I've been working on this program to create a simple desk calculator for a school assignment, and I managed to finish. All we had to do was add, subtract, multiply, and divide positive integers - and I was able to do that just fine. This program got me thinking though, because I do not know how to write commands to multiply/divide negative numbers.
In fact, when I divide a number like 21 by 4, it comes out to 5 because I don't know how to allow it to compute remainders (which wasn't a requirement for my program). This intrigued me so I've been trying to figure it out for the last few days but to no avail. Here's my code:
Code: void flush_buffer(){
int ch;
while ((ch = getchar()) != '
' && ch != EOF);
[Code]....
And just know that my code works perfectly fine, I'm not here for troubleshooting it. I just want to know what I can change to allow negative values to be correctly computed.
I have a homework assignment due that told me for the "input specification" that "n" is an integer greater then 0. How would I put this in and where?
View 1 Replies View RelatedI am reading one of the exercise solutions for C Programming Language: The C Programming Language Exercise 3-4
In it, it states that negative numbers are biased by (2^n - 1) (i.e. -I is represented by (2^n - 1) - (+I). So:
Code:
Bias = 2^8 - 1 = 255 = 11111111
Subtract 25 = 00011001
Equals = 11100110
what is meant by the "bias" here and what is the value of "I" here. It just suddenly uses "I" without explaining what it is.
Ok well i know that isdigit in my code is seeing the negatives as a character and so i made my program give an error message. But i need negative numbers to work how could i get this to work with negative numbers.
The code is supposed to add the 3 numbers input into the command line argument including negative numbers.
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
int main(int argc, char *argv[]){
int add=0;
int i;
[Code] ...
Write a function that raises an integer to a positive integer power. Call the function x_to_the_n taking two integer arguments x and n. Have the function return a long int, which represents the results of calculating x^n.Here's my code:
Code:
#include <stdio.h>
long int x_to_the_n(int x, int n)
{
int i;
long int acc = 1;
for(i = 1; i <= n; ++i)
acc *= x;
}
[code]...
It compiles OK, but when I run it the program stops after entering the number (x) and power (n).
Example input: 2 4 6 -1 7 3 -2 1
Output: 3 3 (longest series of even is 3, longest series of positive is 3)
Here is the code:
Code:
#include <stdio.h>
int even(int x) {
return x % 2 == 0;
}
int positive(int x) {
return x>0;
[Code]...
My question is how to write this code if the prototype of function is:
Code: void series(int *array, int n, int (*s)(int), int **begining, int *lenght);
program:
Example input: 2 4 6 -1 7 3 -2 1
Output: 3 3 (longest series of even is 3, longest series of positive is 3)
Here is the code:
#include <stdio.h>
int even(int x) {
return x % 2 == 0;
}
[Code].....
My question is how to write this code if the prototype of function is:
void series(int *array, int n, int (*s)(int), int **beginning, int *length);
I have a error with one of my programs. I'm supposed to get rid of negative numbers when there are numbers that are randomly generated. Here is the middle part of the code.
{
int vectorLength = 10;
vector<int> bothSigns(vectorLength);
cout << " Input vector: ";
for (int i = 0; i < vectorLength; i = i + 1)
{ bothSigns[i] = rand()%201 - 100;
[code] .....
The part where i'm supposed to start is after the /////'s. However, whenever I input a number for the random numbers(not put in part of code), i keep getting a segmentation error.
I have to write a program that uses negative numbers in a conjecture algorithm. The program terminates when a number is reached that was already outputted. I can not get it to work and I have been racking my brain for a week.
#include <iostream>
using namespace std;
int main() {
int x[1000], y[1000], i=0, j=0, count=0, w=0, z[1000], t = 0;
[code]....
Write a program asks the user for a positive integer value and then prints out all perfect numbers from 1 to that positive integer. I have been trying for some time, i found a way to check if its a perfect number or not but could not find a way to prints out all perfect numbers from 1 to that positive integer. I am here so far.
#include<iostream>
#include<iomanip>
using namespace std;
int main(){
int n,i=1,sum=0;
cout<<"Enter a number: ";
[Code] ....
I having some issues with two different programs here... One of them crashes and returns random negative numbers whenever it reaches a "fscanf" function and the other displays a "Polink fatal error: access denied" error.
Code:
/* Evan Wentz */
/* Pike - ET2560 */
#include <stdio.h>
#define MAX_ACCTS 100
int accounts [];
double balances [];
[Code] ....
I thought the reason this kept crashing before was because I didn't type the data into the text file it was writing too correctly, but I made another program to do that, and it crashed whenever it got to fprintf. Program works perfect besides the file stuff...
I got the while loop right... but how do i write the minimum and max to get negetive numbers like -88....
Code:
#include <stdio.h>#include <math.h>
#include <conio.h>
int gcd(int, int);
int main() {
int x, y, min, max, result, power, flag = 1;
char c;
[Code] ....
#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
[Code] ....
This program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers.
Write a program that calculates the average of a stream of positive numbers. The user can enter as many positive numbers as they want, and they will indicate that they are finished by entering a negative number. For this program, treat zero as a positive number, i.e., zero counts as a number that goes into the average. Of course, the negative number should not be part of the average. You must use a function to read in the numbers, keep track of the running sum and count, compute the average, and return the average to the main() function. Note that you must use a loop to do this, as you don't know how many numbers the user will enter ahead of time. I am having problem writing a loop program for it..
View 1 Replies View RelatedThe Program must allow users to enter any two positive numbers and then display the results.
#include <iostream>
using namespace std;
class ArithmeticOperators{
private:
int x;
int y;
public:
void set_values();
[Code] .....