I got the while loop right... but how do i write the minimum and max to get negetive numbers like -88....
Code:
#include <stdio.h>#include <math.h>
#include <conio.h>
int gcd(int, int);
int main() {
int x, y, min, max, result, power, flag = 1;
char c;
[Code] ....
I just wanted to ask the reason that why is the below code not checking the case -1 while working for the other case values.
#include<stdio.h>
#include<conio.h>
int main() {
int i=-1;
switch(i-2) {
[Code] ....
So why in the below code the case -1 doesnt run,when the value evaluated by the switch construct is actually a negative integer constant.
im supposed to create a program that reads in a list of integers from the terminal and writes the negative numbers to one file and the positive numbers to another file.
i got most of it doen but for some reason its not writting the negative numbers. on what im doing wrong?
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(){
int pos_num = 0;
int neg_num = 0;
int positive_numbers = pos_num % 5;
[Code]...
If I have an integer variable like int a=9 then in the switch case If i write :
switch(a) {
case 4+a: printf("hii");
}
Then why is this statement a compile-time error that variables cannot be used inside a case statement why does the compiler not subtitutes the values in place of the variables.
Place the even lucky numbers in an array called evenList, the odd lucky numbers in an array called oddList, and the negative lucky numbers in an array called negList.
//So in main main i passed the array as parameter and the size;
void lucknumberlist(int favnum[], int size) {
int even = 0, odd = 0, neg = 0;
int evenArray[even];
int oddArray[odd];
int negArray[neg];
if(favnum[even] % 2 == 0) {
evenArray[even] = favnum[even];
[Code] .....
ignoring negative numbers when I am trying to add up only positive numbers.
SAMPLE:
if (num>=0) {
sum= sum + num;
}
else
how would the else in this case being a negative number not be included in the sum
I'm using a dev c++ bloodshed compiler. How can we write a menu using switch statement?
View 1 Replies View RelatedI'm trying to write a program that has a menu with a switch statement. I'm getting "case label'1' not within a switch statement" and subsequent errors for the other two choices and the default.
int main(){
int choice;
Matrix A,B,C;
cout <<"What would you like to do? "<< endl;
[Code]....
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
float rate, hours, overtime, tax_calculated;
float tax = .15;
[Code] ....
I have a program where the user inputs a line of numbers, and the two highest ones are displayed. It works fine, until negative values are entered at which point it shows 0 as the result.
Code: #include <iostream>
using namespace std;
int main( ) {
int num = 0;
int highest = 0;
[Code].....
So i have this program that takes in user input and stores them into an array and then prints them, removes duplicates, and sorts in ascending order. The user can also stop by inputting a sentinel value (in this case -1). But i am also supposed to ignore any negative value besides -1. When i input any other negative value into the program it messes up. How would i go about ignoring the negative values?
Code:
#include<stdio.h>
int main()
{
int input, nums[20], i, j, k, temp, count=0, count2=0;
for(i=0;i<20;i++)
[Code] .....
I've been working on this program to create a simple desk calculator for a school assignment, and I managed to finish. All we had to do was add, subtract, multiply, and divide positive integers - and I was able to do that just fine. This program got me thinking though, because I do not know how to write commands to multiply/divide negative numbers.
In fact, when I divide a number like 21 by 4, it comes out to 5 because I don't know how to allow it to compute remainders (which wasn't a requirement for my program). This intrigued me so I've been trying to figure it out for the last few days but to no avail. Here's my code:
Code: void flush_buffer(){
int ch;
while ((ch = getchar()) != '
' && ch != EOF);
[Code]....
And just know that my code works perfectly fine, I'm not here for troubleshooting it. I just want to know what I can change to allow negative values to be correctly computed.
I have a homework assignment due that told me for the "input specification" that "n" is an integer greater then 0. How would I put this in and where?
View 1 Replies View RelatedI am reading one of the exercise solutions for C Programming Language: The C Programming Language Exercise 3-4
In it, it states that negative numbers are biased by (2^n - 1) (i.e. -I is represented by (2^n - 1) - (+I). So:
Code:
Bias = 2^8 - 1 = 255 = 11111111
Subtract 25 = 00011001
Equals = 11100110
what is meant by the "bias" here and what is the value of "I" here. It just suddenly uses "I" without explaining what it is.
#include <iostream>
using namespace std;
int initialization (int []);
int identifying (int [],int);
[Code].....
Ok well i know that isdigit in my code is seeing the negatives as a character and so i made my program give an error message. But i need negative numbers to work how could i get this to work with negative numbers.
The code is supposed to add the 3 numbers input into the command line argument including negative numbers.
#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
int main(int argc, char *argv[]){
int add=0;
int i;
[Code] ...
I have a error with one of my programs. I'm supposed to get rid of negative numbers when there are numbers that are randomly generated. Here is the middle part of the code.
{
int vectorLength = 10;
vector<int> bothSigns(vectorLength);
cout << " Input vector: ";
for (int i = 0; i < vectorLength; i = i + 1)
{ bothSigns[i] = rand()%201 - 100;
[code] .....
The part where i'm supposed to start is after the /////'s. However, whenever I input a number for the random numbers(not put in part of code), i keep getting a segmentation error.
I have to write a program that uses negative numbers in a conjecture algorithm. The program terminates when a number is reached that was already outputted. I can not get it to work and I have been racking my brain for a week.
#include <iostream>
using namespace std;
int main() {
int x[1000], y[1000], i=0, j=0, count=0, w=0, z[1000], t = 0;
[code]....
I having some issues with two different programs here... One of them crashes and returns random negative numbers whenever it reaches a "fscanf" function and the other displays a "Polink fatal error: access denied" error.
Code:
/* Evan Wentz */
/* Pike - ET2560 */
#include <stdio.h>
#define MAX_ACCTS 100
int accounts [];
double balances [];
[Code] ....
I thought the reason this kept crashing before was because I didn't type the data into the text file it was writing too correctly, but I made another program to do that, and it crashed whenever it got to fprintf. Program works perfect besides the file stuff...
#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
[Code] ....
This program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers.
I'm working on a code that needs to loop a switch case back to the beginning after a certain input is entered.
ex) Code:
printf("Select an option);
printf("1. Play game");
printf("2. Status");
printf("3. Exit");
scanf("%i", &userinput);
switch(userinput);
[Code]...
For my program, I want option 2 to display something, then loop back to "select and option" after the user presses enter. How would I write that? Would i use a while? do while?
Basically I'm supposed to use a while loop to generate a random number and use a switch statement to output the appropriate information. I feel like I'm missing a few things that are very simple.
The errors are:
warning C4244: 'argument' : conversion from 'time_t' to 'unsigned int', possible loss of data
warning C4700: uninitialized local variable 'randomNumber' used
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
using namespace std;
int main(){
int i = 0;
unsigned int randomNumber;
[Code] .....
I have a hit a snag in a number guessing game program. I was given a half-completed program and told to use functions to complete the missing pieces. It looks unwieldy, but this is how it is supposed to be. I have temporarily made the random guess value visible for troubleshooting purposes.
#include <iostream>
#include <time.h>
#include <stdlib.h>
using namespace std;
int welcome() {
cout << " Welcome to the hi-low game!" << endl;
[code]....
The issue lies within this piece of code:
checkGuess(guess, correct); done = false; //either true or false
} while (!done);
cout << "Congratulations, you got it!" << endl;
return 0;
}
I need to manipulate the Boolean variable done so that it registers as false when the user inputs a number higher or lower than the randomly selected value. However, if the user guesses correctly, done will become true and the program will end.
As it stands now, the program will not terminate, and if I set done equal to true like so:
checkGuess(guess, correct); done = true; //either true or false
} while (!done);
cout << "Congratulations, you got it!" << endl;
return 0;
}
Every number the user inputs will register as correct instead of the one right guess.
I have a problem with my simple operations calculator code (using C, in Code::Blocks). I am required to use a while loop statement so the user can execute multiple step operations without re-opening the program. When I launch the program, I get through the first session fine, but when I'm on the second session, when entering the two operands and press enter (to calculate), it just gives me the return and say press any key to continue (exit).Here is the code:
Code:
# include <stdio.h>
int main()
{
int num1, num2;
char op;
int finished = 0;
}
[code]....
I'm trying to create a simple calc program that does all the elementary calculations. How to get it to add and multiply continuously without crashing. but now i need to figure out how to ask the user if they want to continue or not. I'm having trouble here because in the while statement i have a scanf which asks for the operator symbol. and then asks for number in the second scanf..
So basically a user would have to enter 'R' twice for the message to pop up! Also i'm not sure how i would quite the program if they put in a 'N' for no. would return 0; work? What if they press 'Y' for yes, what would the return have to be then?
Here's a snippet of the code
int main () {
double result;
double new_number;
char symbol;
result = 0;
while(1==scanf(" %c", &symbol) && symbol == 'R' && symbol =='r')
[Code] .....
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
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