C :: Simple Multi-Session Calculator / Switch Case And While Loop
Jun 30, 2013
I have a problem with my simple operations calculator code (using C, in Code::Blocks). I am required to use a while loop statement so the user can execute multiple step operations without re-opening the program. When I launch the program, I get through the first session fine, but when I'm on the second session, when entering the two operands and press enter (to calculate), it just gives me the return and say press any key to continue (exit).Here is the code:
Code:
# include <stdio.h>
int main()
{
int num1, num2;
char op;
int finished = 0;
}
I'm working on a code that needs to loop a switch case back to the beginning after a certain input is entered.
ex) Code:
printf("Select an option); printf("1. Play game"); printf("2. Status"); printf("3. Exit"); scanf("%i", &userinput); switch(userinput);
[Code]...
For my program, I want option 2 to display something, then loop back to "select and option" after the user presses enter. How would I write that? Would i use a while? do while?
I am trying to make a program which manages the data of 5 different patients (its an uni assignment), and i want to use a switch case as a menu to switch between the patients. All other functions (as for example putting the infromation on a file) work, but i cant figure out to bring the switch to work. First it asks for the number of the patient which should be worked with, this works perfectly, but afterwards changiung between the persons doesnt work as thought. It should ask everytime after it switches to one patient (i removed some functions to make it easier to read) and then asks to which it should jump next. If i put the number of one case (lets say 3) it just stops the program.
********Example: user@pc ~/wherever $ ./program current variables: jo = 2 a = 0 1 //the entered number The variable a = 1 patient 1 Enter the number of the next patient2 // and then it closes **************
The same thing happens if i compile an example code from a book, it writes the first case and then stops.
I looked already through the forum but didnt find a person with a similar problem, maybe i didnt dig deep enough.
I am running Linux Mint 17 and use gcc as compiler.
Code:
include <stdio.h> #include <stdlib.h> int a=0; int jo=2; int main(void){ printf("current variables: jo = %d a = %d
Ran into something today that does not make sense:
This compiles: Code: int x = 5;
switch(x) { case 0: { int value = 5; } break;
[Code] ....
Ok so it doesn't like int value = 6 b/c of int value = 5 for case 0. However since the value in case 0 is declared within the brackets one would think it has case scope.
So I tried this:
Code: int x = 5; switch(x) { case 0: { int value = 5; } break;
[Code] ....
Now it doesn't like it b/c value has not been declared in case 1:. These two conditions cannot possibly be both true at the same time. You cannot disallow the declaration of value in case 1 b/c it interferes with value in case 0 and at the same time disallow me to use value from case 0 b/c it is not in scope. If it was not in scope then theoretically I should be able to declare value in case 1.
Both MSVS 2012 and 2013 exhibit the same behavior. I checked the standard and it is unclear on the matter.
Im going through a C tutorial and im going to create a Database as part of the course. Im just in the very beginning of the project so its a very simple program so far.
Code:
#include<stdio.h> main(){ /*Variabler for att lagra information om skiva*/ char title[200]; char artist[100]; int tracks; int price;
[Code] ....
The first switch case statement takes me to the menu of choice, 1 or 2. However, chosing menu option one and trying to input a title or artist name, the program crashes.
Next, going into menu option 2 and then trying to print out, for example, title nothing happend. The process just ends.
Again, im sure this simple prototype is full of errors ....
I was just wondering if a switch statement can work without writing each case, for instance:
{ int age; age=18; while (age!=0) { cout<<"Enter age :"<<endl; cin>>age; switch (age) {
[Code] ....
It works only for values specifically entered as a case, for instance if you enter 5 or 15 , it says bicycle, but if you enter anything inbetween it goes to default. Same with 18 and 100. It can't possibly be that you have to enter
case 19: case 20: case 21: case 22:.......up to 100 to include all possible cases.
I'm trying to convert the enum type {PG, R, G, PG-13, etc.} to strings so i can use it in cout statement but no matter what i put inside switch(), the compiler keeps saying Error: expression must have integral or enum type. What am I doing wrong exactly?
Movie covert_rating(Movie r) { switch (r) { case PG: return "PG"; break; case R: return "R";
I tried to write a menu program as a switch-case structure with a separate function for a switch-case structure itself. The outcome for it currently is an undesired one
Code:
#include <iostream> using namespace std; int menu(int answer); int main()
[Code].....
The output I get is one where it's just an infinite loop of "Bad choice! Please try again later.".
was making a somewhat of a Binary to Hex convertor but only 10/15 cases work and the non working are in the middle; 0010, 0011, 0100, 0101, 0110, 0111;;
// Test Code.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <cmath> #include <conio.h> using namespace std; int main(void) {int A; cout << "Enter the binary starting with the MSB
#include <stdio.h> int main () { int num; char choice; printf(" Welcome to a Menu-Demo Program Please select one of the following actions R - Programmers Rock! F - Programming is Fun! G - Geeks Rule! X - Exit program Selection ==>__ "); do{ choice = getchar(); switch(choice)
[code]......
I am currently writing a simple program that utilizes switch statements. When I run my program, it always displays the message for the default case.
If I have an integer variable like int a=9 then in the switch case If i write :
switch(a) { case 4+a: printf("hii"); }
Then why is this statement a compile-time error that variables cannot be used inside a case statement why does the compiler not subtitutes the values in place of the variables.
The basics of the program is that:It will ask the user whether they want to: Pop, Push , Peek or Exit the program.
When it comes to the Exit case: how do so( tried exit(1) & exit(0) using the internet hasn't brought me much luck either. I am getting these two errors also:
"Error LNK2019 : Unresolved external symbol "int_cdcel peek(void)" (?peek@@YAHXZ)"
Each applying to the functions below.
"Error LNK1120: 3 Unresolved Externals"
I'm not sure their is much more I can say about the problem.
Code:
#include "stdafx.h"#include <stdio.h> /* Libary Collection.*/ #define MAX 10 /* Define: The max size of what we are working with.*/ int push (void); int pop(void); int peek (void);
[code]...
I was also told that I could us if statements instead but, that still will remove the first errors
I'm trying to write a code that is read character user 'e' or ' ' space also numbers I mean a number 'e' or space 'e' a number 'e' or space so forth.But i get absurd numbers. The program shows me the added number. If ' ' entered the taking numbers will stop(scanf will stop).
Example input:
e 1 8 7 2 3 6 or e 1 e 8 e 7 e 2 e 3 e 6
Code: #include <stdio.h> #define MAX 10 void addq ( int *, int, int *, int * ) ; void test();
I want to have one case of my switch statement to print out how many times the user has chosen other cases in the switch statement. Such as "You have pressed 2 6 times and 4 3 times."
Trying to write a program that calculates a students grade based on how many assignments have been graded. I am using a switch case since there is a total of 5 assignments, however when I enter case 1, and enter in how many I got out of 100, it just closes the program it doesn't go to the next part.
#include <iostream> using namespace std; char calculategrade(int total); int main() { // local variable declaration: char input;
I'm brand new to coding, and I'm learning C. To start, I wanted to create a program that would show an integer between 1-1000 as words (such as 157=One Hundred and Fifty Seven)
I'm having trouble with the switch-case function. I know that what I'm doing all works until it hits the switch function. I've tried switching one of the strcpy functions out with a printf, followed by a system("PAUSE") function, and it gave me results, so I know that the switch function is accepting my "hund" integer. I believe my problem lies within the strcpy function, and its use in the case function.
In short, why isn't the strcpy function working in the switch-case function? Below is my code as it is:
#include <stdio.h> #include <stdlib.h> #include <string.h> int main() { int num; int hund; char letHund[20];
My code is supposed to read a five to four digit code of a resistor from a file and determine the resistor's nominal, lower and upper tolerance values. I have inputted my file's first resistor code as a string so I could run tests on it but the problem that occurs is that a get the wrong values from my switch-case statements. I have put printfs after the function call to see what the values were and they turned out wrong. If I could get my return values to be right then I could be on my way coding.
#include<stdlib.h> #include<stdio.h> double bandNum(char x); // function prototype that will read the resistor value for the first, second and possibly third band double bandMult(char x); // function prototype that multiplies the resistor by some value of 10 double bandTol(char x); // function prototype that the tolerance of the resistor is multiplied by
I'm making a simple calculator and have done it all right where you can input everything, all the functions are there, but when i run the program it will come to displaying the result and it will always equal zero, I just need it to say 8+8 = 16 rather than 8+8 = 0, i don't know whether its just displaying the results as 0, or not displaying it at all, the code will follow below:
So I'm trying to make a derivative calculator that can do simple polynomial calculations in a very specific way. If you read the cout line you'll understand rather quickly.
I get an error at line 33 and 37 saying error: request for member '_cstr' in 'constant', which is of non-class type 'char' and the same line with 'degree' instead of constant.
My problem is , i want to make a simple calculator , in the console i want afterall the user to choose what type of operation he want pressing a key like i mentioned in the title the keys would be F1,F2,F3 , i'm not finding in the internet the code to the detection of a press key like what i want.
Code: #include <iostream> using namespace std; int F1 (int x, int y) { cout << "Enter a number: " << endl; cin >> x;
I am new to C programming, I have been given an assignment to create a simple calculator by splitting the program in 3 files. It should have 2 .c files and 1 .h... I went through the internet extensively and could only come up with this.
main.c:
Code:
//Calculator main.c #include <stdio.h> #include <conio.h> #include "Functions.h" int main() { float x = 0, y = 0; int operation;
[Code]...
Functions.c
Code:
#include "Functions.h" extern float x, y; float addition (float a, float b) { return a + b;
[Code]...
Functions.h
Code:
#ifndef FUNCTIONS_H_INCLUDED #define FUNCTIONS_H_INCLUDED float Sum(float a, float b); float difference (float a, float b); float remainder (float a, float b); float product (float a, float b); #endif
When I do a 'cl main.c' on the Developer Command window for VS2013, i get an error that reads :
main.obj main.obj : error LNK2019: unresolved external symbol _difference referenced in function _main main.obj : error LNK2019: unresolved external symbol _product referenced in function _main main.obj : error LNK2019: unresolved external symbol _addition referenced in function _main main.exe : fatal error LNK1120: 3 unresolved externals
I am working on a simple calculator in C++ .... All works fine with the calculator up until the requirement for the user to input "do you want to go again y/n" .... What i want to happen is the screen to clear down and reloop to the enter name part....but i can't get it to do that
Program Description: To write and develop a programme where a user can input a cost or price of something before VAT our program must then process the input number and must output the price with the original value plus VAT
#include <iostream>// I must use this to start my programming #include <string> // I have added this for the extension task so the user has to input their name #include <iomanip> // this is to manipulate the text #include <stdlib.h> using namespace std; // using the "using namespace std" shows that i will be using standard text throughout this programme
3. Write a program that reads a sequence of positive integers and prints out their sum, except that if the same number occurs several times consecutively, ignore all but the first. Assume an input of 0 marks the end of the input. For example, if the input is 3 8 5 5 4 9 1 1 1 1 8 0 then you should print 38 (i.e., ignore one of the 5's and three of the 1's).
