C++ :: Switch Case - Program That Calculates Students Grade
Apr 18, 2013
Trying to write a program that calculates a students grade based on how many assignments have been graded. I am using a switch case since there is a total of 5 assignments, however when I enter case 1, and enter in how many I got out of 100, it just closes the program it doesn't go to the next part.
#include <iostream>
using namespace std;
char calculategrade(int total);
int main() {
// local variable declaration:
char input;
I tried to write a menu program as a switch-case structure with a separate function for a switch-case structure itself. The outcome for it currently is an undesired one
Code:
#include <iostream> using namespace std; int menu(int answer); int main()
[Code].....
The output I get is one where it's just an infinite loop of "Bad choice! Please try again later.".
I am trying to make a program which manages the data of 5 different patients (its an uni assignment), and i want to use a switch case as a menu to switch between the patients. All other functions (as for example putting the infromation on a file) work, but i cant figure out to bring the switch to work. First it asks for the number of the patient which should be worked with, this works perfectly, but afterwards changiung between the persons doesnt work as thought. It should ask everytime after it switches to one patient (i removed some functions to make it easier to read) and then asks to which it should jump next. If i put the number of one case (lets say 3) it just stops the program.
********Example: user@pc ~/wherever $ ./program current variables: jo = 2 a = 0 1 //the entered number The variable a = 1 patient 1 Enter the number of the next patient2 // and then it closes **************
The same thing happens if i compile an example code from a book, it writes the first case and then stops.
I looked already through the forum but didnt find a person with a similar problem, maybe i didnt dig deep enough.
I am running Linux Mint 17 and use gcc as compiler.
Code:
include <stdio.h> #include <stdlib.h> int a=0; int jo=2; int main(void){ printf("current variables: jo = %d a = %d
I get so close, and then it seems my brain shuts down ... I need to write a program that outputs a histogram of student grades for an assignment. The program should input each student's grade as an integer and store the grade in a vector. Grades should be entered until the user enters -1 for a grade. The program should then scan through the vector and compute the histogram. In computing the histogram, the minimum value for a grade is 0, but your program should determine the maximum value entered by the user. Use a dynamic array to store the histogram. Output the histogram to the console. For example, if the input is:
20 30 4 20 30 30 -1
Then the output should be:
Number of 4’s: 1 Number of 20’s: 2 Number of 30’s: 3
I can't quite get my output to look like that:
/* This program will display the histogram of student grades for an assignment */ #include <iostream> #include <vector> #include <stdlib.h> #include <conio.h>
Write a program that a prof can use to enter the test marks of several students and which calculates the average mark of each student. Ask the user how many students he has, then ask him to enter each student's marks. When 999 is entered, calculate the average mark for that student (not counting the 999) and print the average. Then go on to the next students until the marks for all students have been entered, calculated and the average printed.
Code: #include<stdio.h> main() { float student,mark,total=0; float a,b,c; int num = 999; printf("
Remove the break statements from each of the cases. What is the effect on the execution of the program? Add an additional switch statement that allows for a Passing option for a grade of D or better. Use the sample run given below to model your output.
Sample Run: What grade did you earn in Programming I ? A YOU PASSED! an A - excellent work!
Rewrite the program LastFirst_lab44.cpp using if and else if statements rather than a switch statement. Did you use a trailing else in your new version? If so, what did it correspond to in the original program with the switch statement?
// This program illustrates the use of the Switch statement. // The break statement causes all subsequent expressions to be executed as well, also known as "falling through". // The trailing else statement acts just like the default section if none of the options from before work it gets "defaulted" to it.
#include <iostream> using namespace std; int main() { char grade; cout << "What grade did you earn in Programming I ?" << endl;
[code]....
how do you add an additional switch statement? i tried multiple times and i'm not sure if i don't understand braces enough but it didnt seem doable. also, I'm not sure what the teacher wants me to submit.
Ran into something today that does not make sense:
This compiles: Code: int x = 5;
switch(x) { case 0: { int value = 5; } break;
[Code] ....
Ok so it doesn't like int value = 6 b/c of int value = 5 for case 0. However since the value in case 0 is declared within the brackets one would think it has case scope.
So I tried this:
Code: int x = 5; switch(x) { case 0: { int value = 5; } break;
[Code] ....
Now it doesn't like it b/c value has not been declared in case 1:. These two conditions cannot possibly be both true at the same time. You cannot disallow the declaration of value in case 1 b/c it interferes with value in case 0 and at the same time disallow me to use value from case 0 b/c it is not in scope. If it was not in scope then theoretically I should be able to declare value in case 1.
Both MSVS 2012 and 2013 exhibit the same behavior. I checked the standard and it is unclear on the matter.
Im going through a C tutorial and im going to create a Database as part of the course. Im just in the very beginning of the project so its a very simple program so far.
Code:
#include<stdio.h> main(){ /*Variabler for att lagra information om skiva*/ char title[200]; char artist[100]; int tracks; int price;
[Code] ....
The first switch case statement takes me to the menu of choice, 1 or 2. However, chosing menu option one and trying to input a title or artist name, the program crashes.
Next, going into menu option 2 and then trying to print out, for example, title nothing happend. The process just ends.
Again, im sure this simple prototype is full of errors ....
I was just wondering if a switch statement can work without writing each case, for instance:
{ int age; age=18; while (age!=0) { cout<<"Enter age :"<<endl; cin>>age; switch (age) {
[Code] ....
It works only for values specifically entered as a case, for instance if you enter 5 or 15 , it says bicycle, but if you enter anything inbetween it goes to default. Same with 18 and 100. It can't possibly be that you have to enter
case 19: case 20: case 21: case 22:.......up to 100 to include all possible cases.
I'm trying to convert the enum type {PG, R, G, PG-13, etc.} to strings so i can use it in cout statement but no matter what i put inside switch(), the compiler keeps saying Error: expression must have integral or enum type. What am I doing wrong exactly?
Movie covert_rating(Movie r) { switch (r) { case PG: return "PG"; break; case R: return "R";
was making a somewhat of a Binary to Hex convertor but only 10/15 cases work and the non working are in the middle; 0010, 0011, 0100, 0101, 0110, 0111;;
// Test Code.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <cmath> #include <conio.h> using namespace std; int main(void) {int A; cout << "Enter the binary starting with the MSB
#include <stdio.h> int main () { int num; char choice; printf(" Welcome to a Menu-Demo Program Please select one of the following actions R - Programmers Rock! F - Programming is Fun! G - Geeks Rule! X - Exit program Selection ==>__ "); do{ choice = getchar(); switch(choice)
[code]......
I am currently writing a simple program that utilizes switch statements. When I run my program, it always displays the message for the default case.
If I have an integer variable like int a=9 then in the switch case If i write :
switch(a) { case 4+a: printf("hii"); }
Then why is this statement a compile-time error that variables cannot be used inside a case statement why does the compiler not subtitutes the values in place of the variables.
I'm working on a code that needs to loop a switch case back to the beginning after a certain input is entered.
ex) Code:
printf("Select an option); printf("1. Play game"); printf("2. Status"); printf("3. Exit"); scanf("%i", &userinput); switch(userinput);
[Code]...
For my program, I want option 2 to display something, then loop back to "select and option" after the user presses enter. How would I write that? Would i use a while? do while?
The basics of the program is that:It will ask the user whether they want to: Pop, Push , Peek or Exit the program.
When it comes to the Exit case: how do so( tried exit(1) & exit(0) using the internet hasn't brought me much luck either. I am getting these two errors also:
"Error LNK2019 : Unresolved external symbol "int_cdcel peek(void)" (?peek@@YAHXZ)"
Each applying to the functions below.
"Error LNK1120: 3 Unresolved Externals"
I'm not sure their is much more I can say about the problem.
Code:
#include "stdafx.h"#include <stdio.h> /* Libary Collection.*/ #define MAX 10 /* Define: The max size of what we are working with.*/ int push (void); int pop(void); int peek (void);
[code]...
I was also told that I could us if statements instead but, that still will remove the first errors
I'm trying to write a code that is read character user 'e' or ' ' space also numbers I mean a number 'e' or space 'e' a number 'e' or space so forth.But i get absurd numbers. The program shows me the added number. If ' ' entered the taking numbers will stop(scanf will stop).
Example input:
e 1 8 7 2 3 6 or e 1 e 8 e 7 e 2 e 3 e 6
Code: #include <stdio.h> #define MAX 10 void addq ( int *, int, int *, int * ) ; void test();
I want to have one case of my switch statement to print out how many times the user has chosen other cases in the switch statement. Such as "You have pressed 2 6 times and 4 3 times."
I'm brand new to coding, and I'm learning C. To start, I wanted to create a program that would show an integer between 1-1000 as words (such as 157=One Hundred and Fifty Seven)
I'm having trouble with the switch-case function. I know that what I'm doing all works until it hits the switch function. I've tried switching one of the strcpy functions out with a printf, followed by a system("PAUSE") function, and it gave me results, so I know that the switch function is accepting my "hund" integer. I believe my problem lies within the strcpy function, and its use in the case function.
In short, why isn't the strcpy function working in the switch-case function? Below is my code as it is:
#include <stdio.h> #include <stdlib.h> #include <string.h> int main() { int num; int hund; char letHund[20];
My code is supposed to read a five to four digit code of a resistor from a file and determine the resistor's nominal, lower and upper tolerance values. I have inputted my file's first resistor code as a string so I could run tests on it but the problem that occurs is that a get the wrong values from my switch-case statements. I have put printfs after the function call to see what the values were and they turned out wrong. If I could get my return values to be right then I could be on my way coding.
#include<stdlib.h> #include<stdio.h> double bandNum(char x); // function prototype that will read the resistor value for the first, second and possibly third band double bandMult(char x); // function prototype that multiplies the resistor by some value of 10 double bandTol(char x); // function prototype that the tolerance of the resistor is multiplied by
I have a problem with my simple operations calculator code (using C, in Code::Blocks). I am required to use a while loop statement so the user can execute multiple step operations without re-opening the program. When I launch the program, I get through the first session fine, but when I'm on the second session, when entering the two operands and press enter (to calculate), it just gives me the return and say press any key to continue (exit).Here is the code:
Code:
# include <stdio.h> int main() { int num1, num2; char op; int finished = 0; }
I'm writing a program to calculate a final grade by adding 4 numbers minus the lowest grade and dividing by 3. My knowledge in c is not extensive I thought that a simple assigment operator would do the job but I'm getting a strange large numbers in the execution.
I have to accept the numerical grade and determine the letter grade that the user will receive. I have to use a grading table to determine the letter grade based on the numerical grade. The Letter Grade table is
I'm trying to put what i've learned into a little program that calculates batting average.
I want to store the batting averages of the players in an array and printf the best average at the end by name for example Dennis Ritchie had best batting average at .600.
I'm having trouble understanding how and what type of array to use.
Code: int main(int argc, const char * argv[]) { char playerName[20]; int totalPlayers, atBats, totalHits, x; float battingAvg;
// Get total number of batters printf("How many batters?
