C :: How To Make A Switch Case Loop After Input Entered
Dec 31, 2013
I'm working on a code that needs to loop a switch case back to the beginning after a certain input is entered.
ex) Code:
printf("Select an option);
printf("1. Play game");
printf("2. Status");
printf("3. Exit");
scanf("%i", &userinput);
switch(userinput);
[Code]...
For my program, I want option 2 to display something, then loop back to "select and option" after the user presses enter. How would I write that? Would i use a while? do while?
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Jun 30, 2013
I have a problem with my simple operations calculator code (using C, in Code::Blocks). I am required to use a while loop statement so the user can execute multiple step operations without re-opening the program. When I launch the program, I get through the first session fine, but when I'm on the second session, when entering the two operands and press enter (to calculate), it just gives me the return and say press any key to continue (exit).Here is the code:
Code:
# include <stdio.h>
int main()
{
int num1, num2;
char op;
int finished = 0;
}
[code]....
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Dec 30, 2014
I am trying to make a program which manages the data of 5 different patients (its an uni assignment), and i want to use a switch case as a menu to switch between the patients. All other functions (as for example putting the infromation on a file) work, but i cant figure out to bring the switch to work. First it asks for the number of the patient which should be worked with, this works perfectly, but afterwards changiung between the persons doesnt work as thought. It should ask everytime after it switches to one patient (i removed some functions to make it easier to read) and then asks to which it should jump next. If i put the number of one case (lets say 3) it just stops the program.
********Example:
user@pc ~/wherever $ ./program
current variables:
jo = 2
a = 0
1 //the entered number
The variable a = 1
patient 1
Enter the number of the next patient2
// and then it closes
**************
The same thing happens if i compile an example code from a book, it writes the first case and then stops.
I looked already through the forum but didnt find a person with a similar problem, maybe i didnt dig deep enough.
I am running Linux Mint 17 and use gcc as compiler.
Code:
include <stdio.h>
#include <stdlib.h>
int a=0;
int jo=2;
int main(void){
printf("current variables:
jo = %d
a = %d
[Code]...
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Feb 28, 2013
I am stuck on an exercise where i am supposed to use a loop to take user input and keep a running sum until the user enters a 0. the code i have so far is:
#include <iostream>
int main() {
using namespace std;
int num;
int total = 0;
int x;
[Code] ....
The full text of the error message is: error c2678:binary'>>':no operator found which takes a left-hand operand of type 'std::istream' . and one more thing i was wondering, is there a difference between c++ and visual c++?
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Jan 31, 2014
Ran into something today that does not make sense:
This compiles: Code: int x = 5;
switch(x) {
case 0:
{
int value = 5;
}
break;
[Code] ....
Ok so it doesn't like int value = 6 b/c of int value = 5 for case 0. However since the value in case 0 is declared within the brackets one would think it has case scope.
So I tried this:
Code: int x = 5;
switch(x) {
case 0:
{
int value = 5;
}
break;
[Code] ....
Now it doesn't like it b/c value has not been declared in case 1:. These two conditions cannot possibly be both true at the same time. You cannot disallow the declaration of value in case 1 b/c it interferes with value in case 0 and at the same time disallow me to use value from case 0 b/c it is not in scope. If it was not in scope then theoretically I should be able to declare value in case 1.
Both MSVS 2012 and 2013 exhibit the same behavior. I checked the standard and it is unclear on the matter.
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Feb 11, 2013
Im going through a C tutorial and im going to create a Database as part of the course. Im just in the very beginning of the project so its a very simple program so far.
Code:
#include<stdio.h>
main(){
/*Variabler for att lagra information om skiva*/
char title[200];
char artist[100];
int tracks;
int price;
[Code] ....
The first switch case statement takes me to the menu of choice, 1 or 2. However, chosing menu option one and trying to input a title or artist name, the program crashes.
Next, going into menu option 2 and then trying to print out, for example, title nothing happend. The process just ends.
Again, im sure this simple prototype is full of errors ....
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Dec 16, 2013
Is it's scope confined to that single case?
char ch;
switch(ch) {
case '1':
using namespace common::section1; //only this case??
break;
[Code] ....
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May 28, 2014
I was just wondering if a switch statement can work without writing each case, for instance:
{ int age;
age=18;
while (age!=0) {
cout<<"Enter age :"<<endl;
cin>>age;
switch (age) {
[Code] ....
It works only for values specifically entered as a case, for instance if you enter 5 or 15 , it says bicycle, but if you enter anything inbetween it goes to default. Same with 18 and 100. It can't possibly be that you have to enter
case 19:
case 20:
case 21:
case 22:.......up to 100 to include all possible cases.
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Dec 11, 2014
I keep getting the error "case value has already appeared in this switch" how do I fix this?
switch (selection) {
case 'A' || 'a':
aFunc(Houses);
break;
case 'B' || 'b': //The error is here
bFunc(Houses);
[code].....
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Jul 4, 2014
I'm trying to convert the enum type {PG, R, G, PG-13, etc.} to strings so i can use it in cout statement but no matter what i put inside switch(), the compiler keeps saying Error: expression must have integral or enum type. What am I doing wrong exactly?
Movie covert_rating(Movie r) {
switch (r) {
case PG:
return "PG";
break;
case R:
return "R";
[code]....
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Feb 13, 2015
I tried to write a menu program as a switch-case structure with a separate function for a switch-case structure itself. The outcome for it currently is an undesired one
Code:
#include <iostream>
using namespace std;
int menu(int answer);
int main()
[Code].....
The output I get is one where it's just an infinite loop of "Bad choice! Please try again later.".
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Jan 31, 2015
was making a somewhat of a Binary to Hex convertor but only 10/15 cases work and the non working are in the middle; 0010, 0011, 0100, 0101, 0110, 0111;;
// Test Code.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include <cmath>
#include <conio.h>
using namespace std;
int main(void)
{int A;
cout << "Enter the binary starting with the MSB
[code]....
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Feb 25, 2014
#include <stdio.h>
int main () {
int num;
char choice;
printf(" Welcome to a Menu-Demo Program
Please select one of the following actions
R - Programmers Rock!
F - Programming is Fun!
G - Geeks Rule!
X - Exit program
Selection ==>__ ");
do{
choice = getchar();
switch(choice)
[code]......
I am currently writing a simple program that utilizes switch statements. When I run my program, it always displays the message for the default case.
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Feb 26, 2015
If I have an integer variable like int a=9 then in the switch case If i write :
switch(a) {
case 4+a: printf("hii");
}
Then why is this statement a compile-time error that variables cannot be used inside a case statement why does the compiler not subtitutes the values in place of the variables.
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Nov 27, 2014
Write a program to make a table for any input number and then continuesly ask to press y to print more table and if you press any key other than y then program must be terminate using while loop and do while loop. How to start or end with it.
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Oct 12, 2013
The basics of the program is that:It will ask the user whether they want to: Pop, Push , Peek or Exit the program.
When it comes to the Exit case: how do so( tried exit(1) & exit(0) using the internet hasn't brought me much luck either. I am getting these two errors also:
"Error LNK2019 : Unresolved external symbol "int_cdcel peek(void)" (?peek@@YAHXZ)"
Each applying to the functions below.
"Error LNK1120: 3 Unresolved Externals"
I'm not sure their is much more I can say about the problem.
Code:
#include "stdafx.h"#include <stdio.h>
/* Libary Collection.*/
#define MAX 10
/* Define: The max size of what we are working with.*/
int push (void);
int pop(void);
int peek (void);
[code]...
I was also told that I could us if statements instead but, that still will remove the first errors
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Nov 10, 2014
I'm trying to write a code that is read character user 'e' or ' ' space also numbers I mean a number 'e' or space 'e' a number 'e' or space so forth.But i get absurd numbers. The program shows me the added number. If '
' entered the taking numbers will stop(scanf will stop).
Example input:
e 1 8 7 2 3 6
or e 1 e 8 e 7 e 2 e 3 e 6
Code: #include <stdio.h>
#define MAX 10
void addq ( int *, int, int *, int * ) ;
void test();
[Code]....
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Sep 20, 2013
I want to have one case of my switch statement to print out how many times the user has chosen other cases in the switch statement. Such as "You have pressed 2 6 times and 4 3 times."
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Apr 18, 2013
Trying to write a program that calculates a students grade based on how many assignments have been graded. I am using a switch case since there is a total of 5 assignments, however when I enter case 1, and enter in how many I got out of 100, it just closes the program it doesn't go to the next part.
#include <iostream>
using namespace std;
char calculategrade(int total);
int main() {
// local variable declaration:
char input;
[Code]....
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Sep 21, 2014
I'm brand new to coding, and I'm learning C. To start, I wanted to create a program that would show an integer between 1-1000 as words (such as 157=One Hundred and Fifty Seven)
I'm having trouble with the switch-case function. I know that what I'm doing all works until it hits the switch function. I've tried switching one of the strcpy functions out with a printf, followed by a system("PAUSE") function, and it gave me results, so I know that the switch function is accepting my "hund" integer. I believe my problem lies within the strcpy function, and its use in the case function.
In short, why isn't the strcpy function working in the switch-case function? Below is my code as it is:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
int num;
int hund;
char letHund[20];
[Code] .....
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Mar 21, 2015
My code is supposed to read a five to four digit code of a resistor from a file and determine the resistor's nominal, lower and upper tolerance values. I have inputted my file's first resistor code as a string so I could run tests on it but the problem that occurs is that a get the wrong values from my switch-case statements. I have put printfs after the function call to see what the values were and they turned out wrong. If I could get my return values to be right then I could be on my way coding.
#include<stdlib.h>
#include<stdio.h>
double bandNum(char x); // function prototype that will read the resistor value for the first, second and possibly third band
double bandMult(char x); // function prototype that multiplies the resistor by some value of 10
double bandTol(char x); // function prototype that the tolerance of the resistor is multiplied by
[Code] ....
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Feb 26, 2015
I just wanted to ask the reason that why is the below code not checking the case -1 while working for the other case values.
#include<stdio.h>
#include<conio.h>
int main() {
int i=-1;
switch(i-2) {
[Code] ....
So why in the below code the case -1 doesnt run,when the value evaluated by the switch construct is actually a negative integer constant.
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Mar 20, 2014
Program is to add two fractions together like so..
This program adds fractions. ‘Y’ continues, any other key exits program
===================================================
Enter numerator 1 ==> 1
Enter denominator 1 ==> 3
Enter numerator 2 ==> 1
Enter denominator 2 ==> 6
1 1 1
--- + --- = ---
3 6 2
-----------------------------------------------------
Continue? Y or N! ==> n
My question is that i need each input to be a number.
if a character is entered i want it to output something like..
This program adds fractions. ‘Y’ continues, any other key exits program
===================================================
Enter numerator 1 ==> 1
Enter denominator 1 ==> a
You need to enter a number here.
Press any key to continue.
and then clear the part where the letter was entered.
This program adds fractions. ‘Y’ continues, any other key exits program
===================================================
Enter numerator 1 ==> 1
Enter denominator 1 ==>
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Feb 26, 2014
The program i am trying to make is for practice of using switch. the idea is the user enters a number and the program will print a day of the week corresponding to said number.
the statement is not complete with all cases yet, but i dont want to write all of it until i am sure of it being correct.
errors when compiling (gcc) are as follows
1 warning and 3 errors generated.
Robins-MacBook-Air:array2 RDenton$ gcc array2.c
array2.c:26:9: warning: format string is not a string literal
(potentially insecure) [-Wformat-security]
printf(a[uservalue]);
[code]....
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May 25, 2014
I had been tasked to create a program that reverses a word i.e.
cat
tac
How to make my program non case-sensitive using vectors?
Code:
// BackWardsSentence.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include <iostream>
#include <sstream>
#include <string>
using namespace std;
string BackWords (string sentence);
int BackSentence (string sentence);
string BackWords1 (string sentence);
[Code] .....
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Dec 4, 2014
im working on our project and this part of the project which says to add a new a room.
Details:
Open the file (ROOMS) that maintains all the ROOMS records.
Ask the user to enter the required data Room_Type and Room_Rate, then save it.
Keep asking the user (Do you want to continue?) until the user enters (N OR n), this should stop the data entry and get the user back to the main menu.
Myproblem :: i keep getting error at the bottom says my while statement is wrong " IntelliSense: no operator "!=" matches these operands"
My other problem:: how do i get back to the main menu?
so what ive done till now is.
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main() {
int choice,i=1,Room_rate;
string alphabet;
string Room_type;
[code].....
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