So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
View 4 Repliesignoring negative numbers when I am trying to add up only positive numbers.
SAMPLE:
if (num>=0) {
sum= sum + num;
}
else
how would the else in this case being a negative number not be included in the sum
I need to ignore negative values in an array, but not exit the function.
For example if the user enters:
1,2,3,4,-1,-2,0
the array would be
[1,2,3,4]
Is there a way to ignore these values?
I have a problem with my assignment. I would like to ask how to transfer positive and negative values from array temperature to arrays positive and negative?
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
int n=0, d=0, temperature[20], sum;
int positive[], negative[];
float avg;
[code]....
#include <iostream>
using namespace std;
int initialization (int []);
int identifying (int [],int);
[Code].....
I have tried writing a code which takes two numbers from the user and calculates their square root then the roots are added up to return the sum. The program is coming out with loads of errors.
#include<iostream>
#include<cmath>
float main(){
using namespace std;
float m1,m2,m3,m4,m5;
[Code] ....
Write a program that calculates the average of a stream of positive numbers. The user can enter as many positive numbers as they want, and they will indicate that they are finished by entering a negative number. For this program, treat zero as a positive number, i.e., zero counts as a number that goes into the average. Of course, the negative number should not be part of the average. You must use a function to read in the numbers, keep track of the running sum and count, compute the average, and return the average to the main() function. Note that you must use a loop to do this, as you don't know how many numbers the user will enter ahead of time. I am having problem writing a loop program for it..
View 1 Replies View Relatedim supposed to create a program that reads in a list of integers from the terminal and writes the negative numbers to one file and the positive numbers to another file.
i got most of it doen but for some reason its not writting the negative numbers. on what im doing wrong?
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int main(){
int pos_num = 0;
int neg_num = 0;
int positive_numbers = pos_num % 5;
[Code]...
I am trying to average the negative numbers and positive number and of course the total average.
This will read in a list of n values, where n is not known ahead of time. The number of values read into the array will be saved in n.
vector<int> readList() {
std::vector<int> result;
ifstream inFile;
inFile.open("setA.txt");
for (int x; inFile >> x; ) {
result.push_back(x);
[code]....
array is a one-dimensional array of integers and n is the number of elements in that array that contain valid data values. Both of these are input parameters to the function. The function must calculate 1) the average of the n integers in array, storing the result in ave; 2) the average of the positive numbers (> 0), storing the result in avePos, and 3) the average of the negative numbers (< 0), storing the result in aveNeg.
void avgs (std::vector &array, int &ave, int &avePos, int &aveNeg) {
int sum = 0, pos_sum = 0, neg_sum = 0, pos_count = 0, neg_count = 0;
for (auto i : array) {
sum += i;
if (i > 0) { pos_sum += i; ++pos_count; }
[code]....
I am studying c and I thought what would be better than using my pi to play with relays and c. I am used to PHP as a scripting lang and don' t do much programming. So I wrote this to use wirepi and ask the user "on or off" they type on or off and it does it. it does work but I know something is wrong when I use strcmp in the if statment I can -10 for a value. Here is the code.....
Code:
#include <stdio.h>
#include <string.h>
main(int argc, const char * argv[]) {
char oo[100];
system("gpio mode 0 out");
printf("Do you want it on or off?
[Code] ....
This is what it outputs at the prompt
Do you want it on or off?
on
on
It is now on!
How can I just get Code: if (oo = on) {} and like so with off.
Write a program asks the user for a positive integer value and then prints out all perfect numbers from 1 to that positive integer. I have been trying for some time, i found a way to check if its a perfect number or not but could not find a way to prints out all perfect numbers from 1 to that positive integer. I am here so far.
#include<iostream>
#include<iomanip>
using namespace std;
int main(){
int n,i=1,sum=0;
cout<<"Enter a number: ";
[Code] ....
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
[Code] ....
#include <iostream>
#include <iomanip>
using namespace std;
// Function Prototype
void sortArray(int array[], int size);
[Code] ....
This program was made to allow students to enter as many test scores as they want and the program will show them in ascending order and then will calculate the average of all test scores. It works wonderful until you enter a negative test score and then it throws the averaging process off. I can't seem to be able to make the program not accept the negative numbers.
What are positive and negative infinity for different data types in c++, are they represent maximum and minimum limit of a type? or positive infinity is not a finite value.can some explain this positive and negative infinity paradigm
View 3 Replies View Relatedint Fib1 = 1;
int Fib2 = 2;
int Fib3 = 0;
int randomynumber;
int Loop;
[code].....
this returns negative numbers sometimes.what did i do wrong side note this is not the complete program it is only the part with the problem because the complete code is sort of longish and very confusing
Write a program to enter the number till 100 till the user want and at the end it should display the count of positive and negative and zero entered.
View 8 Replies View RelatedMy program uses a while loop to eventually get to an error of zero and a root of sqrt(3). I'm not understand why after the third iteration the program fails to compute a new x value. I'm using Visual Studio 2013. The code tag instructions were dubious.
Code:
#include <stdio.h>
#include <math.h>
main() {
/*This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots.*/
printf("This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots. Enter your estimate of the root.
");
float x,y,z;
int num;
num = 0;
[Code]...
Consider a new data type, the mikesint, which can hold 9 bits.
(a) What is the largest integer that an unsigned mikesint can hold?
(b) What is the largest positive integer that a signed mikesint can hold?
(c) What is the largest negative integer that a signed mikesint can hold?
Not sure how to determine this. I'm stuck.
So I tried creating a test code for reading a negative number and positive number but whenever I enter a negative number it read it as being positive.
#include <stdio.h>
#include <iostream>
#include <iomanip>
[Code].....
PS: I am using char over int because the program that I am testing for requires me to use 8 bit variable.
I added my assignment to attachment, i need to calculate the sum for input values of x and n this is my code:
#include<stdio.h>
#include<math.h>
main() {
float gore,dole,s,x;
int n,i,j,z;
s=0;
i=0;
j=0;
[Code] ....
gore calculates x^(2*i)-3 and dole is for (2+i)! for input x=1 and n=1 i get -2.0 output which is the value of x^(2*i)-3 the (2+i)! part gets ignored for some reason, for any other input i tried the output is 0 ....
I have an assigment and I don't know yet how to write this program :" I introduce the average monthly temperatures of a year(12 values for 12 months). When I compile the program it needs to show the highest negative temparature and the lowest positive temperature of that year.
Example: Entry data: -4 -6 0 5 10 20 24 25 17 8 -1 -7 exit data : max negative= -1 and min positive= 5 "
In this exercise, write a rational number calculator that ask the user to enter two rational number:
a/b + c/d
and produce the result:
(ad+bc)/bd
I have this code that im stuck on what i need to do is Extend the code such that when it starts the user is asked to input values to specify each of the three ranges before moving on to accept and tally the main values how do i do that Using a for loop to input and output array values Also calculate the average
*/
#include <stdio.h>
int main(void)
{
/* Declare an array of integers */
int Grades[5];
int nCount;
int nTotal = 0; /* Declare and initialise the value */
float fAverage;
[Code]...
exercise in c: write a program which calculates % of even numbers entered by a user in an array;
1) check if user hasn't entered float value; if has issue warning;
2) give the option for user to press "stop" to exit program any time.
int c,sk[100],i,sum1=0, sum2=0, rel;
printf ("How many numbers will you enter?
");
scanf ("%d", &c);
printf ("Enter %d numbers (to exit program press - stop)
", c);
[Code] ....
I am trying to create a program that will calculate pi based on a user input for accuracy. If the user input .3 then when the leibniz infinite sum value at a particular i becomes less then the input of .3 then the loop will exit.
I have looked at a number of examples on the internet but I feel lost. I have put together working code that will infinitely output sums but I need the loop to stop when the sum value is less then the accuracy value.
My question is what is wrong with my while loop, why will it only give me infinite summations? How do I make it so that the loop will exit when my accuracy input is greater then the sum?
int main () {
double accuracy;
cout<<"Give an accurate number." << flush;//looks nice
cin>>accuracy;
int d;//initialize denominator
double pi = 0.0;
while(accuracy < d){
[Code]...
I'm trying to create a program that will take input from a user and calculate it in a do-while loop. The program does the calculation but the answer is wrong. The loop also doesn't work. The purpose of the program is to see how much an item will cost after a discount is taken off and tax is added.
#include <iostream>
#include <cmath>
using namespace std;
double original_cost;
double discount;
double tax;
double total;
char answer;
[Code]...