C++ :: Input From User A Positive Number N And Find Its Factorial
Oct 8, 2014
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5
5! = 120
Would you like to continue (Y/N)?Y
Please enter a number: 3
3! = 6
Would you like to continue (Y/N)?N
Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream>
using namespace std;
int main(){
int i=1;
int n;
find the prime factors of the number input by the user. This time, we are going to have the user input a number, and the program will find all prime numbers from 2 to that number and prime factors of the number input by the user
#include <iostream> #include <cmath> using namespace std;
I was given a question in my programming class to create a program to find the factorial of any number greater than zero and to use Gosper's formula to approximate it.
Code: #include <stdio.h> #include <math.h> #define PI 3.14159265 double equation(int n); int
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
I wrote this code to find the factorial of any given function ., works fine but when i put it in a class... it gives me an error ::assignment of read only variable fact;
#include <iostream> using namespace std; const static int fact=1; class My_Factorial { public: int x; void Get_Number(){ cout<<"enter a number to find its factorial";
As an assignment for school , I've to write a program to find the sum prime factors of a user input integer.
E.g. 20 = 2 x 2 x 5 , Sum = 2 + 2 + 5 = 9 E.g. 10 = 2 x 5 , Sum = 2 + 5 = 7
My method for finding the result is as follows :
- Divide the number by increasing values if int i , starting from i=2.
- Once I get a value of i that can divide the number without giving me a remainder , I add this value of i to int sum and divide the number by i.
- I will repeat this process until the user input value is equal to 1.
My code is as shown:
#include<stdio.h> int primecheck(int n); // Function to check if i is prime int primesum(int n); // Function to sum the values of i that are prime int main(void) { int n; int sum; printf("Enter a number (> 1): "); //Prompting and scanning user input ,n scanf("%d",&n); sum = primesum(n);
[Code] .....
But for some reason I keep getting an incorrect result, it's as if it is missing out the last factor for each case.
Eg. 20 = 2 x 2 x 5 , the result I get is 4 , which is 2+2 Eg. 40 = 2 x 2 x 2 x 5 , the result I get is 6 , which is 2+2+2;
I have been trying to finish this code (function) for a while now, but am stuck on the last part. In this code, I prompt the user to select a number of integers and any number of digits and then find the smallest and largest value within these digits. On the next part, I am supposed to determine which of the given digits the smallest and largest are located such that the output should be:
Digit _ can be found in integer number(s): _, _
Here is what I have tried:
Code: int digitSizeLoca() { int userNumInteger; int* iPtr; int* iPtr2; int* iPtr3; int value;
[Code] ....
Seems to do the job, but it always outputs 1, 2...
How to find the largest and smallest number entered by a user. So far I'm able to add, find the average and count how many numbers are entered.
I'm just having trouble with find the max and min. I tried if statements and it breaks the program will it wont let me exit the while loop or the program will do a force close after entering a value.
Code:
#include <stdio.h> #include <stdlib.h> int main(){
int maxNum=0, minNum=0, value, count=0, sum=0; double average;
I am trying to find the max number entered by the user, and it should terminate when a negative number is entered. For my code, it will just end when the user inputs a lower number than the previous. i.e.- 10 20 15 "The highest number is 20" when it should be "10 20 5 40 15 -1" "The highest number is 40". No arrays or do/while loops either.
#include <iostream> using namespace std; int Max(int x); int main() { int x;
I am trying to write code to find all the prime numbers before a user entered number. I started with a working program and when I tried to create a function, it got all messed up.
Code:
#include <stdio.h> int is_prime( int num ); int get_positive_integer(void); int main( ) { int upper; /* upper limit to check */ int num; /* current number to check */ int isprime; /* used to flag if number is prime or not */
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234 Value of Y: 234567 Reversed value X: 4321 Reversed value of Y: 765432 New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream> using namespace std; int main(){ int x=0, y=0; int reverse_x=0; int reverse_y=0; int z = 0; int l;
[Code]....
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is then how I could use that concept here.
There's this program I'm trying to code where the user gives input of 2 values.
Sample :- Value of X: 1234 Value of Y: 234567 Reversed value X: 4321 Reversed value of Y: 765432 New value as Z: 1223344567 (each number was taken in both X and Y) Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream> using namespace std; int main(){ int x=0, y=0; int reverse_x=0; int reverse_y=0; int z = 0; int l;
[Code]...
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is I can't seem to really get that idea how I could use that concept here. I'm not really good with programming, fairly new at this.
It is given an integer "p". I have to find a number "n" for which "n factorial" has "p" numbers of zero at the end. Here is the solution i thought, but i am not sure if it is a solution for this problem. Do i have to make a function to calculate the factorial and another function to get the zeros?
int p; int count5=0; int i; int copy_i; printf("Enter p: "); scanf("%d",&p); for(i=1; ;i++) {
I just want to practice in the language so i wrote this simple function that computes the factorial result of a certain number. The problem is that for all numbers > 20, the results are wrong ( < 20 all good).
I already learned that normal "long" type in c is more like 32 bit int and not 64 bit like a long type in java. so I used here a "long long" type.
why am I getting strange results above the number 20? isn't 64 bit enough to hold those numbers?
Code: long long factorial(int n); int main() { long long result = factorial(20); printf("%lld",result);
[code] ...
for 21 i get: -4249290049419214848
where the right result shoud be: 51,090,942,171,709,440,000
If the user puts in a 6. I need the array to display the even number from 0 - 6. Right now what it does is it displays the first six even numbers. Okay as I'm writing this I'm starting to see where my problem might be..
Code: void sumIntegers () { int arr[50]; int i = 0; int num = 0; int sum = 0;
I'm working my way through some C exercises to get some practice and have hit a wall. I need to use a function to take a number, such as 1, and print out One.Here's what I've got so far:
Code: #include <stdio.h> int name(int n); char numberOne[] = "One"; int main(void) { int n; }
[code]...
However, when I run the code and enter "1" the only thing that gets printed to the screen is "(lldb)". I've tried changing it to doing it without variables and just printing "One" but that gave the exact same result.
I'm having a bit issue with ispunct in my function. The user can input a phone number in any of the formats below:
4147778888 (414)7778888 (414)777-8888
The program will only print out:
41447778888
What I am trying to do is accept any integer and parentheses. If the user inputs anything else, the program will display an error message. Right now, parentheses displays an error which is obvious but I'm wondering if there is a way I can allow a parentheses to be entered but not any other symbol. ex: . , : ; " '
Code: void getPhoneNum(){ // Local Declarations char string[14]; char* tokPtr;
User will input a number in the range of 2 and 2^63-1 and the program will decide whether it's prime or not by a simple 'YES' or 'NO'.
I figured out a code:
#include <stdio.h> #include <string.h> main() { unsigned long long n,i=3; int temp=0; int t; scanf("%d",&t); //Number of test cases
[Code] ....
Now this code works for normal inputs but whenever I try it with large primes in tat range, like 987654321987654329 or 9223372036854775783 it does not work />.
I tried to print the values of i to check the limit to which it runs.. and I found it 23697, whose square is 561547809 - nowhere near about the input primes.
write a program that computes the factorial of a number and displays it. A factorial of a number (written N!) is defined as N * (N-1) * (N-2) * (N-3) ... *1 In other words, 5! = 5 * 4 * 3 * 2 * 1 = 120 and 3! = 3 * 2 * 1 + 6.
Example of output 15 is 1.30767e+012
Can't get it to display error when user enters a number lower than 2 or higher 60.
// Program to calculate factorial of a number #include <iostream> #include <iomanip>
The basic idea of this exercise is to generate words from a user-input, seven-digit number(a phone number). The code runs, but for some reason, I can't get it to print the numbers into the file.
Code: /*Write a program that will generate a word based on a randomly generated, seven-digit number. there should be 2187 possible words. Avoid "phone numbers" that begin with 0 or 1*/
#include<stdio.h> #define PHONE 7 void wordGenerator(int number[]); void wordGenerator(int number[]) { //loop counters for each digit in the number
