C :: Take User Input Between 1 And 10 And Print Out Number As A Word
Oct 2, 2014
I'm working my way through some C exercises to get some practice and have hit a wall. I need to use a function to take a number, such as 1, and print out One.Here's what I've got so far:
Code:
#include <stdio.h>
int name(int n);
char numberOne[] = "One";
int main(void)
{
int n;
}
[code]...
However, when I run the code and enter "1" the only thing that gets printed to the screen is "(lldb)". I've tried changing it to doing it without variables and just printing "One" but that gave the exact same result.
I'm learning programming, and C++. I've got a question, but I couldn't solve my problem so far. I need to use arrays and only basic stuff to solve this:
Create a program that reads a word from the user and then print (cout) this word on contrary. It's simple, I know, but I can't do it,. I've tried some stuff but I don't get how I will get the proper values to do this. All I know is that I can use variable.lenght().
I've been agonizing over this all day. The assignment is to capitalize every other word in a user input string.
My logic is as follows:
1. I have the program get each character until it encounters white space (using for loop) 2. Then it should capitalize each character after the white space until it encounters another white space (using while loop).
My problem though is when i try to create a condition for while loop i have to terminate is when white space is encountered, but the very first character to start the while loop is a white space..
I was told to define boolean values, but after trying a few boolean conditions I'm still stuck..
Code: #include <iostream> #include <string> #include <cctype> using namespace std;
I'm trying to write a program that capitalizes every other word of a user output. (ex: if input is "i love you", the output is "i LoVe YoU").
I am using a for loop (although an if loop might be easier?) and I'm assuming that it is possible to write this program using a for loop (although I may be wrong--maybe only if loops can write this program). I have everything down EXCEPT the last step where I have to print the entire sequence. What i have so far is:
Code: #include <cs50.h> #include <stdio.h> #include <string.h> { // get user input printf("Type a sentence: "); string s = GetString();
[Code] .....
The code above basically only prints out the capital letter (ex: input is "hello", output is "EL"). I don't know how to print out the entire sequence.
I'm creating a program that takes user input in the form of a string and tests to see if it matches a word. Each correct word will increase their score by one. Here is a portion of the code that is not working.
To me, this looks like it should do a very simple task as intended-take a String, compare it to another, and reset the word if they match or output incorrect if not. But, I'm not sure if there is some quirk in C++ with Strings, because this code always outputs Incorrect. Please try again. and the score never increases. I also tested this by literally setting the strings equal in the code, which still resulted in it not doing what it's supposed to.
I need to write a C program to make the user input some text,and the first letter of each word has to be uppercase.(have to use while loops)So for example lets say the user inputs:
i lOvE pRoGrAmMiNg The output needs to be: I Love Programming
Code:
#include <stdio.h> int main() { int i = 0; char c, lower_c;
printf("Enter text ");
[code]....
I have started this code by making the letters lowercase.I am not sure how proceed after this step, the step of making the first letter uppercase.
Create a program that will ask the users name, age, and reddit username. have it tell them the information back, in the format: your name is (blank), you are (blank) years old, and your username is (blank).
My program outputted H 0 and an upside down question mark. I was thinking that maybe the error in the program was that i was supposed to use %s instead of %c but im not entirely too sure.
Basically i want to input a number for example 123456 and get back how many 7's are in the input number and also to print out that same number with stars in between like this *1*2*3*4*5*6*. Here is what i have so far:
#include <iostream> using namespace std; int countSeven(int x){ if(x == 7)return 1; int c = 0; while(x/10 > 9)c++; return countSeven(x/10)+1;
when i compile it does not do what i tell it it just tells me there are 0 7's in the input number no matter how many there really are...
Basically I have a text file called words. I'm supposed to extract a word randomly form the file and have the user guess the word. If they guess the word correctly in x number of tries they will receive the definition.
I'm having trouble receiving that random word and I'm getting the definitions from the file.
This is what is in the words.txt file apple#the usually round, red or yellow, edible fruit of a small tree boat#a vessel for transport by water horse#a solid-hoofed plant-eating domesticated mammal with a flowing mane and tail, used for riding television#a system for transmitting visual images and sound that are reproduced on screens soup#a liquid dish, typically made by boiling meat, fish, or vegetables, etc. bottle#a container, typically made of glass or plastic and with a narrow neck barber#a person who cuts hair toast#sliced bread browned on both sides by exposure to radiant heat radar#a system for detecting the presence, direction, distance, and speed of aircraft, ships, and other objects red#of a color at the end of the spectrum next to orange and opposite violet
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234 Value of Y: 234567 Reversed value X: 4321 Reversed value of Y: 765432 New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream> using namespace std; int main(){ int x=0, y=0; int reverse_x=0; int reverse_y=0; int z = 0; int l;
[Code]....
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is then how I could use that concept here.
There's this program I'm trying to code where the user gives input of 2 values.
Sample :- Value of X: 1234 Value of Y: 234567 Reversed value X: 4321 Reversed value of Y: 765432 New value as Z: 1223344567 (each number was taken in both X and Y) Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream> using namespace std; int main(){ int x=0, y=0; int reverse_x=0; int reverse_y=0; int z = 0; int l;
[Code]...
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is I can't seem to really get that idea how I could use that concept here. I'm not really good with programming, fairly new at this.
If the user puts in a 6. I need the array to display the even number from 0 - 6. Right now what it does is it displays the first six even numbers. Okay as I'm writing this I'm starting to see where my problem might be..
Code: void sumIntegers () { int arr[50]; int i = 0; int num = 0; int sum = 0;
I'm having a bit issue with ispunct in my function. The user can input a phone number in any of the formats below:
4147778888 (414)7778888 (414)777-8888
The program will only print out:
41447778888
What I am trying to do is accept any integer and parentheses. If the user inputs anything else, the program will display an error message. Right now, parentheses displays an error which is obvious but I'm wondering if there is a way I can allow a parentheses to be entered but not any other symbol. ex: . , : ; " '
Code: void getPhoneNum(){ // Local Declarations char string[14]; char* tokPtr;
User will input a number in the range of 2 and 2^63-1 and the program will decide whether it's prime or not by a simple 'YES' or 'NO'.
I figured out a code:
#include <stdio.h> #include <string.h> main() { unsigned long long n,i=3; int temp=0; int t; scanf("%d",&t); //Number of test cases
[Code] ....
Now this code works for normal inputs but whenever I try it with large primes in tat range, like 987654321987654329 or 9223372036854775783 it does not work />.
I tried to print the values of i to check the limit to which it runs.. and I found it 23697, whose square is 561547809 - nowhere near about the input primes.
The basic idea of this exercise is to generate words from a user-input, seven-digit number(a phone number). The code runs, but for some reason, I can't get it to print the numbers into the file.
Code: /*Write a program that will generate a word based on a randomly generated, seven-digit number. there should be 2187 possible words. Avoid "phone numbers" that begin with 0 or 1*/
#include<stdio.h> #define PHONE 7 void wordGenerator(int number[]); void wordGenerator(int number[]) { //loop counters for each digit in the number
im writing a program that asks the user to input a number 1-10 and will transform it into the roman numeral of that number but it seems that its not after the user inouts the number nothing will output
#include <iostream> #include<iomanip> using namespace std;
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5 5! = 120 Would you like to continue (Y/N)?Y Please enter a number: 3 3! = 6
Would you like to continue (Y/N)?N Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream> using namespace std; int main(){ int i=1; int n;
The problem that I am having is that , the program outputs numbers that are perfect numbers and im not sure where i can add a statement to make it so that if it isn't a perfect number it doesn't output...
#include<iostream>// allows user input/output #include<conio.h> #include<fstream>//data file / result file #include<iomanip> #include<cmath> // math function #define in_file "data.txt" #define out_file "result.txt"
find the prime factors of the number input by the user. This time, we are going to have the user input a number, and the program will find all prime numbers from 2 to that number and prime factors of the number input by the user
#include <iostream> #include <cmath> using namespace std;
Im trying to create a program that has the user input a 5 digit number. If it's between 10000 & 99999, it will do one thing..(just saying 'yes' for now. Outside those numbers will prompt the user to input again. However, if the user inputs the exact digits 76087, it should display 'term'.
This current code is displaying 'term' whenever the user inputs the 5 digits.
Code:
#include <iostream> using namespace std; int main() { int pin; cout << "Welcome to Movie Food Enter your 5-digit pin code: " ;
i was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h> int * toarray(int *num); int main(void) { int testCases; }
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases 23456 //input number 6 2293452 4 2293700 1974439125
Process returned 0 (0x0) execution time : 4.152 s Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
