im writing a program that asks the user to input a number 1-10 and will transform it into the roman numeral of that number but it seems that its not after the user inouts the number nothing will output
#include <iostream>
#include<iomanip>
using namespace std;
[Code]....
So I'm trying to make a program that asks the user for a number and then prints a statement the same number of times the user entered. 3 different statements, using the 3 loops (for, while, and do while). I made the program but for some reason the statement from the do while loop goes off infinitely.
MY CODE:
The error:
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
Write a program that asks the user to prompt an Integer number and then test whether it is Palindrome Numbers or not.
The following are Palindrome numbers:
1.22
2.333
3.67876
4.44444
5.123454321
C programming: I want to creat a program that asks the user to input the integer lengths of three sides of a triangle, and if so whether the triangle is a right-angled, acute or obtuse one. i am having some doubts about the if, else if statements. I never seem to know how and in what order to use them.
Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
int main(int argc, char *argv[]){
int SideA;
int SideB;
int SideC;
}
[code]....
I have to write a program that will ask you to put in a number between 0 and 9 and multiply it by pi. If the number put in is between 0 and 9 then pi is multiplied but if it isnt between 0 or 9, it will say the number is not between 0 and 9 and asks you to put it in again and will repeat until a number between 0 and 9 is put in.
I have got the program working to the extent that it the number is between 0 and 9 it will multiply it by pi but if its not between 0 and 9 it will say the number is not between 0 and 9 and ask to put in a new number.
I can't work out how to get the program to repeat itself if the number entered isnt between 0 and 9.
I have enclosed the code below .....
So I am trying to write a program that asks the user for a name. If the user enter the right name the program ends but if the user were to enter the wrong name the program would enter a loop prompting the user to re-enter the name. However I am not able to get the program to work!
View 9 Replies View RelatedI'm trying to write a program where it asks the user for a file name.
If that file exists, the it will open the file and then read it and print the information in the file.
However, if the user enters a file name that does not exist, the user will have 2 more tries (for a total of 3 tries) to get the correct name of the file.
I am close to getting it. What I have now just won't go through the loop to validate if the input matches an existing file. It goes straight to the printing of what is in the file. If the file doesn't exist, it prints: "Found your file..Opening..processing...Total keys found = 0."
So, my question, what am I doing wrong that it won't go through the loop properly?
#include<iostream>
#include<iomanip>
#include<fstream>
#include<string>
using namespace std;
int main() {
bool fileFound = false;
[code]....
Write a program that asks the user to type 10 integers of an array. The program will then display either "the array is growing", "the array is decreasing", "the array is constant", or "the array is growing and decreasing."
(Hint: compare consecutive numbers in array and check whether it is increasing or not or constant) I wrote the program very well, but do I have to use "bool" like in c++ ? I haven't known how to code in c++ yet.So, I don't want to use "bool" in C.
I also wrote code about it but it looks like backslash and one,two,three,four,five how can I do it like this ?
Title is self-explanatory.
Code:
#include <iostream>
using namespace std;
int main ( ) {
float number;
float sum;
float divi;
while(number != -1) {
[Code] .....
Write a program that asks the user to enter a student’s grades on four exams. The program should display the four grades and the average of the four grades,rounded to the nearest tenth. To add the grades, use a variable called total_grade, which you should initialize to zero.As the program prompts for and obtains each grade, add the grade to total_grade using the += operator.
View 3 Replies View RelatedI am writing a program that deals with 2d arrays. The program inputs the number of rows and columns and asks for the entries. When the program run and compiles it works perfectly until it outputs then it gives me a warning.
Here is my code:
#include <iostream>
#include <cstdlib>
using namespace std;
int main()
{
int row1=0,col1=0,i,j;
//int a[row1][col1];
int** a= new int*[row1];
[Code]...
I am learning how to do this before I can move on so it can read a text file of numbers.
Also I am having problems with ////delete [] a[];///// I took it out because it made my code compile and run but when I add it in, it gives me an error:
matrixtesting.cpp|56|error: expected primary-expression before ']' token|
I know this expression is suppose to deallocate the array.
The problem that I am having is that , the program outputs numbers that are perfect numbers and im not sure where i can add a statement to make it so that if it isn't a perfect number it doesn't output...
#include<iostream>// allows user input/output
#include<conio.h>
#include<fstream>//data file / result file
#include<iomanip>
#include<cmath> // math function
#define in_file "data.txt"
#define out_file "result.txt"
[Code] ....
Im trying to create a program that has the user input a 5 digit number. If it's between 10000 & 99999, it will do one thing..(just saying 'yes' for now. Outside those numbers will prompt the user to input again. However, if the user inputs the exact digits 76087, it should display 'term'.
This current code is displaying 'term' whenever the user inputs the 5 digits.
Code:
#include <iostream>
using namespace std;
int main() {
int pin;
cout << "Welcome to Movie Food
Enter your 5-digit pin code: " ;
[code]....
So I need to write a program which tells the user if the number they input is prime or not. I have done so and included the code below. My problem is that I need to allow the user to input if they want to enter another number after the first one using y or n and I am having trouble figure it out.
#include <cstdlib>
#include <iostream>
using namespace std;
[Code].....
I'm trying to write a C++ program that will allow a user to input a number from the keyboard. Then using a loop, that will perform 10 times, multiply the entered number by the loop counter. Print out the loop counter, the entered number and the product of the loop counter and the entered number. A one-time heading should be displayed before information is printed.
This kinda of what I have so far:
#include <iosteam>
using namespace std;
int main () {
Start
Declare: numScores, sum, score, avg, SENTINEL = 200
numScores = 0
[Code] ....
All the programs I have tried to make are not working?
I need to create a program that prints a certain number of asterisks based on user input. The user inputs 5 and I want my program to output "*****". How would I do this in C? I've tried printf("%#**", myvariable) but this does not work it only prints "*".
View 1 Replies View Relatedit will not run and im not sure why. I have a couple of errors, but I'm not sure why.
Here is my code.
//Reads input from user to determine different discounts by number of units sold
#include <iostream>
#include <string>
using namespace std;
int main() {
//Declaration and Initialization of variables
int quantity;
double discount,price = 99.00,totalCost;
[Code] ....
I am writing a program for a class where the user enters their age, how much money they have, and their full name. I know that I have to use the getline method to get the user's full name, and I know that I have to use cin.ignore() before that code, but i'm not sure why I have to use cin.ignore()?
View 1 Replies View RelatedI'm making a program for a MMO I play. It calculates the cash and resources needed to build certain 'modules'. I'm having trouble to do something very simple : make a loop until the user asks to break the loop. Here is what the interface looks like :
What module do you want to install?
(Examples: 'Avenger' or 'VLLT')
dd // I input this
DD. COST each : 60,000 cr.
How many do you want? (Modules left:15)
(NOTE : You may enter a negative number if you made a mistake)
3 // I input this
Current Total Module Price : 180000 cr
+6 droids
[Code] ....
The bigger code box below is a part of the code I made. What I deleted is uninteresting, it's just the same thing again : other resources, other 'modules'...
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
int main() {
struct resources// Defines the amount of resources and their price
[Code] ....
write a program that computes the factorial of a number and displays it. A factorial of a number (written N!) is defined as N * (N-1) * (N-2) * (N-3) ... *1 In other words, 5! = 5 * 4 * 3 * 2 * 1 = 120 and 3! = 3 * 2 * 1 + 6.
Example of output 15 is 1.30767e+012
Can't get it to display error when user enters a number lower than 2 or higher 60.
// Program to calculate factorial of a number
#include <iostream>
#include <iomanip>
[Code].....
I have made a program that converts or reverses an input string. Here is my code working fine
static void Main(string[] args){
string input = Console.ReadLine();
string[] words = input.Split(' ')
for (int i = words.Length; i > 0; i--)
Console.Write(words[i - 1] + " ");
Console.WriteLine();
Console.ReadLine();
}
How can I write this program in pseudo code?
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]....
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is then how I could use that concept here.
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]...
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is I can't seem to really get that idea how I could use that concept here. I'm not really good with programming, fairly new at this.
I was wondering what function was the C++ equivalent for testing to see if a user input is numeric.
I have equivalents in Ruby, Java, Python, VB, VBA, php, but being a novice in C++, I have yet to find one - even with Google.
And I know C++ is such a wonderful language, that its extensive library must have one somewhere - considering it's already 2013!
I need to write a program that will allow the user to enter a number "n" and the program tell you that the nth prime number is .....
EXAMPLE
user enters 55
printf("The 55th prime number is %i", variable");