C :: Accept Input Number From User And To Convert It Into Array Of Integer
Oct 7, 2014
i was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h>
int * toarray(int *num);
int main(void)
{
int testCases;
}
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases
23456 //input number
6
2293452
4
2293700
1974439125
Process returned 0 (0x0) execution time : 4.152 s
Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
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Aug 10, 2014
So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
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Jan 29, 2015
Write a C++ application program to accept a signed decimal integer as input and output the equivalent 2s complement version in 16-bit binary. Include a space between every four bits in the output string. The input will only be processed by the application if it falls in the valid range that can be represented in 2s complement format with 16 bits. The range of a decimal number from - to + is -32768 to 32767.
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Oct 28, 2013
I need a program to run that will accept an input for user id. It will take the customer input and capitalize the letters, and return invalid id with the user inputted values. Then if it's valid it will add a counter counting the number of letters and numbers. It will keep track until the user puts in !. It seems when I try to pass values from the array to my toUpper function to capitalize it it doesn't seem to work right.
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Jan 10, 2015
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
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Feb 27, 2012
It seems to be going null. I can't get a null value, I want it to accept input till the user hits enter with no text typed. I've tried checking to see if the input is NULL, "", and " " all to no avail.
Code:
#include <stdio.h>
#include <sys/shm.h>
#include <sys/stat.h>
#include <iostream>
#include <fstream>
#include <string.h>
#include <cstring>
using namespace std;
int main() {
string info = "";
[Code] ....
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Code:
void sumIntegers () {
int arr[50];
int i = 0;
int num = 0;
int sum = 0;
[Code] .....
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Aug 26, 2013
I am having a problem printing out the results for my code, It is supposed to print out the largest and smallest value in the array, but keeps giving me a value not entered and I don't know why.
//This program lets the user enter 10 numbers and then display the highest and lowest number.
#include <iostream>
#include<stdio.h>
using namespace std;
int main() {
const int NUM_ENTERED = 9;
int number[NUM_ENTERED], highestValue = number[0], lowestValue = number[0], count=0;
[Code] .....
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Nov 6, 2014
I need to create A program That makes a 12x10 Array Grid Filled With Random Numbers From 0-99.
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Code:
#include <iostream>
using namespace std;
int main() {
int input;
int number;
int row=0;
int col=0;
int Array [12][10];
[Code] ....
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Sep 16, 2014
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E.g. 20 = 2 x 2 x 5 , Sum = 2 + 2 + 5 = 9
E.g. 10 = 2 x 5 , Sum = 2 + 5 = 7
My method for finding the result is as follows :
- Divide the number by increasing values if int i , starting from i=2.
- Once I get a value of i that can divide the number without giving me a remainder , I add this value of i to int sum and divide the number by i.
- I will repeat this process until the user input value is equal to 1.
My code is as shown:
#include<stdio.h>
int primecheck(int n); // Function to check if i is prime
int primesum(int n); // Function to sum the values of i that are prime
int main(void) {
int n;
int sum;
printf("Enter a number (> 1): "); //Prompting and scanning user input ,n
scanf("%d",&n);
sum = primesum(n);
[Code] .....
But for some reason I keep getting an incorrect result, it's as if it is missing out the last factor for each case.
Eg. 20 = 2 x 2 x 5 , the result I get is 4 , which is 2+2
Eg. 40 = 2 x 2 x 2 x 5 , the result I get is 6 , which is 2+2+2;
I've looked through my code numerous times.
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Is there anyway we can make an integer array to an integer...
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I have to do this without using vectors.
This is what i have, I cannot figure out what to put in main. I was thinking of a do-while?
Code:
#include <iostream>
using namespace std;
void resize(int *[], int);
int main() {
int *listDyn;
int size=2;
[code].....
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Feb 4, 2014
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int main (void)
{
char cn[17];
char *cardtype;
int n0,n1,n2,n3,n4,n5,n6,n7,n8,n9,n10,n11,n12,n13,n14, n15;
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[code]....
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Sep 4, 2013
// prompts the user for a non-negative numbers (>= 0)
// reads in the a number and checks
// keeps re-prompting user if the input is invalid (negative)
[Code].....
How do I go about Populating the elements in the array created, I keep getting a compiler error on this vArr[i] = tmp_stream.str.at(i);
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What I'm trying to do is have the user input a hex number this number will then be converted to a char and displayed to the monitor this will continue until an EOF is encountered.I have the opposite of this code done which converts a char to a hex number. The problem I'm running into is how do i get a hex number from the user I used getchar() for the char2hex program. Is there any similar function for hex numbers?
this is the code for the char2hex program
#include <stdio.h>
int main(void) {
char myChar;
int counter = 0;
while(EOF != (myChar = getchar())) {
if (myChar == '')
[Code] .....
This is what i want to the program to do except it would do this continuously
#include<stdio.h>
int main() {
char myChar;
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scanf("%x",&myChar);
printf("Equivalent Char is: %c",myChar);
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Sep 6, 2013
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Code:
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
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#include<iostream>
using namespace std;
int main() {
int a[9],x,f=1;
cout<<"Please enter an integer [0-10 only] : ";
[Code] ....
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i have mathematic operation and the result is near 70 digits....single variable cannot hold it....
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Jun 29, 2014
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]....
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is then how I could use that concept here.
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Jun 29, 2014
There's this program I'm trying to code where the user gives input of 2 values.
Sample :-
Value of X: 1234
Value of Y: 234567
Reversed value X: 4321
Reversed value of Y: 765432
New value as Z: 1223344567 (each number was taken in both X and Y)
Now the thing is I could do the reverse, and I've been trying to find out how.
Here's my code,
#include <iostream>
using namespace std;
int main(){
int x=0, y=0;
int reverse_x=0;
int reverse_y=0;
int z = 0;
int l;
[Code]...
What I thought about that area where I've put a comment on, I was wondering if I code a loop for the amount of times x gets divided by 10 until it becomes 0 and store it in the value, same thing for Y, and add the value together to get Z. But if that's how it is I can't seem to really get that idea how I could use that concept here. I'm not really good with programming, fairly new at this.
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I was wondering what function was the C++ equivalent for testing to see if a user input is numeric.
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And I know C++ is such a wonderful language, that its extensive library must have one somewhere - considering it's already 2013!
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Heres My Code:
//Assignment 19 Program 2
#include <iostream>
using namespace std;
int main()
[Code].....
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