C++ :: Convert Int Array To Integer
Nov 23, 2013Is there anyway we can make an integer array to an integer...
View 4 RepliesIs there anyway we can make an integer array to an integer...
View 4 Replies I'm just learning and C. Here is a code snippit from a program that will compile. It's function is to validate credit card numbers. I have an error I can't find though. the last print statement shows the conversion in reverse string (as integers). Here is the code:
int main (void)
{
char cn[17];
char *cardtype;
int n0,n1,n2,n3,n4,n5,n6,n7,n8,n9,n10,n11,n12,n13,n14, n15;
int s1,s2,s3,s4,s5,s6,s7,s8;
int oddsum;
int sum;
int total;
int validate;
}
[code]....
// prompts the user for a non-negative numbers (>= 0)
// reads in the a number and checks
// keeps re-prompting user if the input is invalid (negative)
[Code].....
How do I go about Populating the elements in the array created, I keep getting a compiler error on this vArr[i] = tmp_stream.str.at(i);
i was trying to solve a problem in SPOJ and what i wanted to do is to accept an input number from the user and to convert it into a array of integer.
Code:
#include<stdio.h>
int * toarray(int *num);
int main(void)
{
int testCases;
}
[code]....
But whenever i try to print the array in the main function i get only two value and the rest address
Code:
1//number of testCases
23456 //input number
6
2293452
4
2293700
1974439125
Process returned 0 (0x0) execution time : 4.152 s
Press any key to continue. However, if i tried to print the array from within the function, it prints the numbers just fine.
print the array elements from the main program, so that i would be able to go on with the rest of it
i have mathematic operation and the result is near 70 digits....single variable cannot hold it....
View 4 Replies View RelatedI have to implant a code to convert any integer to its 2'complement. I have already finished the first and the second part, which was to convert the integer to its binary representation, then to invert each digit in the binary representation. The third part is to add 1 to the binary representation.
// the last step is to add 1 to the binary number
int carryIn=0;
int carryOut;
for(itr= bainaryList.begin(); itr!= bainaryList.end(); itr++) {
//start comparing the possibilities of the values in both lists
if (((*itr)==0) && (carryIn== 0))
[Code] ....
I need to convert below value char *time="00.00.05".
I need to convert this to hh/mm/ss ....
This is my c++ code...the problem is the RESULT is not coming and a bigger number is outputting...I dont know how to convert character to integer..
Code:
#include <iostream>
#include <math.h>
#include <stdlib.h>
using namespace std;
const int size = 50;
char infix[size],postfix[size],stack[size],dummy='?';
int top=-1;
[Code]....
I'm having a problem converting part of a string to an integer.I used strtok to seperate my string and I have also a function for atoi but how to apply it to my strtok function.What i need is to change the char *years to an int.Have a look of what I got:
Code:
int main() {
char sentence[]="trade_#_2009_#_invest_#_DEALING";
char *word=strtok(sentence, "_#_");
char *year=strtok(NULL, "_#_");; // assigning NULL for previousely where it left off
char *definition=strtok(NULL,"_#_");
char *synonyms=strtok(NULL,"_#_");
[code]...
I have been trying to write a function which can convert a number from an unsigned long integer to a readable ASCII character string. this is what I have come up with, but I am receiving some very strange characters in return. Could the problem be that I am telling a char to = an unsigned long int, (cString[i] = product[i])?
void convertToString(unsigned long con) {
unsigned long product[10];
char cString[10];
const unsigned long begConvert = 10 ^ 10;
[Code] ....
I'm trying to read in two instances of date and time (from user input) into a string value (MM/DD/YY hh:mm).
I need to be able to calculate the difference between the two in order to return how much time has elapsed from the first date/time to the second date/time.
What would be the most efficient way to go about obtaining said results?
I was thinking I need to convert each year, month, day, hour, and minutes into its own integer variable, after researching immensely online I'm still not sure how to convert from a string of characters to an integer.
I am supposed to convert a string made of many numbers between every number spaces are between, to an integer variable for every number..
How am I supposed to get over this problem?
Example: String: " 322 52 231"
I would like to know how I can convert a string which represents a date to an integer.
#include <iostream>
using namespace std;
#include <string>
int main(){
string actual_date("18/10/2000");
int date = ????????
I am trying to read an array values from Tmin.txt file. I take array size from user viz. number of raw & column and then, read the following data from Tmin.txt file which look like this:
20 40 20 25 30
20 30 40 20 25
20 40 20 25 30
20 30 40 20 25
30 40 40 30 40
I am using getline, and then converting it to int by using atoi. But my code is not working.
Code :
// reading a text file
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
[Code] ....
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431
How do I convert date in integer format to DateTime without using DateTime?
I have tried:
Regex regex = new Regex(@"^(0[1-9]|1[012])(0[0-9]|1[0-9]|2[0-9]|3[01])(1[789]|[2-9][0-9])dd+$");
if (regex.IsMatch(txt_fromdate.Text) == true)
{
DateTime dt = DateTime.ParseExact(txt_fromdate.Text, "MMddyyyy", null);
}
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
My intent was to convert the string variable for the year to an integer data type. The code compiles but now cannot run on my system. I'm not sure what's going as to what the program is displaying.
Objective: Prompt the user for two years. Print all Comedy movies that were released between those two years.
#include <iostream>
#include <cstdlib>
#include <string>
#include <fstream>
#include <cctype>
using namespace std;
struct Movie {
string name;
[Code] .....
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
I am having problem in writing the code for the problem "To assign the elements of 1-D integer array into 2-D array of integers such as if the array is 1,2,3,4,5,6 The resultant 2-D array should be like :
1 0 0 0 0 0
1 2 0 0 0 0
1 2 3 0 0 0
1 2 3 4 0 0
1 2 3 4 5 0
1 2 3 4 5 6
"
I'm having trouble converting this binary search with an int array to use a string array..
Code:
#include <iostream>
#include <string>
using namespace std;
// Function prototype
int binarySearch(string [], int);
[Code] .....
I have the following code which attempts to assign a u_int8 array of 256 to an unsigned char[256]:
Code:
unsigned char testData[256]=pSample->data;
I get the compilation error:
error C2440: 'initializing' : cannot convert from 'const uint8_t [256]' to 'unsigned char [256]'
What is the safe way to cast or convert here?
I need to convert an integer, for example 10, to its base 16 equivalent, 16. I found this code that converts a base 16 number to base 10, but I need the opposite. Plus, this code doesn't seem to work properly with input values under 32.
Code:
uint32_t input = 16;
uint8_t temp;
temp = ((input>>8)*100)|((input>>4)*10)|(input&0x0f);
I am writing code to multiply two int arrays and in my one function i am trying to convert the char array into an int array. I have tested many parts however i can not find the problem.
Code:
struct integer* convert_integer(char* stringInt){
struct integer *converted = malloc(sizeof(struct integer));
int length, i, *ints;
ints = (int *)malloc(10001 * sizeof(int));
length = strlen(stringInt);
printf("stringInt: %s with length of %d
", stringInt, length);
converted->size = length;
[Code]...
I want to sort an array like Myarray[3][4] based on the second column while other correspondent rows exchange consequently.
My array is as follows:
3 8 7 2
9 12 0 4
12 2 14 1
I want to sort it based on the second column using “std::qsort" or "std::sort” or other quick method that would lead to the following :
12 2 14 1
3 8 7 2
9 12 0 4
I have an array:
Code: int array1[]={0,1,1,0}
I need to convert the entire array to Hexadecimal.
My first thoughts to the approach was to convert the array to a string then strcmp but i cant seem to find how to convert an array to a string either.
How to convert the array to hexadecimal directly? or, How to convert the array to a string to be strcmp'ed?