C++ :: Convert Positive Integer Into Its English Name Equivalent To Digit?
Jul 13, 2014
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431
I'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code: #include <stdio.h> int main (void) { int x, y = 0; printf ("This program displays each digit of an integer in English.
#include <cstdlib> #include <iostream> #define TRUE 1 #define FALSE 0 using namespace std; typedef int Bool;
[Code] ....
Gives repeated digits in an integer but only in one condition : Only if the repeated digit is the result of n%10 where n is the integer the user writes. If the repeated digit is not the result of n%10 , then the compiler gives a wrong result.
so the question is : how to make this code gives the repeated digit in an integer (regardless the fact that the repeated digit is the result of n%10 or not and especially with making the minimum of changes on the code)????????? ?????
Assignment: Take an integer keyed in from the terminal and extract and display each digit of the integer in English. Ex. 932 --> nine three two
Code:
/*This program takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English.*/ #include<stdio.h> int main(void) { //DECLARE VARIABLES int num; }
[code]....
I don't know how the program works if the integer is more than one digit.
I need to create a program that lists off each digit of an integer and then display the sum off all the digits in that integer. I know that sepereatly the sum function i wrote works. But the first part which i try to list off the digits work but in reverse order which i dont know how to correct. and for some reason that i cant figure out this is affecting the sum output.
#include <iostream> using namespace std; int digcount (int x) {;
I have been working on some C++ code that doesn't seem to be going right. I'm wanting it to read a (three-digit) integer representing the value to be encrypted, a (one-digit) integer representing the encryption key, encrypt the value and print the encrypted value. The encrypting method used is that each digit in the given number is replaced by ((the sum of that digit plus key) modulo 10) then the first and last “encrypted” digits are swapped.
For example, if the number entered was 216 and the key given was 7, after applying the encryption procedure described the first digit (2) would become 9, the middle digit (1) would become 8 and the last digit (6) would become 3. The first and last encrypted digits are then swapped. The program displays the encrypted number: that is 389 in this case.
#include <iostream> using namespace std; int main() { int isolateDigits(); int replaceDigits(); int swapDigit1withDigit3();
Return the digit at the user specified index of an integer. If the integer has n digits and the index is NOT in the range 0 <=index <n return -1 Start the digit numbering at 0. Example, if user input is 4 (index) and the integer equals 123456790 the return value for the function is 5 (start index at 0) ; if user input is 40 (index) and the integer equals 123456790 the return value for the function is -1
#include <iostream> #include <istream> #include <cstdlib> #include <cassert> #include <string> using namespace std; int getIndex(int, int);
You pros are once newbies like us. Hoped you might take a little time sharing your expertise. Got freaked out when our teacher gave us this activity, where she haven't taught this to us yet. So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0
if n = 6 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0 6==5==4==3==2==1==0
I have an embedded microcontroller system communicating with a similar system by radio. The api for the radio requires data to be transmitted as an unsigned char array. It will always transmit a positive integer in the range 0 to 255.When I receive the data I am having difficult in extracting this positive integer.
Code: unsigned char rxData[4]={'1','2','3',''}; int inVal=0;
//want to assign inVal whatever number was transmitted
E.g. 123
I've been at this for a week and have tried at least 10 different approaches including the use of the atoi(), copying the absolute value of each element of rxData into another char array, reinterpret_cast, and others.
The problem states that i need to accept any pin number between "00000" and "99999". I need to read the PIN the user enters as an integer. The problem is that if the PIN is read as an integer, the PIN "01111" will be "1111" which is invalid and the pin "00001" would be read as "1" which is also invalid. How would I go about fixing this problem for PIN numbers that start with a "0"? Again I cannot read the PIN as a char array or string.
Write a program asks the user for a positive integer value and then prints out all perfect numbers from 1 to that positive integer. I have been trying for some time, i found a way to check if its a perfect number or not but could not find a way to prints out all perfect numbers from 1 to that positive integer. I am here so far.
#include<iostream> #include<iomanip> using namespace std; int main(){ int n,i=1,sum=0; cout<<"Enter a number: ";
My question is are there various ways that I can approach this program. I.e. do I have to use switch statements?
/* NumToTxt Creates the appropriate word form of any positive integer up to 999999 */
#include <iostream> using namespace std; //represents the largest array size for the user entered number const int MAXNUMARRAY = 6; /*represents the largest number that can be entered + 1. Used to calculate the first number used to truncate the user entered number and to display an error message to the user that tells the user the largest number that the program will accept. */ const int BIGGESTNUMBER = 1000000;
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0
if n = 6 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0 6==5==4==3==2==1==0
the real char got 1000 digits this is just example how do i convert chars from numbers[4] to numbers[15] and save them as one number ? in this case i will get int x = 5444546546545643 as u can see char numbers as a example above
Design an algorithm using flowchart or pseudo-code to prompt the user for a series of positive integer values. Calculate the average of these values and display the average at the end of the program. Assume that the user types the sentinel value -1 to indicate end of data entry.
Sample input-output: Enter a positive integer (-1 to end) : 5 Enter a positive integer (-1 to end) : 7 Enter a positive integer (-1 to end) : 6 Enter a positive integer (-1 to end) : -1
The average value is: 6
I searched online and found out this solution however it is only for three numbers.Is there any way of modifying this to include the sum of x numbers / number of x(integers) to find the average?
Code: Complete the program below which converts a binary number into a decimal number. Sample outputs are shown belowComplete the program below which converts a binary number into a decimal number. Sample outputs are shown below.
Sample Output 1:
8-bit Binary Number => 11111111 Decimal Number = 255
Sample Output 2:
8-bit Binary Number => 10101010 Decimal Number = 170
Sample Output 3:
8-bit Binary Number => 101010102 Number entered is not a binary number
#include <iostream> using namespace std; int main() { int num;
Write a function which will take 3 arguments. The function needs to return a new number which is formed by replacing the digit on a given position in the number with a digit which is carried as an argument (the position in the number is counted from right to left, starting with one). Write a main program which will print the newly formed number.
Examples: A function call of 2376, 3 and 5 should return the number 2576 A function call of 123456, 4 and 9 should return the number 129456
What I succeeded to do so far: Figure out the logic for swapping the digit and write working code for it (in the main function).
What I failed to do so far: Write a function which will return the desired result.
What is my problem: I tried writing a function to do this, but as you see from my calculations, my result is divided in 3 parts. I don't know how to return more variables from a function.
Code:
#include <stdio.h> int main() { int inputNumber, swapPosition, swapDigit; scanf("%d%d%d", &inputNumber, &swapPosition, &swapDigit); int i, numberPart1 = inputNumber; for (i = 1; i <= swapPosition; i++)
I have to implant a code to convert any integer to its 2'complement. I have already finished the first and the second part, which was to convert the integer to its binary representation, then to invert each digit in the binary representation. The third part is to add 1 to the binary representation.
// the last step is to add 1 to the binary number int carryIn=0; int carryOut; for(itr= bainaryList.begin(); itr!= bainaryList.end(); itr++) { //start comparing the possibilities of the values in both lists if (((*itr)==0) && (carryIn== 0))
I'm having a problem converting part of a string to an integer.I used strtok to seperate my string and I have also a function for atoi but how to apply it to my strtok function.What i need is to change the char *years to an int.Have a look of what I got:
Code: int main() { char sentence[]="trade_#_2009_#_invest_#_DEALING"; char *word=strtok(sentence, "_#_"); char *year=strtok(NULL, "_#_");; // assigning NULL for previousely where it left off char *definition=strtok(NULL,"_#_"); char *synonyms=strtok(NULL,"_#_");
