Constructing this right aligned half pyramid? The code I had so far is right aligned and they're not in numbers
Write a program that receives one positive integer and display
_________ _ 1
________ 4 2
_______9 6 3
___16 12 8 4
25 20 15 10 5
when the user key in 5.PS: ignore the line
You pros are once newbies like us. Hoped you might take a little time sharing your expertise. Got freaked out when our teacher gave us this activity, where she haven't taught this to us yet. So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
if n = 6
0
1==0
2==1==0
3==2==1==0
4==3==2==1==0
5==4==3==2==1==0
6==5==4==3==2==1==0
How to write a function that receives an integer array along with its length. the function calculates and returns the sum of the squares of all the odd numbers in the array?
View 2 Replies View RelatedSo I need to make a program that recieves a 10 letter only password, then once the password is entered, it starts off as AAAAAAAAAA...AAAAAAAAAB...AAAAAAAAAC...etc, Until it gets the correct password, which it then stops. This is for a science fair project on cyber security not for malicious purposes ...
View 2 Replies View RelatedI'm new to C programming and in my first computer science class. Our assignment was to write a program that displays each digit of an integer in English. I wrote the following but cannot figure out why it won't display zeros. When I execute and type in the number 1,000, I get "zero."
Code:
#include <stdio.h>
int main (void)
{
int x, y = 0;
printf ("This program displays each digit of an integer in English.
[Code] ....
I need to have a program display an error message if the variable entered isn't an integer but then I want it to cin again. I have this but it doesn't work:
cout << "Enter an Integer: " ;
for (;;) {
cin >> var;
if (!cin) {
[Code] ....
I am not sure how to do what I want and this doesn't work, it just repeats That wasn't an int.. over and over again.
I am fairly new to the topic of the ethernet and the data link layer and I am trying to write a C program which allows the sending and receiving of ethernet frames.
I am trying to have my program send the ethernet frame to myself, so the program will have the same source and destination mac addresses.
The program that I'm using is a modified version of the code from [URL] ....
I keep having trouble with the recvfrom() function, it seems to just be blocking and the program doesn't terminate. From the code, I am trying send the ethernet frame and have the recvfrom() function be able to retrieve the frame and store it in a buffer. But because recvfrom() function is just blocking, it seems to me that the sendto() function was not able to successfully send the frame.
Here is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/socket.h> /* Must precede if*.h */
#include <linux/if.h>
#include <linux/if_ether.h>
[Code] ....
This is on a linux machine ....
Write a program to enter the number till 100 till the user want and at the end it should display the count of positive and negative and zero entered.
View 8 Replies View RelatedI have an embedded microcontroller system communicating with a similar system by radio. The api for the radio requires data to be transmitted as an unsigned char array. It will always transmit a positive integer in the range 0 to 255.When I receive the data I am having difficult in extracting this positive integer.
Code:
unsigned char rxData[4]={'1','2','3',''};
int inVal=0;
//want to assign inVal whatever number was transmitted
E.g. 123
I've been at this for a week and have tried at least 10 different approaches including the use of the atoi(), copying the absolute value of each element of rxData into another char array, reinterpret_cast, and others.
Write a program asks the user for a positive integer value and then prints out all perfect numbers from 1 to that positive integer. I have been trying for some time, i found a way to check if its a perfect number or not but could not find a way to prints out all perfect numbers from 1 to that positive integer. I am here so far.
#include<iostream>
#include<iomanip>
using namespace std;
int main(){
int n,i=1,sum=0;
cout<<"Enter a number: ";
[Code] ....
My question is are there various ways that I can approach this program. I.e. do I have to use switch statements?
/*
NumToTxt
Creates the appropriate word form of any positive integer up to 999999
*/
#include <iostream>
using namespace std;
//represents the largest array size for the user entered number
const int MAXNUMARRAY = 6;
/*represents the largest number that can be entered + 1. Used to calculate the first number used to truncate the user
entered number and to display an error message to the user that tells the user the largest number that the program will
accept. */
const int BIGGESTNUMBER = 1000000;
[Code] .....
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO)
if the input is 23456 the output is : TWO THREE FOUR FIVE SIX
if the input is 9349 the output is : NINE THREE FOUR NINE
if the input is 245 the output is : INVALID CODE (3 DIGITS)
if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code
step 2 : count the number of digits in the code
step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4
step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS)
step 5 : call a function called digit_name to convert each digit into its
equivalent english name. display the result
step 6 : print the digits in reverse order
eg; if input is 13453, reverse order is 35431
The Program must allow users to enter any two positive numbers and then display the results.
#include <iostream>
using namespace std;
class ArithmeticOperators{
private:
int x;
int y;
public:
void set_values();
[Code] .....
Design an algorithm using flowchart or pseudo-code to prompt the user for a series of positive integer values. Calculate the average of these values and display the average at the end of the program. Assume that the user types the sentinel value -1 to indicate end of data entry.
Sample input-output:
Enter a positive integer (-1 to end) : 5
Enter a positive integer (-1 to end) : 7
Enter a positive integer (-1 to end) : 6
Enter a positive integer (-1 to end) : -1
The average value is: 6
I searched online and found out this solution however it is only for three numbers.Is there any way of modifying this to include the sum of x numbers / number of x(integers) to find the average?
A problem that lets the user enter any positive integer, but you do not have to check for this, and then calculates the sum of the digits and displays this to user. For example, if user enters 14503, the outputted sum of the digits would be 13.
Here is my program
#include <iostream>
int main(void) {
int integer, sum=0;
while(integer) {
sum += integer % 10;
integer /= 10;
} cout << "The sum of the integers numbers is " <<sum;
return 0;
}
My program uses a while loop to eventually get to an error of zero and a root of sqrt(3). I'm not understand why after the third iteration the program fails to compute a new x value. I'm using Visual Studio 2013. The code tag instructions were dubious.
Code:
#include <stdio.h>
#include <math.h>
main() {
/*This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots.*/
printf("This program uses the Newton-Raphson method to solve y = (x^3)-3 for it's roots. Enter your estimate of the root.
");
float x,y,z;
int num;
num = 0;
[Code]...
I'm trying to get my C program to compile but it's not working at all. I've programmed a little in C++ before but I'm not used to C. Here's my program so far:
Code:
int main(void){
// Establishes variables
int num1, num2, product;
float quotient;
[Code] .....
It keeps giving me an error message as follows:
"/usr/bin/ldrelabwk2: file format not recognized; treating as linker script
/usr/bin/ldrelabwk2:1: syntax error
collect2: ld returned 1 exit status"
Write a program that calculates the average of a stream of positive numbers. The user can enter as many positive numbers as they want, and they will indicate that they are finished by entering a negative number. For this program, treat zero as a positive number, i.e., zero counts as a number that goes into the average. Of course, the negative number should not be part of the average. You must use a function to read in the numbers, keep track of the running sum and count, compute the average, and return the average to the main() function. Note that you must use a loop to do this, as you don't know how many numbers the user will enter ahead of time. I am having problem writing a loop program for it..
View 1 Replies View RelatedI'm writing the program below to take an integer input for temperature and display a cheesy message for different ranges for each day of the week.
I tried using two if statements, the first to determine if the input is valid, and the else display that it was invalid and to try again.
The second set of if (if else) statements would evaluate a number input and display the cheesy message based on the value, or if it was out of range, to make you re input that days temperature.
I understand that the else statement is linked to the closest if statement, unless brackets are added to prevent this. I thought my brackets were correct, but I keep getting [Error]'else' without previous if'. The red lines are the if and else statement I'd like to be linked, and tried to do so by enclosing the 2nd if statement in brackets.
The assignment doesn't require the error checking, but if I don't use some form of it I believe it will just loop. Again I have to use the last 4 lines due to instructors rules, and have to use scanf and not strings or arrays.
This program will ask the user what the temperature will be for each day of the week. The integer input from the keyboard will be tested in a series of IF tests and a message will be printed depending on the temperature.
Code] ....
#include <stdio.h>
#define MAX 100
#define MIN 0
int main() {
int day = 1;
int temp;
[Code] ....
I have an assigment and I don't know yet how to write this program :" I introduce the average monthly temperatures of a year(12 values for 12 months). When I compile the program it needs to show the highest negative temparature and the lowest positive temperature of that year.
Example: Entry data: -4 -6 0 5 10 20 24 25 17 8 -1 -7 exit data : max negative= -1 and min positive= 5 "
I have a problem with this work. It is that when the server send some data to the client it send them correctly but when they arrive to the client all the info are changed and i don't know why, because i print them before the send and they are right, but after they arrive to the client the data doesn't be the same.
here it is the server and client's code. In the code there are some italian words, but there are only constant, so there is a real problem to understand the code.
Server
#include <stdio.h>
#include <string.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <stdbool.h>
#define FLUSH while(getchar()!='
[code]....
the problem is in the line 136 of the server and on the line 203 of the client
There is one question :
Considerint A[10]={ ....................}; // already filled
int B[10]={ ....................}; // already filled
Using PIONTER NOTATION ONLY, write a function that receives two arrays of integers like A and B above. The function should swap the values in A and B. You may NOT use array notation [ ]. Also, you have to use pointers to move among array cells. Note: Both arrays are of the same size, and size should be variable in the function.
I am trying to send 0x20 from arduino and get the hex in c program on the pc iam using RS-232 for Linux and Windows lirary for rs232 communication and when i send 0x20 i get 28ef30 i dont know why.. but i want to get 20 integer type value in c program the code that i use in c is
Code:
n = PollComport(cport_nr, buf, 4095);
if(n > 0)
{
buf[n] = 0; /* always put a "null" at the end of a string! */
}
[code]....
C++: write a c++ program that will display your name, address and age..
View 3 Replies View Relatedi wrote this program to display even number from 100-200. But visual c gives me this error with undeling the "a" in if statement. Error1error C2106: '=' : left operand must be l-value
#include<iostream>
#include<conio.h>
using namespace std;
void main(){
for(int a=100;a<200;a++){
if(a%2=0)
cout<<a<<endl;
}
_getch();
}
