How to write a function that receives an integer array along with its length. the function calculates and returns the sum of the squares of all the odd numbers in the array?
View 2 RepliesAny good function that get the length of an integer in C++
I do know of str.length(), however i want something similar for integers
Constructing this right aligned half pyramid? The code I had so far is right aligned and they're not in numbers
Write a program that receives one positive integer and display
_________ _ 1
________ 4 2
_______9 6 3
___16 12 8 4
25 20 15 10 5
when the user key in 5.PS: ignore the line
There is one question :
Considerint A[10]={ ....................}; // already filled
int B[10]={ ....................}; // already filled
Using PIONTER NOTATION ONLY, write a function that receives two arrays of integers like A and B above. The function should swap the values in A and B. You may NOT use array notation [ ]. Also, you have to use pointers to move among array cells. Note: Both arrays are of the same size, and size should be variable in the function.
How can I obtain the length of an array that has been sent throughout a function. In the following code, I obtain "2" as output, while I was expecting "5".
void call(int a[]) {
cout<<sizeof(a)/sizeof(int);
}
int main() {
int* a=new int[5];
call(a);
}
How can I properly call this function so I can obtain the correct array size?
The programming problem is supposed to take a decimal number from a user and turn it into a binary number. Here is my code:
for (int i=0; i< count; i++) {
binary[i] = decimal % 2;
decimal = decimal/2;
} cout << binary[2] << endl;
decimal is the number entered by the user.
binary [] is the char array and count is... you know how many times the for loop will turn. So my question is, how do i know the length of the number ? Any function that shows the integer length ? because its impossible to know what count is equal to. like 100 is 3.
I intend to reference this thread from another thread so I do not clutter that thread with code
/* This code is relied on by some of the functions I will post */
typedef unsigned long long zxumax;
typedef signed long long zxsmax;
[Code]....
I already have the standard one that mimics the one taught in schools written but I've found that there is a faster formula that can be used however I not sure how to implement this. The formula is called the "Fast Fourier Transform", any simplistic example using this function base:
typedef unsigned int uint;
typedef unsigned char uchr;
uint umul( uint* src, uint val ) {
uint des = *src;
[Code] ....
If you're doing the buffer based functions then I have some pre-made functions you may need. [URL]
On a controlled buffer of unsigned char it is possible to do subtraction faster than if you followed standard mathematical rules, here is an example:
typedef unsigned char uchr;
uchr num1 = 5; //00000101
uchr num2 = 3; //00000011
num2 = ~num2; // 11111100
++num2; // 11111101
uchr num3 = num1 + num2; // 00000010(2) - computer truncates result to fit char
Since you will be working with a buffer you don't even need to worry about truncating the final bit because the add function will not be able to reach it - unless it is given the ability to grow the buffer in which case you just set the bit to 0 yourself
What I'm trying to do is to assign the length of a string to an integer variable. This is what i tried, it did not work.
Code:
printf("Enter a string
");
fgets(test_pass, 30, stdin);
strcpy(x,(strlen(test_pass)));
printf("%d", x);
This was just a test, and it did not compile. How to do this?
The problem is how to return an array of integer from a function?
I'm writing a C program code to return an array of integers ( grades of students ) to the main function!
Code:
#include <stdio.h>
void define (int integer, int IntArr[0], int *IntP);
int main(void)
{int integer = 0, IntArr[1] = {0}, IntP = 0;
define(integer, IntArr, &IntP);
[Code]...
Why does the integer with array change after passing trough the function and the normal integer doesn't? (I know why the normal one doesn't, but I dont get the array one)
I'm writing a function that stores a number into an array. If the number is greater that the lowest number in the array then it replaces it. The array size is 10. When the number is stored in the array. The lowest number must then be remove.
View 3 Replies View RelatedI'm writing code to create an array of integer and let user input choice to display, replace, add new element, etc.I created a header file in the header file there's a function:
Code:
int display_one_element(int* array, int num_of_elements, int position) {
if(num_of_elements < position || position < 0) {
printf("Position out of bound.
");
return 1;
}
return array[position-1];
}
in main I write a function call:
Code:
display_one_element(array, *p_num_elements, position);
My code seems to work fine but there's an error message right next to my function call:
1.too many arguments provided to function like macro invocation
2.Expression result unused
I tried to move the function from header file to c source file. but other functions in the header file works fine and this doesn't work with the error message.
I have an assignment which requires me to do the following:
Required to write a function that finds an integer in an array and returns its corresponding index. The function must be called findNumber. It must have FOUR parameters:
- The first parameter is the array to be searched
- The second parameter is the integer to be found within the array
- The third parameter is the size of the array
- The fourth parameter is an integer that indicates whether the array is sorted. A value of 1 means the array is sorted; a value of zero means the array is not sorted.
Since a function can only return one value(To return the position of a required integer in an array in this instance) I have tried to make use of pointers to try and return a value stating whether the array is sorted or not.This is my code : (It compiles perfectly but it does not produce any outputs)
Code:
#include <stdio.h>
#define SIZE 10
size_t findNumber(int *sort, const int array[],int key,size_t size);
int main(void){
int a[SIZE];
size_t x;
[code].....
I am trying to assign the integer value to unsigned char array. But it is not storing the integer values. It prints the ascii values. Here the code snippet
Code: uchar uc[100];
for(i=0;i<100;i++)
{
uc[i] = i;
}
The values which are stored in uc[] is ascii values.I need the integer values to be stored in uc[]. I tried to do it with sprintf. but the output is not as expected. if I print the uc[i] it should diplay the value as 0,1,2....99.
So I need to make a program that recieves a 10 letter only password, then once the password is entered, it starts off as AAAAAAAAAA...AAAAAAAAAB...AAAAAAAAAC...etc, Until it gets the correct password, which it then stops. This is for a science fair project on cyber security not for malicious purposes ...
View 2 Replies View RelatedI have a problem with this work. It is that when the server send some data to the client it send them correctly but when they arrive to the client all the info are changed and i don't know why, because i print them before the send and they are right, but after they arrive to the client the data doesn't be the same.
here it is the server and client's code. In the code there are some italian words, but there are only constant, so there is a real problem to understand the code.
Server
#include <stdio.h>
#include <string.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <netdb.h>
#include <stdlib.h>
#include <string.h>
#include <unistd.h>
#include <stdbool.h>
#define FLUSH while(getchar()!='
[code]....
the problem is in the line 136 of the server and on the line 203 of the client
I'm just wondering, why you have to set the length of the inner arrays declaring a function. In which moment does the code needs to be sure about the length of the inner arrays accessing an cell?
I came up with this question realizing the elements of the outer array beeing pointers to the first value of each inner array. Therefore I can access e.g. the first first element of the second inner array like this:
**(arr + 1) ...regardless of the length of any array to my mind.
parallel post: [URL]...
I am fairly new to the topic of the ethernet and the data link layer and I am trying to write a C program which allows the sending and receiving of ethernet frames.
I am trying to have my program send the ethernet frame to myself, so the program will have the same source and destination mac addresses.
The program that I'm using is a modified version of the code from [URL] ....
I keep having trouble with the recvfrom() function, it seems to just be blocking and the program doesn't terminate. From the code, I am trying send the ethernet frame and have the recvfrom() function be able to retrieve the frame and store it in a buffer. But because recvfrom() function is just blocking, it seems to me that the sendto() function was not able to successfully send the frame.
Here is my code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/socket.h> /* Must precede if*.h */
#include <linux/if.h>
#include <linux/if_ether.h>
[Code] ....
This is on a linux machine ....
I'm working with arrays that might have NULL bytes in them and I'm wondering how to determine the length of the array or store it somewhere with the array (strlen() won't work because of the NULL, right?).
I've found advice like store the length of the array in the first byte of the array, but since sizeof(size_t) is 8 should I leave the first 8 bytes for the length?
Would it be better do define my own structure which would store the array and its length? What's the usual way these things are handled in practice?
I was reading in a book I had about C that an array has at the very end a "null character" signifying the end of the string inside it, "/o". So that made me think, "I guess one needs to declare arrays as having 1 extra space than one expects the array to need. I wonder what will happen if I exceed the array length?" So I made a program to test it out. Here is the program/results:
Code:
#include <stdio.h>
int main(void){
char name[3];
printf("
What's your name?
");
scanf("%s", name);
}
[code]....
As you can see my name was able to fit in the array somehow even though I only allocated 3 bytes to the array. I tried again using my legal first name, Benjamin, and it was still able to fit. How is the array able to hold my name when I declared it as only having 3 bytes?
i having a code to pass in array as argument, but the length returned is 1. This is not match with the array size.
int Getsize(int Array[])
{
int len = sizeof(Array)/sizeof(int);
cout << len << "
";
}
int main()
{
int X[] = {45, 12, 54, 83, 41, 36};
getsize(X);
}
I can't find any method of retrieving the length of an array except for doing this:
string first[] = {"a","be","see"};
int length = sizeof(first)/sizeof(first[0])
This is a very unconventional way of getting the length of an array.
first->length() would return 1 because it returns the number of letters in the first element of the array (which actually makes no logical sense).
first.size() would return 1 aswell as it's practically the same thing.
Since getting the length of an array is such a fundamental feat, how come I can't find a decent method of doing it?
Is there no buildt in method for this? If there is not, why has it not been implemented in the std?
I have a program with the following code, and I need to be able to either change the value of any or all of the strlen or to replace one or all with a temp array value. All values of the expression are arrays.
if (::strlen(tc_buf) + ::strlen(maxtime_buf) + ::strlen(" ") < sizeof(localBuf))
I'm trying to make an application and I need the length of the array of a struct. Like this:
struct myStruct {
int integer;
};
myStruct struct[] =
{
1,
2,
};
I want to get how many ints are in the array...