I have a program with the following code, and I need to be able to either change the value of any or all of the strlen or to replace one or all with a temp array value. All values of the expression are arrays.
if (::strlen(tc_buf) + ::strlen(maxtime_buf) + ::strlen(" ") < sizeof(localBuf))
im new to c++ ,so my question is how do i change a length of a text. for example hi my name is blah blah blah. nice to meet you. (n i want every lines to have 8 chars how do i do that)
(hi__my__
name_is_
balh____
blah____
blah____
._nice__
to_meet_
you.) (_ equal space)
I'm working with arrays that might have NULL bytes in them and I'm wondering how to determine the length of the array or store it somewhere with the array (strlen() won't work because of the NULL, right?).
I've found advice like store the length of the array in the first byte of the array, but since sizeof(size_t) is 8 should I leave the first 8 bytes for the length?
Would it be better do define my own structure which would store the array and its length? What's the usual way these things are handled in practice?
I was reading in a book I had about C that an array has at the very end a "null character" signifying the end of the string inside it, "/o". So that made me think, "I guess one needs to declare arrays as having 1 extra space than one expects the array to need. I wonder what will happen if I exceed the array length?" So I made a program to test it out. Here is the program/results:
Code:
#include <stdio.h>
int main(void){
char name[3];
printf("
What's your name?
");
scanf("%s", name);
}
[code]....
As you can see my name was able to fit in the array somehow even though I only allocated 3 bytes to the array. I tried again using my legal first name, Benjamin, and it was still able to fit. How is the array able to hold my name when I declared it as only having 3 bytes?
i having a code to pass in array as argument, but the length returned is 1. This is not match with the array size.
int Getsize(int Array[])
{
int len = sizeof(Array)/sizeof(int);
cout << len << "
";
}
int main()
{
int X[] = {45, 12, 54, 83, 41, 36};
getsize(X);
}
I can't find any method of retrieving the length of an array except for doing this:
string first[] = {"a","be","see"};
int length = sizeof(first)/sizeof(first[0])
This is a very unconventional way of getting the length of an array.
first->length() would return 1 because it returns the number of letters in the first element of the array (which actually makes no logical sense).
first.size() would return 1 aswell as it's practically the same thing.
Since getting the length of an array is such a fundamental feat, how come I can't find a decent method of doing it?
Is there no buildt in method for this? If there is not, why has it not been implemented in the std?
I'm trying to make an application and I need the length of the array of a struct. Like this:
struct myStruct {
int integer;
};
myStruct struct[] =
{
1,
2,
};
I want to get how many ints are in the array...
I am working on a c-programm. In this program I have to convert the amount of money I read on two variables into the corret format. I got Euros and cents on 2 ints. But now I want to add both of those variables in a String (char array). Also i want to find out the length of the new char array.
View 2 Replies View RelatedHow can I obtain the length of an array that has been sent throughout a function. In the following code, I obtain "2" as output, while I was expecting "5".
void call(int a[]) {
cout<<sizeof(a)/sizeof(int);
}
int main() {
int* a=new int[5];
call(a);
}
How can I properly call this function so I can obtain the correct array size?
How can i change or add a cell to an array without knowing its length ? (I mean that I shouldn't know the length I need to make the length dynamic so i can add a cell)we just learned Dynamic assignment(I hope this is the correct name) and Pointers.
View 5 Replies View RelatedThis code snippet compiles and runs fine
Code:
#include <stdio.h>
int main(void) {
int i, a[i];
i=2;
for(int n=0; n<=i; n++)
a[n]=0;
[Code] .....
It prints out 3 "0", but when slightly changed
Code:
#include <stdio.h>
int main(void) {
int i, a[i];
i=200;
for(int n=0; n<=i; n++)
[Code] ....
It compiles fine but core dumps when run, how come? i'm using gcc version 4.4.7, and compiling like this
gcc -std=c99 test.c -o test
The WinAPI has a struct like this for raw input:
Code:
typedef struct tagRAWINPUT { RAWINPUTHEADER header;
union {
RAWMOUSE mouse;
RAWKEYBOARD keyboard;
RAWHID hid;
} data;
[code]...
The definition of the struct doesn't show it but the documentation says that bRawData is variable length. sizeof(RAWINPUT) will not be the correct size when the data field is of RAWHID type so how do you allocate a variable with automatic storage type that has the right size for the entire struct? You can get a header that has the size for the entire struct but how do you actually allocate storage space for the data without using malloc? I've seen some example code that used a char array but that violates aliasing rules and there are also alignment issues with that approach.
I believe that everything is fine except that I can think of the condition can be inserted inside the parentheses ..
#include <iostream>
using namespace std;
int main() {
int i=0, k=0;
char *string_n, **matrix, temp;
[code].....
How to write a function that receives an integer array along with its length. the function calculates and returns the sum of the squares of all the odd numbers in the array?
View 2 Replies View Relatedi have to read a file with between 5 and 10 pairs of numbers, each on a different line. i can read the file, and wrote something to save the length of the file as a variable, but when i use it i start returning crazy data. the problem is in the do while loop and i want to change the i< in the for loop to "lines" so the code stops when the last digit is read. if i use i<10 the file has extra digits is the file is only 8 or 5 pairs of numbers.
FILE *Fpointout;
FILE *Fpointin = fopen ("test.txt","r"); //read this one
Fpointout = fopen ("out.txt","w"); //write this one
if (Fpointin == NULL) //if no file in source {
printf ("File does not exist."); //tell user it is not there
[Code] .....
I want to ask for a number as an input during runtime and then create an 2-dimensional array of size as specified by user. i.e. if the user inputs 3, the array should be of size 3X3, and likewise...
View 9 Replies View Relateduse 2D array in function and change the array values. I do not know if I can use array by calling from a function. I have 6 row 6 column array, I used it inside a function and for the another function I just need to change 4. row 4. column and I do not want to type array to just change one part. I do not know if there is another way or not
View 7 Replies View RelatedI want to pass an array to a function and change the array, how can I do that?
Code:
#include<stdio.h>
/*function to change the array*/
void rearng(int *qw) {
int i,j,a;
int sa[8]; //temp array
int c = 0;
int high;
[Code] ....
My coin/money change code works when there can be an exact change each time, i.e. when the 1 cent option is available. However, when the change options are only $10, $5, $1, 25 cents and 10 cents, it does not give me what I want for instance, I wanted to get change for $237.80, I was expecting to get:
23 10's, one 5, two 1's and 8 dimes. However, the code below is giving me 23 10's, one 5, two 1's and 3 quarters (there is no option left for the 5 remaining cents).how to fix it?
Code:
#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
void change(double cents, int a[]);
int main() {
double Dollars;
double cents;
[code]...
So this is the code I have so far, I didn't know it had to be a dynamic array so how would I Utilize dynamic array allocation to size the modal array
#include <iostream>
using namespace std;
int main() {
const int arraySize = 25;
const int patternSize = 10;
[Code] ....
how can i change the array value and display the updated value. for example this is the output beginning of the program
-----------------------------------------------------
Part Description Number of parts in the bin
----------------------------------------------------
valve 10
Bearing 5
Bushing 21
Coupling 7
[Code].....
#include <iostream>
#include <string>
using namespace std;
[Code]....
// dynamic memory for 2D char array
char **board = (char**) calloc(column, sizeof(char*));
for(int i=0; i<column; i++)
board[i] = (char*) calloc(row, sizeof(char));
//for char 255 row and colum
char temp[255];
inputFile.getline(temp,255);
[Code]...
so i want to change into vector class like Vector<board>row;
Code:
#include <stdio.h>
void define (int integer, int IntArr[0], int *IntP);
int main(void)
{int integer = 0, IntArr[1] = {0}, IntP = 0;
define(integer, IntArr, &IntP);
[Code]...
Why does the integer with array change after passing trough the function and the normal integer doesn't? (I know why the normal one doesn't, but I dont get the array one)
why does this give me an error when i try to change the elements of the char string array.
code:
int main(void)
{
char *name = "aaa";
// setup the name
name[0] = 'Z';
name[1] = 'e';
name[2] = 'd';
name[3] = '';
return 0;
}
[code]....
This code ran well until i added in the ToLower function which is supposed to convert the char array string to lower case (based off ascii strategy -32). correct this function so it converts string to lower case and doesn't get errors.
#include <iostream>
#include <string>
using namespace std;
const int MAX = 81; //max char is sting is 80
void ToLower(char s[]);
int main(){
string y_n;
[Code]...