use 2D array in function and change the array values. I do not know if I can use array by calling from a function. I have 6 row 6 column array, I used it inside a function and for the another function I just need to change 4. row 4. column and I do not want to type array to just change one part. I do not know if there is another way or not
View 7 Replieshow can i change the array value and display the updated value. for example this is the output beginning of the program
-----------------------------------------------------
Part Description Number of parts in the bin
----------------------------------------------------
valve 10
Bearing 5
Bushing 21
Coupling 7
[Code].....
I want to pass an array to a function and change the array, how can I do that?
Code:
#include<stdio.h>
/*function to change the array*/
void rearng(int *qw) {
int i,j,a;
int sa[8]; //temp array
int c = 0;
int high;
[Code] ....
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code:
#include<stdio.h>
void display(int array[],int size) {
int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
Code:
#include <stdio.h>
void define (int integer, int IntArr[0], int *IntP);
int main(void)
{int integer = 0, IntArr[1] = {0}, IntP = 0;
define(integer, IntArr, &IntP);
[Code]...
Why does the integer with array change after passing trough the function and the normal integer doesn't? (I know why the normal one doesn't, but I dont get the array one)
This code ran well until i added in the ToLower function which is supposed to convert the char array string to lower case (based off ascii strategy -32). correct this function so it converts string to lower case and doesn't get errors.
#include <iostream>
#include <string>
using namespace std;
const int MAX = 81; //max char is sting is 80
void ToLower(char s[]);
int main(){
string y_n;
[Code]...
Goal: Write a program that compares the values stored in the first array to the user inputted values in the second array.
In order to fix this error: [URL]...
I had to change my array initialization to one with a star in front of it:
char a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
to:
char *a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
I also changed my 2nd array to one with a star in front of it: char *a2[20];
What does this mean exactly? Putting a star in front of an array?
Also, I am now getting an "unhandled exception" when I try to get input for my 2nd array:
cin>>a2[i];
I have been trying to make a function that compares all the values of the array and if they are all equal will return a value to print true. The problem I am having is that regardless of what values I enter the function is always returning true. Any way to tell the program o check all the values in one command instead I put them each,
Code:
#include<stdio.h>
#include<stdlib.h>
int compare(int arrayA[], int arrayB[]);
[Code]....
This read a file (arrival time , brust time) for n processes and suppose to do shortest job first scheduling. the file read correctly but passing the value to SJF function gives read of 0's to all values .
#include<stdio.h>
#include<stdlib.h>
typedef struct {
int brust_time[10];
int arrival_time[10];
}Time;
[Code] .....
I know that the issue is around the array distance being of type double in the function get distance of type double. My question is how do i get around using the values from the distance array in the function to be used for calculations.
#include <stdio.h>/* initialization of preprocessor directives*/
#include <stdlib.h>
#include <math.h> /*preprocessor directive in order to use sqrt function*/
int calcSecondsvar(int,int,int ,double);
double getdistance(double,double,int,int,int);
[Code] ....
I forgot to mention that it keeps giving me the error cannot convert from 'double[8] to 'double' ....
// I believe my loop for the functions work but the values are not returning !
// Acoustic data
#include <iostream>
#include <fstream>
using namespace std;
double low( double []);
double high( double []);
void readArrayr( double [], double , double);
[Code] .....
I am required to write a program which, when given an nxn 2D array of char, and the specified coordinates of a specific point in that array, returns thelargest number of horizontal, vertical or diagonal contiguous (side-by-side) sequence of points of that same char value that intersects with the given point.
The way I took on this problem was to:
1) First find out the number of points with the same char value up, down, right, left, north-east, north-west, south-east, and south-west of the given point.
2)Add up+down+1(the one is for the point itself), north-west+south-east+1, etc...
3) Finally I compared the four values (updown, rightleft, NESW, NWSE) and returned the largest one.
Well, that's how the program is supposed to work in theory but as you can probably guess it doesn't work. In addition to telling me what I'm doing wrong, is there a simpler way to do what I am trying to accomplish?
Here's the code:
Code:
int findLongest(char **board, int n, int row, int col)
{
char current;
int rightleft, updown, NESW, NWSE;
int r, c, c1=0, c2=0, c3=0, c4=0, c5=0, c6=0, c7=0, c8=0, d;
int t1=1, t2=1, t3=1, t4=1, t5=1, t6=1, t7=1, t8=1;
current=board[row][col];
//check Above: col remains the same
for(r=row-1;r>=0||t1!=0;r--)
//with the condition r>=0 I made sure not to accidentally check values outside of the array
[Code]...
I am so close to finishing this program. It will find the median of an array of 5 values. I have one last error that I cannot seem to get to go away. Here's the code:
#include <algorithm>
#include <functional>
#include <array>
#include <iostream>
using namespace std;
int main() {
int integer1, integer2, integer3, integer4, integer5;
[Code] .....
The error states: "IntelliSense: no instance of overloaded function "std::nth_element" matches the argument list, argument types are: (std::_Array_iterator, std::_Array_iterator, unsigned int, std::_Array_iterator)
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) {
if (cards[0]) {
hideFirstCard=true;
cards[0] = '**';
} for(int a = 0; a <= numCards; a++) {
cout >> showCard(cards[a]);
} }
But it can the other way around
Code:
static_Array= dynamic_Array;
dynamic_Array = static_Array;
The second statement works and i'm able to print out both arrays with equal values but with the first
[code] static_Array = dynamic_Array;I get incompatible types in assignment of 'int*' to 'int [7]' is the error I get [/code]
My program takes the values from one array and searches for their index position in another array (linear search algorithm). This is an example of the issue im having(its not part of the actual code below)
a[]={1,2,3,4,5,6}
Arr[]={1,2,2,3,4,5}
If it finds 1 in arr, it returns 0, which is fine but if it finds 2 in arr it return 1 and 1 instead of 1 and 2.
for (int q=0; q=size2;q++) {
int rs=secfunc(array1;size1;array2[q])
if(rs>=0) {
cout<<rs << "";
[Code] .....
How can I Figure out and store the sum of EACH COLUMN in the 2D array values in a 1D array? And to the same for the average?
View 1 Replies View RelatedSo this is the code I have so far, I didn't know it had to be a dynamic array so how would I Utilize dynamic array allocation to size the modal array
#include <iostream>
using namespace std;
int main() {
const int arraySize = 25;
const int patternSize = 10;
[Code] ....
I have a program with the following code, and I need to be able to either change the value of any or all of the strlen or to replace one or all with a temp array value. All values of the expression are arrays.
if (::strlen(tc_buf) + ::strlen(maxtime_buf) + ::strlen(" ") < sizeof(localBuf))
#include <iostream>
#include <string>
using namespace std;
[Code]....
// dynamic memory for 2D char array
char **board = (char**) calloc(column, sizeof(char*));
for(int i=0; i<column; i++)
board[i] = (char*) calloc(row, sizeof(char));
//for char 255 row and colum
char temp[255];
inputFile.getline(temp,255);
[Code]...
so i want to change into vector class like Vector<board>row;
why does this give me an error when i try to change the elements of the char string array.
code:
int main(void)
{
char *name = "aaa";
// setup the name
name[0] = 'Z';
name[1] = 'e';
name[2] = 'd';
name[3] = '';
return 0;
}
[code]....
Write a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
View 6 Replies View Relatedim trying to read in 1 array and get 2 as outputs from 3 different functions.my read array is easy enough were im getting confused is how to read that array, separate it and take out only the parts i want and place them into a 2nd, then again a 3rd array.i have the following so far:
Code:
#include<stdlib.h>#include<stdio.h>
#include<unistd.h>
#define SIZE 10
}
[code]....
this compiles without a complaint, but when i go to run it no longer responds after taking the 10th element (well 9th if counting from 0).I think i have the if correct for the even odd section, but when i try to populate B or C array with the output of that if statement from A is were i think things are dying...
I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
Its output is not correct
#‎include <stdio.h>
void main() {
int n,i,j,option;
int evensum=0;
int oddsum=0;
[Code] ....