how can i change the array value and display the updated value. for example this is the output beginning of the program
-----------------------------------------------------
Part Description Number of parts in the bin
----------------------------------------------------
valve 10
Bearing 5
Bushing 21
Coupling 7
[Code].....
use 2D array in function and change the array values. I do not know if I can use array by calling from a function. I have 6 row 6 column array, I used it inside a function and for the another function I just need to change 4. row 4. column and I do not want to type array to just change one part. I do not know if there is another way or not
View 7 Replies View RelatedGoal: Write a program that compares the values stored in the first array to the user inputted values in the second array.
In order to fix this error: [URL]...
I had to change my array initialization to one with a star in front of it:
char a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
to:
char *a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
I also changed my 2nd array to one with a star in front of it: char *a2[20];
What does this mean exactly? Putting a star in front of an array?
Also, I am now getting an "unhandled exception" when I try to get input for my 2nd array:
cin>>a2[i];
I have a program that makes change from an amount. It works fine, but the output is the correct output looped over and over. I have tried everything, but it still doesn't work. For example, a amount of 98 should print
3 quarters
2 dimes
0 nickles
3 pennies
but instead it prints
3 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
Why it's doing this?
Code:
#include <iostream>
using namespace std;
int coinscount(int& amount, int value) {
int tracker = 0;
int amountdimes = amount;
[Code].....
I want to pass an array to a function and change the array, how can I do that?
Code:
#include<stdio.h>
/*function to change the array*/
void rearng(int *qw) {
int i,j,a;
int sa[8]; //temp array
int c = 0;
int high;
[Code] ....
My coin/money change code works when there can be an exact change each time, i.e. when the 1 cent option is available. However, when the change options are only $10, $5, $1, 25 cents and 10 cents, it does not give me what I want for instance, I wanted to get change for $237.80, I was expecting to get:
23 10's, one 5, two 1's and 8 dimes. However, the code below is giving me 23 10's, one 5, two 1's and 3 quarters (there is no option left for the 5 remaining cents).how to fix it?
Code:
#include<iostream>
#include<algorithm>
#include<vector>
using namespace std;
void change(double cents, int a[]);
int main() {
double Dollars;
double cents;
[code]...
So this is the code I have so far, I didn't know it had to be a dynamic array so how would I Utilize dynamic array allocation to size the modal array
#include <iostream>
using namespace std;
int main() {
const int arraySize = 25;
const int patternSize = 10;
[Code] ....
I have a program with the following code, and I need to be able to either change the value of any or all of the strlen or to replace one or all with a temp array value. All values of the expression are arrays.
if (::strlen(tc_buf) + ::strlen(maxtime_buf) + ::strlen(" ") < sizeof(localBuf))
#include <iostream>
#include <string>
using namespace std;
[Code]....
// dynamic memory for 2D char array
char **board = (char**) calloc(column, sizeof(char*));
for(int i=0; i<column; i++)
board[i] = (char*) calloc(row, sizeof(char));
//for char 255 row and colum
char temp[255];
inputFile.getline(temp,255);
[Code]...
so i want to change into vector class like Vector<board>row;
Code:
#include <stdio.h>
void define (int integer, int IntArr[0], int *IntP);
int main(void)
{int integer = 0, IntArr[1] = {0}, IntP = 0;
define(integer, IntArr, &IntP);
[Code]...
Why does the integer with array change after passing trough the function and the normal integer doesn't? (I know why the normal one doesn't, but I dont get the array one)
why does this give me an error when i try to change the elements of the char string array.
code:
int main(void)
{
char *name = "aaa";
// setup the name
name[0] = 'Z';
name[1] = 'e';
name[2] = 'd';
name[3] = '';
return 0;
}
[code]....
This code ran well until i added in the ToLower function which is supposed to convert the char array string to lower case (based off ascii strategy -32). correct this function so it converts string to lower case and doesn't get errors.
#include <iostream>
#include <string>
using namespace std;
const int MAX = 81; //max char is sting is 80
void ToLower(char s[]);
int main(){
string y_n;
[Code]...
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) {
if (cards[0]) {
hideFirstCard=true;
cards[0] = '**';
} for(int a = 0; a <= numCards; a++) {
cout >> showCard(cards[a]);
} }
But it can the other way around
Code:
static_Array= dynamic_Array;
dynamic_Array = static_Array;
The second statement works and i'm able to print out both arrays with equal values but with the first
[code] static_Array = dynamic_Array;I get incompatible types in assignment of 'int*' to 'int [7]' is the error I get [/code]
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code:
#include<stdio.h>
void display(int array[],int size) {
int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
My program takes the values from one array and searches for their index position in another array (linear search algorithm). This is an example of the issue im having(its not part of the actual code below)
a[]={1,2,3,4,5,6}
Arr[]={1,2,2,3,4,5}
If it finds 1 in arr, it returns 0, which is fine but if it finds 2 in arr it return 1 and 1 instead of 1 and 2.
for (int q=0; q=size2;q++) {
int rs=secfunc(array1;size1;array2[q])
if(rs>=0) {
cout<<rs << "";
[Code] .....
How can I Figure out and store the sum of EACH COLUMN in the 2D array values in a 1D array? And to the same for the average?
View 1 Replies View RelatedIts output is not correct
#‎include <stdio.h>
void main() {
int n,i,j,option;
int evensum=0;
int oddsum=0;
[Code] ....
I tried sorting arr2 from lowest to highest value, but it only gives me 4 values and then the rest are zero.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
cout << fixed << setprecision(1);
[code].....
I have this simple program below:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct {
unsigned long long int address;
float current;
unsigned char pressure_units;
} sensor;
[Code]...
As you can see, it has stored the last struct in all three indexes of the array. Why?
How would i go about making a program that asks the user how many elements they want in the array and then what those numbers would be.
View 4 Replies View Relatedusing Win 7 64 bit enterprise, sp1.
I'm getting unwanted values assigned to a 2D array. I'm working on a tic tac toe program as a method of building my array skills. It's just text/ascii based command prompt output, in case you are wondering.
I have a 3x3 array for the actual grid values (to determine if there is a blank, an X or an O) based on x,y position as determined by GetAsyncKeyState to use arrows for square selection.
these x,y values I use to determine the array slot, square[xX][xY]
the xX and xY values range from 0-2 respectively depending on the game square the cursor is currently in.
The problem is, some of the array values get assigned to multiple array slots, and some don't get assigned at all, although 6 of the 9 squares function correctly. It is always the same squares. (I've tried it on multiple PC's and get the same error). I reset the array to 0's when the program starts.
I have a debugging output of this array's values that show on the screen so I can keep an eye on what it is doing.
Intended operation is to select a square and assign a value of 1 indicating an X. For example, select the center square and hit the enter key it will place an X in the center square and assign a value of 1 to square[1][1].
My debugging output shows square[1][1]=1 as shown by this line of code from below
curPos(31,4); cout<<"square["<<xX<<"]["<<xY<<"]="<<square[xX][xY];
if I hit the up arrow, xY changes to 0, xX remains 1, and the cursor moves up one. If I hit enter, it will place an X in the upper center square.
Debugging output shows square[0][1]=1, but my grid tracking the values square[][] will change to square [0][0]=1, square [0][1]=1, and square[0][2]=1. function square[xX][xY]=1 get's exercised only once that I can see, yet 3 elements in the array get assigned the value of 1. square[0][0] when selected gets no value assigned.
Here is the code in question: I think the offend variables are the xX and xY, and this is the only location in the entire code where they appear, aside from declaring them.
for (a=0; a<3; a++){//reset square[][] to 0
for (b=0; b<3; b++)
square[a][b]=0;
}
drawboard();//draw large # gameboard
[Code] ...
If I have an array of two columns that have the same values and I want to change only the third column how can I go about doing this. The values of the third column will change based on the values in one of the columns which I plug into a math equation. Also how come I can't show a double value in the array?
#include <iostream>
#include <math.h>
#include<iomanip>
#include <vector>
using namespace std;
[code]...
If we have array like
int numbers [] = {3,4,8,9,6,3,2,58,6,3,2,5};
how can we fast do smth like 3*4*8*9*6*3*2*58*6*3*2*5
also numbers[0]*numbers[1]*numbers[2] etc
all must be in one loop....
I have an array as such and need to multiply all the values of it by each other and put that as a variable.
//for example
int array1[100]
//assume i have already input the values of each element properly up to, say, element 4
//I need to now multiply all of those values together. I think I need the size of the array to control what it multiplies (I know how to find size) ....