I have an array as such and need to multiply all the values of it by each other and put that as a variable.
//for example
int array1[100]
//assume i have already input the values of each element properly up to, say, element 4
//I need to now multiply all of those values together. I think I need the size of the array to control what it multiplies (I know how to find size) ....
#include <iostream>
#include <cstdlib>
using namespace std;
[Code]....
I am trying to initialize int x[] = {10, 100, 1000, 10000} into a loop and give me four different numbers for something. I was trying to get creative and just do
myArr[j] = j * 10; with (int j = 1; j < 10000; j++) ,
But that doesn't work. It still gives me an output of 10 11 12... How to make an array punch through a loop and give me
10 Press any key to continue...
100 Press any key to continue...
1000 Press any key to continue...
10000 Press any key to continue....
I'm thinking I must set the for loop to < 10000.1 or < 10001 to output the final value in the array.
I am suppose to find voltage by multiplying a resistance array and a current array by using a function and pointers. This is what I have so far:
#include "stdafx.h"
#include <iostream>
using namespace std;
#include <iomanip>
[Code] ....
Goal: Write a program that compares the values stored in the first array to the user inputted values in the second array.
In order to fix this error: [URL]...
I had to change my array initialization to one with a star in front of it:
char a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
to:
char *a1[]={"a","d","b","b","c","b","a","b","c","d","a","c","d","b","d","c","c","a","d","b"};
I also changed my 2nd array to one with a star in front of it: char *a2[20];
What does this mean exactly? Putting a star in front of an array?
Also, I am now getting an "unhandled exception" when I try to get input for my 2nd array:
cin>>a2[i];
I'm very new to C++ so I've been trying to run through some code examples to begin to learn basic structures and syntax, but I've recently run into a problem using examples from the 7th ed. of Sams Teach Yourself C++. I'm using the code provided within one of the examples that allows you to specify and multiply two variables, but when I compile and run the executable the final output seems to only show the first variable and b/c of this the multiplication operation does not work.
Here is a my example code:
Code:
#include <iostream>
using namespace std;
int main() {
cout << "This program will multiply two numbers" << endl;
[Code] ....
Trying to multiply to matrixes using the following algorithm,
Code:
ABrec(A,B)
n=A.rows; //n must be multiple of 2
C is a new n*n matrix.
if(n==1)
C[0][0]=A[0][0]*B[0][0];
[Code] ....
but the code doesn't work !!!
we have to make a Invoice class which has a function called computeInvoiceAmount() which multiplies the price and the quantitiy which are private member of the class.
double computeInvoiceAmount(){
return quantity * pricePerItem;
}
This is my function, but if i compile it i get the following error:
"Invoice.cpp:53:11: error: "quantity" was not declared in this scope" and "Invoice.cpp:53:22: error: "pricePerItem" was not declared in this scope"
I tried it with the get functions but i get the same error.
Full code is here: [URL]
Two different matrices will be read from text files (input1.txt, input2.txt) and they will be stored in two dimensional arrays (matrix1, matrix2) and one dimensional arrays (array1, array2). Our aim is to obtain the matrix multiplication using two dimensional and one dimensional arrays.
You are asked to write the main and the following functions. The definitions of the functions are given in the skeleton code.
int read_file(ifstream& in_file, int &row, int &col, double *array, double **matrix)
int write_file(ofstream& out_file, int row, int col, double **matrix)
void print_matrix(double **matrix, int row, int col)
void print_array(double *array, int row, int col)
void multip(double **matrix1, double **matrix2, double **result, int k, int m, int n)
void multip_array(double *array1, double *array2, double *array_result, int k, int m, int n)
You are going to obtain the input and output files as command line arguments
input1.txt :
3 4
2 3 4 5
1 3 5 4
0 4 4 7
The first element in the first line represents the number of rows (3) and the second element represents the number of columns (4) of the matrix (the result file will have the same format).
likewise;
input2.txt :
4 5
1 2 3 4 5
2 9 43 44 21
32 32 32 43 54
1 3 3 4 5
thats my homework and here is the code i wrote from the sceleton code they gave me :
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
int read_file(ifstream& in_file, int &row, int &col,/* double *array,*/ double **matrix)
[Code] ....
I didn't understand the array part but even when i exclude the array part i get the program has stopped working message. My os is windows7 ultimate with mingw installed and i compile the program using g++ command in cmd with the arguments input.txt input2.txt resultt.txt
I have code the following but result is not ok.
int main()
{
int i,j,m;
m = 0;
[Code].....
So I have this program to calculate the types of meat, I have fixed the system errors but the actual program when I run it comes up with <null>
Code:
#include <stdio.h>
#include <stdlib.h>
#define beef 1 /* multiplication factor of beef*/
#define chicken 1.5 /*factor of chicken*/
[Code] .....
I am having a bit of difficulty with implementing an object oriented program that uses both linked lists and operator overloading. The program calls for adding and multiplying polynomials together, with each single polynomial being represented as a node of a linked list (which is further a data member of an object of a class I have defined to implement this program). For example:
polynomial A will be: 3x^4 // 1 node of a linked list
polynomial B will be: 5x^2 // 1 node of a linked list
polynomial C will be blank for the time being. // empty list
Now, I need to use operator overloading so that this following line of code can be implemented:
C = A + B;
C should now be: 3x^4 + 5x^2.
The checklist of which parts of my code that work:
constructor works;
copy constructor works;
destructor works;
operator= works;
print function needs work but i can worry about that later;
operator* work on later
Here is my code:
#include <iostream>
using namespace std;
struct termNode {
int exp; // exponent
int coef; // coefficient
termNode * next;
[Code] ....
For the time being I need to add multiple nodes together (with the result being in descending order). So for example:
polyType a(2,3), b(4,5), c(6,7), d;
d = a + b + c;
d.print(); // should print out 7x^6 + 5x^4 + 3x^2, but it will only print out: 3x^2 + 7x^6
I got this program to create an array of playing cards and assign the values and suits and shuffle the array. I'm at the point where I need to output the cards but I need to burn the first card by making it output "**" instead of the card. my cards[] is a constant so I can's assign the first card as such.
void showCards(const int cards[], int numCards, bool hideFirstCard) {
if (cards[0]) {
hideFirstCard=true;
cards[0] = '**';
} for(int a = 0; a <= numCards; a++) {
cout >> showCard(cards[a]);
} }
But it can the other way around
Code:
static_Array= dynamic_Array;
dynamic_Array = static_Array;
The second statement works and i'm able to print out both arrays with equal values but with the first
[code] static_Array = dynamic_Array;I get incompatible types in assignment of 'int*' to 'int [7]' is the error I get [/code]
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code:
#include<stdio.h>
void display(int array[],int size) {
int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
My program takes the values from one array and searches for their index position in another array (linear search algorithm). This is an example of the issue im having(its not part of the actual code below)
a[]={1,2,3,4,5,6}
Arr[]={1,2,2,3,4,5}
If it finds 1 in arr, it returns 0, which is fine but if it finds 2 in arr it return 1 and 1 instead of 1 and 2.
for (int q=0; q=size2;q++) {
int rs=secfunc(array1;size1;array2[q])
if(rs>=0) {
cout<<rs << "";
[Code] .....
use 2D array in function and change the array values. I do not know if I can use array by calling from a function. I have 6 row 6 column array, I used it inside a function and for the another function I just need to change 4. row 4. column and I do not want to type array to just change one part. I do not know if there is another way or not
View 7 Replies View RelatedHow can I Figure out and store the sum of EACH COLUMN in the 2D array values in a 1D array? And to the same for the average?
View 1 Replies View RelatedHaving error . I multiplied 0 by -4 and my result is -0 instead of 0. I tried to change the data type put It won't work. This is my code:
#include <iostream>
int main () {
double b, c;
std::cout<<"b: ";
std::cin>>b;
std::cout<<"c: ";
std::cin>>c;
std::cout<<b*c<<std::endl;
return 0;
}
Its output is not correct
#‎include <stdio.h>
void main() {
int n,i,j,option;
int evensum=0;
int oddsum=0;
[Code] ....
I tried sorting arr2 from lowest to highest value, but it only gives me 4 values and then the rest are zero.
Code:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
cout << fixed << setprecision(1);
[code].....
I have this simple program below:
Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct {
unsigned long long int address;
float current;
unsigned char pressure_units;
} sensor;
[Code]...
As you can see, it has stored the last struct in all three indexes of the array. Why?
How would i go about making a program that asks the user how many elements they want in the array and then what those numbers would be.
View 4 Replies View Relatedusing Win 7 64 bit enterprise, sp1.
I'm getting unwanted values assigned to a 2D array. I'm working on a tic tac toe program as a method of building my array skills. It's just text/ascii based command prompt output, in case you are wondering.
I have a 3x3 array for the actual grid values (to determine if there is a blank, an X or an O) based on x,y position as determined by GetAsyncKeyState to use arrows for square selection.
these x,y values I use to determine the array slot, square[xX][xY]
the xX and xY values range from 0-2 respectively depending on the game square the cursor is currently in.
The problem is, some of the array values get assigned to multiple array slots, and some don't get assigned at all, although 6 of the 9 squares function correctly. It is always the same squares. (I've tried it on multiple PC's and get the same error). I reset the array to 0's when the program starts.
I have a debugging output of this array's values that show on the screen so I can keep an eye on what it is doing.
Intended operation is to select a square and assign a value of 1 indicating an X. For example, select the center square and hit the enter key it will place an X in the center square and assign a value of 1 to square[1][1].
My debugging output shows square[1][1]=1 as shown by this line of code from below
curPos(31,4); cout<<"square["<<xX<<"]["<<xY<<"]="<<square[xX][xY];
if I hit the up arrow, xY changes to 0, xX remains 1, and the cursor moves up one. If I hit enter, it will place an X in the upper center square.
Debugging output shows square[0][1]=1, but my grid tracking the values square[][] will change to square [0][0]=1, square [0][1]=1, and square[0][2]=1. function square[xX][xY]=1 get's exercised only once that I can see, yet 3 elements in the array get assigned the value of 1. square[0][0] when selected gets no value assigned.
Here is the code in question: I think the offend variables are the xX and xY, and this is the only location in the entire code where they appear, aside from declaring them.
for (a=0; a<3; a++){//reset square[][] to 0
for (b=0; b<3; b++)
square[a][b]=0;
}
drawboard();//draw large # gameboard
[Code] ...
If I have an array of two columns that have the same values and I want to change only the third column how can I go about doing this. The values of the third column will change based on the values in one of the columns which I plug into a math equation. Also how come I can't show a double value in the array?
#include <iostream>
#include <math.h>
#include<iomanip>
#include <vector>
using namespace std;
[code]...
If we have array like
int numbers [] = {3,4,8,9,6,3,2,58,6,3,2,5};
how can we fast do smth like 3*4*8*9*6*3*2*58*6*3*2*5
also numbers[0]*numbers[1]*numbers[2] etc
all must be in one loop....
how can i change the array value and display the updated value. for example this is the output beginning of the program
-----------------------------------------------------
Part Description Number of parts in the bin
----------------------------------------------------
valve 10
Bearing 5
Bushing 21
Coupling 7
[Code].....