I want to pass an array to a function and change the array, how can I do that?
Code:
#include<stdio.h>
/*function to change the array*/
void rearng(int *qw) {
int i,j,a;
int sa[8]; //temp array
int c = 0;
int high;
[Code] ....
use 2D array in function and change the array values. I do not know if I can use array by calling from a function. I have 6 row 6 column array, I used it inside a function and for the another function I just need to change 4. row 4. column and I do not want to type array to just change one part. I do not know if there is another way or not
View 7 Replies View RelatedI'm trying to pass an array from one function to another without resorting to pointers and I have to use Pass by Reference. I can't seem to figure it out. I've been looking at many examples and just don't get it.
the function createAbc makes an array populated with the Alphabet. I need to pass that into my display function so that i can work with the array there. I don't know how to pass it in there... :(
#include "stdafx.h"
#include <iostream>
#include <cctype>
[Code]...
How would I pass let say 2 array pointers to a function X , allocate memory for them in X , fill them with values and get them back in my main function without creating a structure.
example:
Code:
void X(int *a, int*b){
a= malloc ...
b = malloc ...
// fill a and b
return them back to the main function
}
void main(){
[Code]...
I have been working on this all day, and its due in like an hour and a half. I have done everything the program wants except the last part. Here is the assignment:
Write a program that inputs 10 integers from the console into an array, and removes the duplicate array elements and prints the array. You may assume that all the integers are between 0 and 100, Write at least 1 function in addition to the main function, and pass an array into that function as a parameter. e.g.
Please enter your 10 numbers: 1 2 3 4 5 6 7 8 9 10
The array contains: 1 2 3 4 5 6 7 8 9 10
Please enter your 10 numbers: 1 1 3 3 3 6 7 8 9 9
The array contains: 1 3 6 7 8 9
Please enter your 10 numbers: 1 1 1 1 1 1 1 1 1 1
The array contains: 1
The bolded part is what I cant get to work. I have tried this and it keeps telling me I have not identified the items when I have.
Here is my code:
#include "stdafx.h"
#include <iostream>
using namespace std;
[Code]....
If a function takes N-dimensional array as a parameter, what is generic way to do that? I couldn't figure out a nice way to do that.
View 7 Replies View RelatedHow to pass my array to the function and return it as a sorted vector. I'm kind of lost with the functions part.
Problem: Write a program that performs a sorting routine as discussed in class. Create an array of 10 integers (e.g., 63, 42, 27, 111, 55, 14, 66, 9, 75, 87). Pass this array to a separate function that sorts the integers and returns a vector containing the sorted integers. Use either the SELECTIONSORT algorithm or the INSERTIONSORT.
Code so far:
#include <iostream>
#include <string>
#include <vector>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <iomanip>
[Code]...
Looking for info about the typedef 2-dimensional array ....
Suppose I have typedef two_Darr[3][3];
How to declare this and how to pass it to other function definition in the main function ....
I have this code:
const BYTE original[2][4] = {
{0x00, 0x00, 0x00, 0x00},
{0xFF, 0xFF, 0xFF, 0xFF}
};
void function(const BYTE** values){
[Code] ....
You might notice that the above code doesn't compile, this is the error:
cannot convert parameter 2 from 'BYTE [2][4]' to 'BYTE *'
1>
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
Even after some search I couldn't really find an answer to my problem, how do I pass the const BYTE array which I declared above in the function as a parameter (or what structure do I need to set for the function as a parameter)?
Code:
#include <stdio.h>
void define (int integer, int IntArr[0], int *IntP);
int main(void)
{int integer = 0, IntArr[1] = {0}, IntP = 0;
define(integer, IntArr, &IntP);
[Code]...
Why does the integer with array change after passing trough the function and the normal integer doesn't? (I know why the normal one doesn't, but I dont get the array one)
In my project, GreedyKnap::calKnap(int nItem, int nCapacity, float fWeights, float fProfits);
This function include two array member pass as parameter. how can i do this?
This code ran well until i added in the ToLower function which is supposed to convert the char array string to lower case (based off ascii strategy -32). correct this function so it converts string to lower case and doesn't get errors.
#include <iostream>
#include <string>
using namespace std;
const int MAX = 81; //max char is sting is 80
void ToLower(char s[]);
int main(){
string y_n;
[Code]...
I am trying to pass an array of objects however i m finding some problems.
pieces.h
Code: class Cpiece{
public:
Cpiece* board[8][8];// array of objects
virtual char getcolor() =0;
virtual char setcolor(char colour)=0;
[Code] .....
I need to pass an array of 10 instances of a custom class to a function. The snippets of code are posted below. How would I do this right?
The prototype:
Code:
int Search(Vertex vertex[], ofstream &outfile);
The implementation in the main function.
Code:
Search(vertex[10], outfile);
I am trying to write a poker program. I created a class to create a deck of cards..and then shuffle the deck..Now I am trying to pass value from the deck to an array to deal a hand..so 5 cards to player1[] array.. I tried doing it directly such as.
for (int j = 0; j < 5; j++) {
getCard=deck[j].toString();
}
But I would get error such as [Error] no match for 'operator=' in 'player1[j] = deck[j].Card::toString()'
So then I tried using a pointer..
char *getCard;
getCard = new char;
for (int j = 0; j < 5; j++) {
getCard=deck[j].toString();
}
but I would get this error [Error] void value not ignored as it ought to be. So how can I pass a value from the object deck..to an array? or should I be doing it another way?..I tried to think of a way to do it via a function but really got hung up there..
here is full code
#include <stdlib.h>
#include <iostream>
#include <ctime>
#include <algorithm>
using namespace std;
const char* FaceString[13] = {"Ace", "2", "3", "4",
"5", "6", "7", "8",
"9", "10", "Jack", "Queen", "King"};
[Code] ....
#include <iostream>
#include <iomanip>
using namespace std;
double calculateCharges(double hours[], double sizeofArray);//call function
[Code]....
I want to pass an array to a constructor, but only the first value is passed--the rest looks like garbage. Here's a simplified version of what I'm working on:
#include <iostream>
class board {
public:
int state[64];
board(int arr[])
[Code] ....
Why this doesn't work and how to properly pass an array? Notes: I don't want to copy the array. Also, I'm using MSVC++ 2010 Express.
I have a struct which has an array inside of it:
struct someStruct{
int structArray[999];}
Now when I want to access that array, I have the following:
ptrSomeStruct->structArray[someIndex];
But now I want to pass structArray to this function by reference so that it can adjust the array as needed and I can continue to use the array back in my caller function:
void adjustArray(void *& someArray){}
How do I accomplish this?
So this is the code I have so far, I didn't know it had to be a dynamic array so how would I Utilize dynamic array allocation to size the modal array
#include <iostream>
using namespace std;
int main() {
const int arraySize = 25;
const int patternSize = 10;
[Code] ....
I have a program with the following code, and I need to be able to either change the value of any or all of the strlen or to replace one or all with a temp array value. All values of the expression are arrays.
if (::strlen(tc_buf) + ::strlen(maxtime_buf) + ::strlen(" ") < sizeof(localBuf))
how can i change the array value and display the updated value. for example this is the output beginning of the program
-----------------------------------------------------
Part Description Number of parts in the bin
----------------------------------------------------
valve 10
Bearing 5
Bushing 21
Coupling 7
[Code].....
I am attempting to write a program " that has a function that is passed an array of int and its size, and with that it prints out only the numbers that are above average. "
I have included my code so far, but I am only getting one value as output, and that value seems to be completely off. I keep trying, but I am really stuck.
#include <iostream>
using namespace std;
int average(int values[],int size);
int main(){
int size;
int values[] = {1,2,3,4,5,6};
[Code] ....
Added the floats in the average() function. But there is still a value problem.
#include <iostream>
#include <string>
using namespace std;
[Code]....
// dynamic memory for 2D char array
char **board = (char**) calloc(column, sizeof(char*));
for(int i=0; i<column; i++)
board[i] = (char*) calloc(row, sizeof(char));
//for char 255 row and colum
char temp[255];
inputFile.getline(temp,255);
[Code]...
so i want to change into vector class like Vector<board>row;
why does this give me an error when i try to change the elements of the char string array.
code:
int main(void)
{
char *name = "aaa";
// setup the name
name[0] = 'Z';
name[1] = 'e';
name[2] = 'd';
name[3] = '';
return 0;
}
[code]....
Write a function that takes an array and returns true if all the elements in the array are positive, otherwise, it returns false.
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