Looking for info about the typedef 2-dimensional array ....
Suppose I have typedef two_Darr[3][3];
How to declare this and how to pass it to other function definition in the main function ....
If a function takes N-dimensional array as a parameter, what is generic way to do that? I couldn't figure out a nice way to do that.
View 7 Replies View RelatedI need to create the following brain damaging abomination:
I need a function pointer type to a function that has an argument of the same function pointer type and returns the same function pointer type.
The purpose is to enable a type of subroutine threading scheme for a small application specific scripting language. The question could just as well have been posted to the C forum.
This syntax works, but Payload is a generic type which I can coerce into the right pointer type via a cast. This is ugly IMHO. I could also hide it as a pointer in the FlipState class since I've forward declared this.
But this is an extra indirection in a performance critical part of the code, and also ugly.
Code:
class FlipState ;
typedef PayLoad (*FuncPtr) (FlipState *fs, PayLoad P) ; This syntax blows chunks using gcc on the other hand. Code: class FlipState ;
typedef FuncPtr (*FuncPtr) (FlipState *fs, FuncPtr P) ;
[Code] .....
This is hardly surprising. The compiler could not possibly understand what I was defining in the typedef. I think what I need is some kind of way to forward declare a function pointer type and then redefine it properly.
Is such a think even possible or am I just SOL? This one is mind boggling. We know how to do this with classes or other complex data types, but the syntax eludes me for both C++ and C.
I have some trouble with DLL. I created a dll with function
double square(const double * args)
and then in my application defines
typedef double (*MyFunct)(const double *args);
I use LoadLibrary and GetProcAddress to get the function address and cast it to MyFunct. Everything works fine except that when I pass a double *, for example 0x08800350, to the DLL function, the argument becomes totally something else, for example, 0x0aa00460.
I have no clue what happens to the argument value.
Write a program using user-defined function which accepts an integer array and its size as arguments and assign the elements into a two dimensional array of integers in the following format: If the array is 1,2,3,4,5,6, the resultant 2D array is
1 2 3 4 5 6
1 2 3 4 5 0
1 2 3 4 0 0
1 2 3 0 0 0
1 2 0 0 0 0
1 0 0 0 0 0
//This program calls unionLL function which takes list1 and list2 objects of //LinkedList type as arguments also nowhere in the function I had changed List1
//and List2 contents although the list1 and list2 head's and also their next //pointer remain same but the elem or data field is automatically updated to //some garbage value.
#include <iostream>
using namespace std;
typedef int E;
class LinkedList;
class Node {
[Code] ......
How to pass arguments from other functions to main. i want to write a program like nano well not exactly like nano editor. I have a function f_read(char* filename[]), and fopen() get filename[1] as file name and *filename[2] as "r" read mode and rest of the code will read from a file.
I want is this char filename[] to main(int argc , char argv[])
how can i do that??
I want to use one median function "selectfunction" to choose one of the 2 other functions at random to pass my 2-dim array to the selected function. There is a problem in the median function
#include <iostream>
#define random(x)(rand()%x) // for random number between numbers of 0 and 1
using namespace std;
void proc1 (int iArray[][2]);
void proc2 (int iArray[][2]);
void selectfunction(int iArray[][2]);
int A[4][2] = {{1, 2} , {3, 4} , { 5, 7} , {8, 1} };
[Code]...
I'm given a mathematical function F(x) = etc..., the user inputs an initial x point and a final x point. The program finds the integration.
Below is a snippet of code.
/*Typedefs as given by prof*/
typedef double (*mainFunction) (double);
typedef double (*calcArea) (mainFunction, double, double);
int main () {
answer = calcIntegral(mainFunction *curve1, calcArea *calcAreaRect, a, B)/>; /*it doesn't like this line*/
printf("The integral from %lf to %lf is: %.4lf", &a,&b,&answer);
return 0;
}
curve1 is a function that accepts a double and returns a double, calcAreaRect takes mainFunction main(which is F(x) so i stored the fn in curve1), double and double.
I'm trying to pass an array from one function to another without resorting to pointers and I have to use Pass by Reference. I can't seem to figure it out. I've been looking at many examples and just don't get it.
the function createAbc makes an array populated with the Alphabet. I need to pass that into my display function so that i can work with the array there. I don't know how to pass it in there... :(
#include "stdafx.h"
#include <iostream>
#include <cctype>
[Code]...
How would I pass let say 2 array pointers to a function X , allocate memory for them in X , fill them with values and get them back in my main function without creating a structure.
example:
Code:
void X(int *a, int*b){
a= malloc ...
b = malloc ...
// fill a and b
return them back to the main function
}
void main(){
[Code]...
I have been working on this all day, and its due in like an hour and a half. I have done everything the program wants except the last part. Here is the assignment:
Write a program that inputs 10 integers from the console into an array, and removes the duplicate array elements and prints the array. You may assume that all the integers are between 0 and 100, Write at least 1 function in addition to the main function, and pass an array into that function as a parameter. e.g.
Please enter your 10 numbers: 1 2 3 4 5 6 7 8 9 10
The array contains: 1 2 3 4 5 6 7 8 9 10
Please enter your 10 numbers: 1 1 3 3 3 6 7 8 9 9
The array contains: 1 3 6 7 8 9
Please enter your 10 numbers: 1 1 1 1 1 1 1 1 1 1
The array contains: 1
The bolded part is what I cant get to work. I have tried this and it keeps telling me I have not identified the items when I have.
Here is my code:
#include "stdafx.h"
#include <iostream>
using namespace std;
[Code]....
This seems simple enough but I'm missing something here to make this code work.What I'm trying to do is print the contents of the two dimensional array in 25 rows and 4 columns. I experimented with something similar to this code when I initialized the array with numbers.
#include <iostream>
#include <iomanip>
#include <cmath>
[Code].....
I'm getting garbage. I tried including the name of the array in the cin object but I got an error message that says "no match for operator '>>'. When I take the name of the array out, the program compiles but I get garbage. Program is suppose to reads data from a file of 25 students and calculates test scores and class grade average output each student's name score, letter grade and grade average. I would be happy at this point if I could just print out something that wasn't garbage.
Here is the code.
#include <iostream>
#include <iomanip>
#include <cmath>
#include <string>
#include <fstream>
using namespace std;
//const
const int Array_Row = 25;
const int Array_Col = 4;
[Code] ......
I want to have a function pointer inside a typedef struct but I get a segmentation fault when I run my code. Here's my code:
#include <stdio.h>
typedef struct Foo {
void (*bar)(int);
} Foo;
void func(int x) {
printf("display: %d
[Code] ....
In class, we have learned how to set up the main method so we can convert command line arguments to integers and utilize them. Here is an example of a method we learned to store command line arguments as integers in an array:
Code:
int main (int argc, constchar* argv[]) {int i;
int a[argc - 1];
// Fill the array with the arguments on the command line
for (i = 0; i < argc - 1; i++){
a[i] = atoi(argv[i + 1]);
[Code] .....
I understand that there are probably better ways to do it than using the atoi function, but for our purposes, the professor said this was okay.
Now, I am being asked to create a separate function to perform the same task (store integers in an array). I was told I would need to declare the array "out in the main program", and that the function would need to take at least 2 arguments: an array, and an array size.
Firstly, what should my return value be? My professor gave a hint that it would be important for me to figure out what the return value is, but I don't see why it would be anything else than void.
Also, wouldn't I need a third parameter? Perhaps the integers that are being stored in the array? (But how would I represent this as a parameter)?
Write a function that accepts an array of integers and its size as arguments. The function should create a new array that is one element larger than the argument array. The first element of the new array should be set to 0. Element 0 of the argument array should be copied to element 1 of the new array, element 1 of the argument array should be copied to element 2 of the new array, and so forth.
The function should return a pointer to the new array. Use ONLY pointer parameters instead of arrays in both functions; use pointers (not subscripts) to move through elements of both arrays. Before calling the function, display your original array. When the function call is completed, display the new array.
Here is what i got so far:
#include <iostream>
using namespace std;
int *shifted (int * , int);
const int SIZE = 10;
int main () {
int array_size [30];
[Code] ....
write a function accepts two arguments, an array of integers and a number indicating the number of elements in the array. the function should recursively calculate the sum of all the numbers in the array. Demonatrate the use of the functions in a program that asks the users to enter an array of numbers and prints it sum
i had done this but it wont work
#include <iostream>
#include <conio.h>
#include <iomanip>
using namespace std;
[Code].....
I want to pass an array to a function and change the array, how can I do that?
Code:
#include<stdio.h>
/*function to change the array*/
void rearng(int *qw) {
int i,j,a;
int sa[8]; //temp array
int c = 0;
int high;
[Code] ....
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
std::vector<int> results;
results.reserve(arr1.size() + arr2.size());
results.insert(results.end(), arr1.begin(), arr1.end());
results.insert(results.end(), arr2.begin(), arr2.end());
and for the one dimensional array as:
int * result = new int[size1 + size2];
copy(arr1, arr1 + size1, result);
copy(arr2, arr2 + size2, result + size1);
But I do not know how to make a 3-dimensional array or vector.
How to pass my array to the function and return it as a sorted vector. I'm kind of lost with the functions part.
Problem: Write a program that performs a sorting routine as discussed in class. Create an array of 10 integers (e.g., 63, 42, 27, 111, 55, 14, 66, 9, 75, 87). Pass this array to a separate function that sorts the integers and returns a vector containing the sorted integers. Use either the SELECTIONSORT algorithm or the INSERTIONSORT.
Code so far:
#include <iostream>
#include <string>
#include <vector>
#include <cmath>
#include <cstdlib>
#include <ctime>
#include <iomanip>
[Code]...
I have this code:
const BYTE original[2][4] = {
{0x00, 0x00, 0x00, 0x00},
{0xFF, 0xFF, 0xFF, 0xFF}
};
void function(const BYTE** values){
[Code] ....
You might notice that the above code doesn't compile, this is the error:
cannot convert parameter 2 from 'BYTE [2][4]' to 'BYTE *'
1>
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast
Even after some search I couldn't really find an answer to my problem, how do I pass the const BYTE array which I declared above in the function as a parameter (or what structure do I need to set for the function as a parameter)?
In my project, GreedyKnap::calKnap(int nItem, int nCapacity, float fWeights, float fProfits);
This function include two array member pass as parameter. how can i do this?
I have a class "Result" with a single template function Set(const std::string& arName, T& val) and a specialization of this function Set<Real>(const std::string& arName, Real& val) where Real is a typedef for double. The class is in a shared library and I use it in my main program. If I do result->Set<GLOBAL::Real>("U", 100.0); the wrong template function is called!
I check this by the output with std::cout.
Maybe it's a problem with the typedef.
If I link the object file of the Result class directly to my main program (no shared library), it works.
typedefs.hpp:
namespace GLOBAL {
typedef double Real;
} results.hpp
#include <iostream>
[Code] ....
I had a hard question in my C++ final exam and I'm trying to solve it for the last 3 days. I haven't succeded yet! Here is the question: You have a one-dimensional array A[20]={1,2,3,4,...,20} and B[5][4] you have to assign the A array's elements to the B array but there is an order which is: B[5][4] = { { 12, 9, 11, 10 }, { 14, 7, 13, 8 }, { 16, 5, 15, 6 }, { 18, 3, 17, 4 }, { 20, 1, 19, 2 } } and there is a restriction: you can only use ONE for statement, nothing else!
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
int A[20] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15,
16, 17, 18, 19, 20 }; // define A array's elements.
int B[5][4] = { 0 }, k = 1; // define B array and k counter.
[code]....
I can't narrow the statements to one,This program works perfectly but it shouldn't be that long, we need ONLY ONE FOR statement, not two!
is it allowed to to like this:
char a[10] = "Lizard";
char b[2][5];
b[0][0] = a[0];
b[0][1] = a[1]; etc?