This seems simple enough but I'm missing something here to make this code work.What I'm trying to do is print the contents of the two dimensional array in 25 rows and 4 columns. I experimented with something similar to this code when I initialized the array with numbers.
#include <iostream>
#include <iomanip>
#include <cmath>
[Code].....
I'm getting garbage. I tried including the name of the array in the cin object but I got an error message that says "no match for operator '>>'. When I take the name of the array out, the program compiles but I get garbage. Program is suppose to reads data from a file of 25 students and calculates test scores and class grade average output each student's name score, letter grade and grade average. I would be happy at this point if I could just print out something that wasn't garbage.
Here is the code.
#include <iostream>
#include <iomanip>
#include <cmath>
#include <string>
#include <fstream>
using namespace std;
//const
const int Array_Row = 25;
const int Array_Col = 4;
[Code] ......
I want to use one median function "selectfunction" to choose one of the 2 other functions at random to pass my 2-dim array to the selected function. There is a problem in the median function
#include <iostream>
#define random(x)(rand()%x) // for random number between numbers of 0 and 1
using namespace std;
void proc1 (int iArray[][2]);
void proc2 (int iArray[][2]);
void selectfunction(int iArray[][2]);
int A[4][2] = {{1, 2} , {3, 4} , { 5, 7} , {8, 1} };
[Code]...
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code:
#include<stdio.h>
void display(int array[],int size) {
int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
i am programming Cli/Ser ,so part of the program is to open file to download it from client side,but i want to return the global value Errorno to print it to screen , and how to use strerror() func ??? i write this "This is part of server code" :
Code:
fd= open("abc.txt",O_RDONLY);
//error handilng in open file
if(fd<0)
{
[Code].....
I have a very simple program here, and somehow I can't get it to print out a two-dimensional array. Here's my code:
Code:
#include <stdio.h>
#define MAX_PEOPLE 100
char display_table(int table[MAX_PEOPLE][MAX_PEOPLE], int n);
int main (void) {
int n = 5;
char names[MAX_PEOPLE][4] = {"Ami", "Bob", "Cal", "Dan", "Ion"};
[Code]...
and here's how the printed table should look like when i run the program:
Code:
|Ami Bob Cal Dan Ion
--- --- --- --- --- ---
Ami| 0 1 1 1 0
Bob| 0 0 1 0 0
Cal| 0 0 0 0 0
Dan| 1 0 1 0 1
Ion| 0 1 1 1 0
If a function takes N-dimensional array as a parameter, what is generic way to do that? I couldn't figure out a nice way to do that.
View 7 Replies View RelatedLooking for info about the typedef 2-dimensional array ....
Suppose I have typedef two_Darr[3][3];
How to declare this and how to pass it to other function definition in the main function ....
How can I concatenate two 2-dimensional int arrays into one larger 3-dimensional array. This question is also valid for the 3-dimensional vectors. I know the command for the one dimensional vector as:
std::vector<int> results;
results.reserve(arr1.size() + arr2.size());
results.insert(results.end(), arr1.begin(), arr1.end());
results.insert(results.end(), arr2.begin(), arr2.end());
and for the one dimensional array as:
int * result = new int[size1 + size2];
copy(arr1, arr1 + size1, result);
copy(arr2, arr2 + size2, result + size1);
But I do not know how to make a 3-dimensional array or vector.
I need to create subfunctions to do basic Matrix mathematics (addition, subtraction, etc.) I need to be able to pass bot of my Matrices to subfunctions. I started with the addition sub function and I cant get the code to run. I keep getting expected primary-expression before ']' token error for line 75.
#include <iostream>
#include <stdio.h>
using namespace std;
[Code].....
So i am struggling for days to get this done and all i need is to get the sum of the areas and get them printed on the screen my code is this:
Code:
#include<stdio.h>
#include <stdlib.h>
#include<conio.h> //Not needed in Dev C++//
#define PI 3.1415
float Area_of_Rectangular(float length,float width);
float Area_of_Circle(float radius);
int main()
[Code]...
Print the inverse number. Ex: 2178*4=8712
Write down a program which can satisfy the prerequisite and print out the screen.
The answer is:
Code:
void inverse2 ()
{
int i,j;
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
if (i*j==inverse (i))
printf("%5d%2d",i,j);
}
I can't understand the double for loop.
for (i=1000;i<=9999;i++)
for (j=1;j<=9;j++)
And The meaning for
i*j==inverse (i)
This code runs. However, when I run it, the text from printf doesn't appear until after I type in the two numbers.
I use Wascana, will it run correctly on other compilers?
Code:
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main() {
fflush(stdout);
[Code].....
And this is how it turns out on the screen:
Code:
6
3
What size is the die:
how many dice to roll:
Numbers are 3d6
Rolling die no.1...
RolledDie: 4 DieTotal: 4
Rolling die no.2...
RolledDie: 5 DieTotal: 9
Rolling die no.3...
RolledDie: 5 DieTotal: 14
The total is: 14
How to print to the screen the value of n after it has been multiplied.
For example: if I use cout << "n: " << n << " power: " << power << "
"; I
can see the variable "power" decrementing by 1, but I don't see the variable "n" incrementing with its new value after it has been multiplied by n * n.
#include <iostream>
using namespace std;
typedef unsigned short int USHORT;
typedef unsigned long int ULONG;
ULONG Getpower(USHORT n, USHORT power);
[Code] .....
My objective is to check to see if a number is odd or even and print it to the screen just to make sure its working correctly.
The data file contains:
138
402 2 485
9
43
98 805
58
421
948 7 97
48
67
35
42
948
579 39 12
700 20 500 210
98
I can get the numbers to print fine using:
fstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
while(infile1.get(listNum))
cout << listNum;
}
However, when I check for odd or even numbers it will check each and every number.
printed like this (partial list):
1 is odd 3 is odd 8 is even
9 is odd
But it should print:
138 is even
9 is odd
I tried using getline, but it keeps giving me the errors:
invalid conversion from 'void*' to 'char**'
invalid conversion from 'char' to 'size_t*'
too few arguments to function 'ssize_t getline(char**, size_t*, FILE*)'
Here is the getline code, what am I doing wrong? I have tried switching things around, adding things. Just nothing works.
ifstream infile1(argv[1]);
if(!infile1.is_open())
cout << "Could not open file";
else {
char listNum;
getline(infile1, listNum);
cout << listNum;
}
Given this sentence as an input: "Hello my name and "John" (with its spaces and capital letters), print it on the screen .. NB the phrase must be entered from the keyboard all at once ... you can do this in C / C + +?
View 3 Replies View Relatedhow to print the result on screen without using printf in C...?
View 6 Replies View RelatedI'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.
I've tried
function ( array[][6] ) ;
But the size of the array has to be constant so it cannot be declared later.
I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?
The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.
How can I make the output print out to the screen in reverse?
Code: #include <iostream>
#include <iomanip>
using namespace std;
int getnum();
void Fibonacci(int n);
[Code].....
I'm trying to write a program that prints all of the prime numbers to the screen. I'm getting angry because it only prints EVERY number. I think it has something to do with the bool change not being able to leave the for-loop but how to fix it.
Code:
#import <stdio.h>
#include <stdbool.h>
int main(void){
printf("
The Primes Are: 1");
[Code] ....
is there anyway to read an entire file and print in on screen? file consists of strings and integers!
View 7 Replies View RelatedHow do I print a mathematical series such as
1 + 2/2! - 3/3! + ...... n/n! //n is read from user
Not only we need to print the series on the screen but at the same time find the sum using simple loops.
I want to pass array to function, to fill array with new values and then to print the array in the main. But I have problem because it prints me just array of zeros. Maybe the concept is wrong, I'm new with passing arrays to function.
function:
Code:
void printSum(int *return_array) {
int return_array[3];
int i;
for(i = 0; i < 3 ; i++){
return_array[i] = 5;
Code:
void printSum(int *return_array);
int main {
int m_return_array[3];
int i,j;
for(i= 0 ; i < 3 ; i++){
m_return_array[i] = 0;
} printfSum(start,m_return_array);
[Code]...
I need to pass a 2D array to a function. I want to know, where I may have made a mistake. This is the piece of code that I found on the web, and I am using it to allocate my 2D array.
Code:
signed char allocate2D( int** arr2D, int rows, int cols )
{
int i;
arr2D = malloc( rows*sizeof( int* ) );
if( !arr2D )
return -1;
[Code]....
My main function passes the 2D array to the function
Code: signed char read_root_message_file( int **Root_Messages, int *num ) This is how I pass the array in the main function to the above function:
Code:
int main( int argc, char *argv[] )
{
int **Root_Messages;
...
...
Root_Messages = NULL;
read_root_message_file( Root_Messages, &num_root_msg );
[Code]....
Would this be an example of passing an array to a function??
Code:
void wipe (int theArray[] ) {
int index;
printf("
Inside function wipe() sets each array element back to 0.
");
[code]....
I am following a tutorial and the topic was passing array to function so i tried to do a BMI calculator by myself. I am using code blocks to compile the codes, it is actually working while using compiler's run button. But when I open the exe file, its closing the window after entering the persons' weights and heights. Here is the code
Code:
// Passing array to function example BMI calculator of n person
#include<stdio.h>
#include<math.h>
void assess(float bmi[],int a);
int main(void){
int n,i,j;
}
[code]....