I need to pass a 2D array to a function. I want to know, where I may have made a mistake. This is the piece of code that I found on the web, and I am using it to allocate my 2D array.
Code:
signed char allocate2D( int** arr2D, int rows, int cols )
{
int i;
arr2D = malloc( rows*sizeof( int* ) );
if( !arr2D )
return -1;
[Code]....
My main function passes the 2D array to the function
Code: signed char read_root_message_file( int **Root_Messages, int *num ) This is how I pass the array in the main function to the above function:
Code:
int main( int argc, char *argv[] )
{
int **Root_Messages;
...
...
Root_Messages = NULL;
read_root_message_file( Root_Messages, &num_root_msg );
I want to use one median function "selectfunction" to choose one of the 2 other functions at random to pass my 2-dim array to the selected function. There is a problem in the median function
#include <iostream> #define random(x)(rand()%x) // for random number between numbers of 0 and 1 using namespace std; void proc1 (int iArray[][2]); void proc2 (int iArray[][2]); void selectfunction(int iArray[][2]); int A[4][2] = {{1, 2} , {3, 4} , { 5, 7} , {8, 1} };
I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.
Code: #include<stdio.h> void display(int array[],int size) { int i;
[Code]....
With this code I want to print the five elements from the element present in [0][4].
But shows an error that
Code: D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':| D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]| D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'| ||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|
I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?
I want to pass array to function, to fill array with new values and then to print the array in the main. But I have problem because it prints me just array of zeros. Maybe the concept is wrong, I'm new with passing arrays to function.
function:
Code: void printSum(int *return_array) { int return_array[3]; int i; for(i = 0; i < 3 ; i++){ return_array[i] = 5;
Code:
void printSum(int *return_array); int main { int m_return_array[3]; int i,j; for(i= 0 ; i < 3 ; i++){ m_return_array[i] = 0; } printfSum(start,m_return_array);
I am following a tutorial and the topic was passing array to function so i tried to do a BMI calculator by myself. I am using code blocks to compile the codes, it is actually working while using compiler's run button. But when I open the exe file, its closing the window after entering the persons' weights and heights. Here is the code
Code:
// Passing array to function example BMI calculator of n person #include<stdio.h> #include<math.h> void assess(float bmi[],int a); int main(void){ int n,i,j; }
i have defined an object which is an array of my class called Player now i want to pass this whole array as a parameter in a function, i think it will be done by using pointers but i am not able to figure out how it is done?
Player player[4]; void showscoreboard(" ", int cround){} " " represents the blank where the array should b passed.
Write a program that inputs 10 integers from the console into an array, and removes the duplicate array elements and prints the array. By removing, I mean that you should make it appear as if the elements hadn't been there. You may assume that all the integers are between 0 and 100, Write at least 1 function in addition to the main function, and pass an array into that function as a parameter. e.g.
Please enter your 10 numbers: 1 2 3 4 5 6 7 8 9 10 The array contains: 1 2 3 4 5 6 7 8 9 10
Please enter your 10 numbers: 1 1 3 3 3 6 7 8 9 9 The array contains: 1 3 6 7 8 9
Please enter your 10 numbers: 1 1 1 1 1 1 1 1 1 1 The array contains: 1
The bolded area is where I'm having trouble. How I can go about doing this, passing an array into the function as a parameter?
Here is my code:
#include "stdafx.h" #include <iostream> using namespace std; int main () { const int MAX = 10; int a[MAX] = {0}; int i;
I am trying to pass a dynamic array to a function which will:
- Copy the contents of the array to a temporary dynamic array - Change the array passed in to one size bigger - Copy the elements from the temp array back into the newly changed array - Insert an item into the last spot of the array
Here is my code:
#include <iostream> using namespace std ;
void make_array ( int Old [] , int & old_size , int toInsert ) ; void zero_array ( int arry [] , int arry_size ) ; void print_array ( int arry [] , int arry_size ) ;
[Code] .....
The output seems like a memory address but is just a very large number, what have I done incorrectly to cause this?
In the below program, When the getline function is called, it passes a char array of size 1000 by VALUE. It must have passed by value because there is no pointer or reference in the argument list of the getline function definition. And if that's the case, when exiting the getline function, isn't the s[] char array destroyed? And if it is destroyed, then when we reference line in the copy function, what are we actually copying?
#include <stdio.h> #define MAXLINE 1000/* maximum input line length */ int getline(char line[], int maxline); void copy(char to[], char from[]); /* print the longest input line */ main() {
how can i pass an array as an argument to the function? in getCoin() fcn, I am supposed to pass coins array as an argument to the function. fcn prompts user to enter coin(Date, Type and Country). values entered by user are read and assigned to the coins array. I tried the code below.
//# include "Coins.h"; #include <iostream> #include <string> using namespace std;
After passing the address of the first element (&array[0][0]) of a multidimensional integer array to a function with a "const int*" parameter, parameter seems to be pointing to the wrong values, which are not the actual elements of the passed array.
First, why does this happen ?
Second, how can I fix this without changing the parameter type into a multidimensional int array ?
You should be able to enter those fields, and after some time when while loop is stopped (when u press n) it should print out that PhoneBook bellow. I don't understand what is the problem but I think it is that Display function.
having problem passing arguments between main and a function.
I would like to pass three values to a function, have it calculate a 2D matrix and return it back to main. I would like it to accept variable matrix size. Here is my code:
I've been trying to work fix this piece of code to put into a project but I could not get it to work. I keep getting this error C2664: 'SumOfNumbers' : cannot convert parameter 1 from 'int' to 'double []' . I've worked every thing piece by piece but when I try to pass the array to the function I get the error and don't know what it means. Does C++ not allow what I'm trying to do?
Code: #include <iostream> using namespace std; void SumOfNumbers(double Nbr[], int size); int main()
