C++ :: Passing Array Into Function As Parameter

May 2, 2013

Write a program that inputs 10 integers from the console into an array, and removes the duplicate array elements and prints the array. By removing, I mean that you should make it appear as if the elements hadn't been there. You may assume that all the integers are between 0 and 100, Write at least 1 function in addition to the main function, and pass an array into that function as a parameter. e.g.

Please enter your 10 numbers: 1 2 3 4 5 6 7 8 9 10 The array contains: 1 2 3 4 5 6 7 8 9 10

Please enter your 10 numbers: 1 1 3 3 3 6 7 8 9 9 The array contains: 1 3 6 7 8 9

Please enter your 10 numbers: 1 1 1 1 1 1 1 1 1 1 The array contains: 1

The bolded area is where I'm having trouble. How I can go about doing this, passing an array into the function as a parameter?

Here is my code:

#include "stdafx.h"
#include <iostream>
using namespace std;
int main () {
const int MAX = 10;
int a[MAX] = {0};
int i;

[Code]...

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C :: Passing Array As A Parameter To Function

Oct 6, 2014

How come when we pass an array as a parameter to a function, the entire array is copied and is available to function?

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C++ :: Passing Function As Parameter?

Jan 7, 2015

gcc v.8.3 -std=gnu++11

[URL]

I'm trying to pass a function as a parameter and failing. It seems simple, until I get the error messages.

Here is the code:

class MinimalSolver {
typedef double (*func)(double sum, double char);
void driver();

[Code]....

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C++ :: Passing A Function As Template Parameter

Dec 26, 2013

Pseudocode:
template<typename T /*, some parameter for member_function */>
class Foo {
public:
void someFunction() {
T t;
t.member_fuction(...);
} }

I'm trying to make the call to T::member_function a templated value because member_function might vary by name in my scenario. Since std::mem_fn isn't a 'type', i can't do something like Foo<std::string, std::mem_fn(&std::string::clear)> foo;

I also want to take into account that member_function might have more than one parameter. That is, the first parameter will always be something known but there might be other defaulted parameters.

The only thing I can think of is to make a proxy structure, something like this:

template<typename T, T> struct proxy;
template<typename T, typename R, typename... Args, R (T::*member_function)(Args...)>
struct proxy<R (T::*)(Args...), member_function> {
R operator()(T &obj, Args.. args) {
return (obj.*member_function)(std::forward<Args>(args)...);
} }

Which would then allow me to do (for example) this:

Foo<std::string, proxy<void(std::string::*)(), &std::string::clear> >

when Foo is implemented like this:

template<typename T, typename member_function>
class Foo {
public:
void someFunction() {
T t;
member_function()(t);
} };

That implementation works for me.

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C++ :: Passing A Function Parameter By Reference?

Sep 25, 2012

I created the following code to pass the the variable 'inputVoltage' by reference to the function 'input'. It certainly works when I run the program, but I dont think it is a standard way of doing it, i.e. the use of '*' and '&' is not according to convention ? Or perhaps the way did it is acceptable ?

int input (double *inputVoltage);
int main ( {
double inputVoltage;
input(&inputVoltage);

[Code]....

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C++ :: Passing Extra Parameter To Operator Function?

Jul 29, 2013

I have a class and I would like to be able to pass an extra parameter to the function that is executed.

BigInt operator / (BigInt N,BigInt D) {
...
}

is what I have now. but I would like to do something like this. so the default value for a is 10. and if the user does something like N/D (12) Then the value of a is 12.

BigInt operator / (BigInt N,BigInt D, int a=10) {
...
}

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C++ :: Extra Parameter Passing To Overloaded Binary Operator Function

Jun 11, 2013

I have a class matrixType that has some overloaded operators (+, -, *, and <<). With a view to having clearly-delineated, perfectly-formatted, four-sided matrices, as shown below:

A = 1 2 3
4 5 6
7 8 9
or
A + B = 1 2 3
4 5 6
7 8 9

and NOT this jagged ones shown below:

A = 1 2 3
4 5 6
7 8 9

or

A + B = 1 2 3
4 5 6
7 8 9
,

I want a scheme in which the string literals (A, A+B, etc.) could be passed as parameters to the overloaded stream insertion (<<) operator function so that I could use the string’s length to determine how much offset from the display screen’s left to apply to each matrix’s row (by using the setw() function). However, I do know that the << operator is a binary operator, meaning the function cannot take more than two parameters: that is what compounds my problem!

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C++ :: Template Function Parameter Passing By Reference Instead Of Copy / Pointer

Sep 19, 2014

Basically I'm trying to pass an object as a reference to the template function, rather than a copy as it's seeing. I'm needing to do this without editing Obj::Call to accommodate a reference as its first parameter, as it'd break other calls.

You'll notice in the following code the object will be destroyed upon passing, while the object defined is still in-scope due to the infinite end loop.

#include <iostream>
#include <string>
using namespace std;
class Obj {
public:
string name;
Obj(string name): name(name) {cout << "create " << this << endl;}

[code]....

In the past I tried ref(), which appeared to stop this happening, however it created a blank copy of the object instead.

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C++ :: Array Into Function As Parameter Pass

May 2, 2013

I have been working on this all day, and its due in like an hour and a half. I have done everything the program wants except the last part. Here is the assignment:

Write a program that inputs 10 integers from the console into an array, and removes the duplicate array elements and prints the array. You may assume that all the integers are between 0 and 100, Write at least 1 function in addition to the main function, and pass an array into that function as a parameter. e.g.

Please enter your 10 numbers: 1 2 3 4 5 6 7 8 9 10
The array contains: 1 2 3 4 5 6 7 8 9 10

Please enter your 10 numbers: 1 1 3 3 3 6 7 8 9 9
The array contains: 1 3 6 7 8 9

Please enter your 10 numbers: 1 1 1 1 1 1 1 1 1 1
The array contains: 1

The bolded part is what I cant get to work. I have tried this and it keeps telling me I have not identified the items when I have.

Here is my code:

#include "stdafx.h"
#include <iostream>
using namespace std;

[Code]....

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C++ :: Function Parameter Scope - NumArray Not Recognized As Valid Parameter

Sep 28, 2014

My errors are at the end of the program in two function calls within the definition of the InsertByValue function. g++ does not seem to recognize NumArray as a valid parameter.

#include <iostream>
#include <assert.h>
using namespace std;
const int CAPACITY = 20;

/* Displays the content of an int array, both the array and the size of array will be passed as parameters to the function
@param array: gives the array to be displayed
@param array_size: gives the number of elements in the array */
void DisplayArray (int array[], int array_size);

[Code] ....

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C++ :: How To Use Function With Pointer Parameter To Print Array

Jul 20, 2013

The printArray function should take in the dynamically created array and the size of the array as parameters. It should print out the contents of the array.

#include <iostream>
#include <string>
using namespace std;

[Code].....

My problem is that how to write the code to print the array using pointers. I've been stuck for awhile trying to figure it out.

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Visual C++ :: Write A Function With Array And Int Parameter?

Nov 25, 2012

i need to write a function with an array parameter and an int parameter.

that array has to be filled with first 10 prime numbers that are exact or higher than the int parameter...and then i need an average value of those 10 prime numbers...

The problem is im not really sure how i should do the part to fill the array with prime numbers that are higher than that int??

Code:

int avgprimearray (int higharray[], int somenumber){
}

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C :: Passing Filename As A Parameter

Aug 23, 2013

Code:
#include <stdio.h>
void ASCII_to_EBCDIC( size_t, unsigned char *);
void EBCDIC_to_ASCII( size_t, unsigned char *);
void to_ASCII(unsigned char *);
void to_EBCDIC(unsigned char *);
/* conversion tables */
static unsigned char

[Code] ....

The above snippet is for a buffer/string, where as i want to pass file name as a parameter and want function to process the file line by line?

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C++ :: Passing Node As Parameter

May 1, 2013

#include <cstdlib>
#include <iostream>
struct tax_node {
char form; // tax form letter
int version; // tax form number

[Code] ....

I cannot seem to get why function print_contents will not work. The couts at the end of the program is just to test that it printed correctly. But, if I need it to print the contents such when print_contents(ptr2) is called. I think it should be tax_ptr in the parameter list but I am not quite sure.

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C# :: Passing Event As A Parameter

Nov 16, 2014

I want to create events and then, functions which are subscribed to the event can access information about the event. For example, in Class 2 below, I want it to be able to access things such as touch.position, etc. of class 1.

Class 1:

public delegate void TouchEventHandler (EventArgs e);
public event TouchEventHandler TouchBegan;
public Vector2 touchPosition;
void Update () {
if (Input.touchCount > 0) {

[Code] ...

Class 2:

void OnTouchBegan (EventArgs e) {
Debug.Log ("Ran");
}

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C++ :: How To Pass Constant BYTE Array Declared In Function As Parameter

Apr 20, 2013

I have this code:

const BYTE original[2][4] = {
{0x00, 0x00, 0x00, 0x00},
{0xFF, 0xFF, 0xFF, 0xFF}
};
void function(const BYTE** values){

[Code] ....

You might notice that the above code doesn't compile, this is the error:

cannot convert parameter 2 from 'BYTE [2][4]' to 'BYTE *'
1>
Types pointed to are unrelated; conversion requires reinterpret_cast, C-style cast or function-style cast

Even after some search I couldn't really find an answer to my problem, how do I pass the const BYTE array which I declared above in the function as a parameter (or what structure do I need to set for the function as a parameter)?

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C++ :: Passing Lambdas As Template Parameter

Oct 6, 2013

I've been playing around with this piece of code:

#include <iostream>
#include <string>
#include <algorithm>
template <void(*funky)(const std::string&)>
void callback()
{funky("Hello World!");}

[Code] ....

But when I try to build it, I get this error on line 24:could not convert template argument 'lambda' to 'void (*)(const string&) {aka void (*)(const std::basic_string<char>&)}'|

I thought the lambda expression I wrote would decay to a function pointer matching the template parameter. I can guess that the constexpr qualifier might have changed the type, but without it my compiler complains that lambda needs to be declared as constexpr...

So is there a way to pass lambda expressions as template parameters?

Without having to use std::function

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C/C++ :: Two Array Member Pass As Parameter - Expression Syntax Error For Function

Nov 8, 2013

In my project, GreedyKnap::calKnap(int nItem, int nCapacity, float fWeights, float fProfits);

This function include two array member pass as parameter. how can i do this?

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C# :: Passing Object As Parameter Creates A Copy Of It

Dec 17, 2014

Here is my issue: I am making a simple audioplayer in Xamarin.android but i want every time i change the track to make a crossfade effect. So im using 2 mediaplayers at the same time for the fade. The problem is that im defining one time the players and i pass the player as a parameter like this:

public MediaPlayer player = null;
public MediaPlayer player2 = null;
....

If i have to fadeout the player and start the next one im doing it like this:

if (player != null){
if (player.IsPlaying) {
cts = new CancellationTokenSource();
token = cts.Token;
FadeOut (player, 2000 ,token);

[Code] .....

So my problmem is that player and player2 remain always null. Why? i guess c# creates a copy of player and player2 and use this one. How i can pass a mediaplayer as parameter and always use only player and player2?

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C# :: Reference Type When Passing Struct To Parameter?

Jan 24, 2015

Does putting a ref when passing a struct to a parameter work? Say i have this code

struct struct1 {
public int i;
public void show() {
Console.WriteLine(i);

[Code] ....

The output doesn't change. The result is

0
100
500
0

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C++ :: Passing 2 Dimensional Array Through Median Function To One Of 2 Other Function

Aug 20, 2013

I want to use one median function "selectfunction" to choose one of the 2 other functions at random to pass my 2-dim array to the selected function. There is a problem in the median function

#include <iostream>
#define random(x)(rand()%x) // for random number between numbers of 0 and 1
using namespace std;
void proc1 (int iArray[][2]);
void proc2 (int iArray[][2]);
void selectfunction(int iArray[][2]);
int A[4][2] = {{1, 2} , {3, 4} , { 5, 7} , {8, 1} };

[Code]...

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C++ :: Passing Lambda As Template Parameter Not Working Correctly

May 30, 2013

I've was trying out a function template to automatically get the type of a lambda, but it seems that it won't compile

I've tried two different ways:

1.
template<class HASHER>
auto make_unordered_map(size_t bucketCount, HASHER const && hf)
-> unordered_map<string const, HASHER>&& {
return unordered_map<string const, int, HASHER>(bucketCount, hf);
} auto x = make_unordered_map(1, [](string const& key)->size_t { return key[0]; });

2.
template<class HASHER>
auto make_unordered_map(size_t bucketCount, HASHER const && hf2)
-> unordered_map<string const, int, decltype(hf2)> {
return unordered_map<string const, int, decltype(hf2)>(bucketCount, hf2);
} auto x = make_unordered_map(1, [](string const& key)->size_t { return key[0]; });

The test code are located here:

1. [URL] ....
2. [URL] ....

They are both based on the code that is stated to work in those examples. I.e.:

auto hf = [](string const& key)->size_t { return key[0]; };
unordered_map<string const, int, decltype(hf)> m (1, hf);

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C :: Print Values Of Array From Function By Passing Array?

Nov 1, 2014

I wanted to print the values of a array from a function by passing the array as well as the number of elements to be read. For a single dimensional array, this is how i have written it. It's pretty straight forward. I want to read 5 elements from the 5th element in the array.

Code:
#include<stdio.h>
void display(int array[],int size) {
int i;

[Code]....

With this code I want to print the five elements from the element present in [0][4].

But shows an error that

Code:
D:BennetCodeblocks CLearning CSingleDimentionalArray.c||In function 'main':|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|18|warning: passing argument 1 of 'display' from incompatible pointer type [enabled by default]|
D:BennetCodeblocks CLearning CSingleDimentionalArray.c|2|note: expected 'int (*)[10]' but argument is of type 'int *'|
||=== Build finished: 0 error(s), 1 warning(s) (0 minute(s), 0 second(s)) ===|

I know when you pass a array as an argument it gets decomposed into a pointer, but with a multi-dimensional array this is not the case. how this works for mult- dimensional array's?

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C++ :: Passing 2D Array To A Function Where Size Of Array Is Not Known At Runtime

Jun 27, 2014

I'm wondering if it is possible to pass a 2d array to a function where the size of the array is not known at runtime.

I've tried

function ( array[][6] ) ;

But the size of the array has to be constant so it cannot be declared later.

I've tried using a template but you still have to declare the size of the array at runtime. Is this even possible at all?

The only other way I can think of is using a dynamic 2d array but how to create one and manipulate it.

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C :: Passing Array To Function?

Jul 31, 2014

I want to pass array to function, to fill array with new values and then to print the array in the main. But I have problem because it prints me just array of zeros. Maybe the concept is wrong, I'm new with passing arrays to function.

function:

Code:
void printSum(int *return_array) {
int return_array[3];
int i;
for(i = 0; i < 3 ; i++){
return_array[i] = 5;

Code:

void printSum(int *return_array);
int main {
int m_return_array[3];
int i,j;
for(i= 0 ; i < 3 ; i++){
m_return_array[i] = 0;
} printfSum(start,m_return_array);

[Code]...

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C :: Passing 2D Array To A Function

Sep 17, 2013

I need to pass a 2D array to a function. I want to know, where I may have made a mistake. This is the piece of code that I found on the web, and I am using it to allocate my 2D array.

Code:
signed char allocate2D( int** arr2D, int rows, int cols )
{
int i;
arr2D = malloc( rows*sizeof( int* ) );
if( !arr2D )
return -1;

[Code]....

My main function passes the 2D array to the function

Code: signed char read_root_message_file( int **Root_Messages, int *num ) This is how I pass the array in the main function to the above function:

Code:
int main( int argc, char *argv[] )
{
int **Root_Messages;
...
...
Root_Messages = NULL;
read_root_message_file( Root_Messages, &num_root_msg );

[Code]....

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