C++ :: Passing 2 Dimensional Array Through Median Function To One Of 2 Other Function
Aug 20, 2013
I want to use one median function "selectfunction" to choose one of the 2 other functions at random to pass my 2-dim array to the selected function. There is a problem in the median function
#include <iostream>
#define random(x)(rand()%x) // for random number between numbers of 0 and 1
using namespace std;
void proc1 (int iArray[][2]);
void proc2 (int iArray[][2]);
void selectfunction(int iArray[][2]);
int A[4][2] = {{1, 2} , {3, 4} , { 5, 7} , {8, 1} };
This seems simple enough but I'm missing something here to make this code work.What I'm trying to do is print the contents of the two dimensional array in 25 rows and 4 columns. I experimented with something similar to this code when I initialized the array with numbers.
I'm getting garbage. I tried including the name of the array in the cin object but I got an error message that says "no match for operator '>>'. When I take the name of the array out, the program compiles but I get garbage. Program is suppose to reads data from a file of 25 students and calculates test scores and class grade average output each student's name score, letter grade and grade average. I would be happy at this point if I could just print out something that wasn't garbage.
Here is the code.
#include <iostream> #include <iomanip> #include <cmath> #include <string> #include <fstream> using namespace std; //const const int Array_Row = 25; const int Array_Col = 4;
I'm trying to write code that implements [median filtering] on a two-dimensional array.
Here's an image to illustrate:
The program starts at the beginning of the array. The maximum array size is 100. I know that I can use an array like:
int a[100][100];
to store the input, and that I can iterate over a part of this array using two `for` loops like this:
for(i=0;i<size_filter;i++) for(j=0;j<size_filter;j++) temp[i][j]=a[i][j] // not so sure
But how can I make this code loop over the neighbors of every element in the array, calculate their median, and replace the center element with the median?
For some examples of what I'm trying to do, let's say that the input is a 5x5 matrix, so the input size is 5. And I want to run a 3x3 median filter on it, i.e. each element should be replaced by the median of the 3x3 elements surrounding it.
The program starts at the corner index (0,0). For this index, it scans the 3x3 region surrounding it (of which only four indexes actually lie within the input array), which contains the values 0, 0, 1, and 0. The median of these values is 0, so that's what the code should output for this array index.
In the picture below, the number in -band - is the center cell, and the plain * and * numbers are its neighbors within the 3x3 region surrounding it:
This time, the elements in the 3x3 region (excluding those outside the input array) have the values 0, 0, 0, 1, 0, and 0, and again, their median is therefore 0.
Here's yet another example, this time from the middle of the input, at center index (3,2):
I am so close to finishing this program. It will find the median of an array of 5 values. I have one last error that I cannot seem to get to go away. Here's the code:
#include <algorithm> #include <functional> #include <array> #include <iostream> using namespace std; int main() { int integer1, integer2, integer3, integer4, integer5;
[Code] .....
The error states: "IntelliSense: no instance of overloaded function "std::nth_element" matches the argument list, argument types are: (std::_Array_iterator, std::_Array_iterator, unsigned int, std::_Array_iterator)
I want to pass array to function, to fill array with new values and then to print the array in the main. But I have problem because it prints me just array of zeros. Maybe the concept is wrong, I'm new with passing arrays to function.
function:
Code: void printSum(int *return_array) { int return_array[3]; int i; for(i = 0; i < 3 ; i++){ return_array[i] = 5;
Code:
void printSum(int *return_array); int main { int m_return_array[3]; int i,j; for(i= 0 ; i < 3 ; i++){ m_return_array[i] = 0; } printfSum(start,m_return_array);
I need to pass a 2D array to a function. I want to know, where I may have made a mistake. This is the piece of code that I found on the web, and I am using it to allocate my 2D array.
Code: signed char allocate2D( int** arr2D, int rows, int cols ) { int i; arr2D = malloc( rows*sizeof( int* ) ); if( !arr2D ) return -1;
[Code]....
My main function passes the 2D array to the function
Code: signed char read_root_message_file( int **Root_Messages, int *num ) This is how I pass the array in the main function to the above function:
Code: int main( int argc, char *argv[] ) { int **Root_Messages; ... ... Root_Messages = NULL; read_root_message_file( Root_Messages, &num_root_msg );
I am following a tutorial and the topic was passing array to function so i tried to do a BMI calculator by myself. I am using code blocks to compile the codes, it is actually working while using compiler's run button. But when I open the exe file, its closing the window after entering the persons' weights and heights. Here is the code
Code:
// Passing array to function example BMI calculator of n person #include<stdio.h> #include<math.h> void assess(float bmi[],int a); int main(void){ int n,i,j; }
i have defined an object which is an array of my class called Player now i want to pass this whole array as a parameter in a function, i think it will be done by using pointers but i am not able to figure out how it is done?
Player player[4]; void showscoreboard(" ", int cround){} " " represents the blank where the array should b passed.
Write a program that inputs 10 integers from the console into an array, and removes the duplicate array elements and prints the array. By removing, I mean that you should make it appear as if the elements hadn't been there. You may assume that all the integers are between 0 and 100, Write at least 1 function in addition to the main function, and pass an array into that function as a parameter. e.g.
Please enter your 10 numbers: 1 2 3 4 5 6 7 8 9 10 The array contains: 1 2 3 4 5 6 7 8 9 10
Please enter your 10 numbers: 1 1 3 3 3 6 7 8 9 9 The array contains: 1 3 6 7 8 9
Please enter your 10 numbers: 1 1 1 1 1 1 1 1 1 1 The array contains: 1
The bolded area is where I'm having trouble. How I can go about doing this, passing an array into the function as a parameter?
Here is my code:
#include "stdafx.h" #include <iostream> using namespace std; int main () { const int MAX = 10; int a[MAX] = {0}; int i;
I am trying to pass a dynamic array to a function which will:
- Copy the contents of the array to a temporary dynamic array - Change the array passed in to one size bigger - Copy the elements from the temp array back into the newly changed array - Insert an item into the last spot of the array
Here is my code:
#include <iostream> using namespace std ;
void make_array ( int Old [] , int & old_size , int toInsert ) ; void zero_array ( int arry [] , int arry_size ) ; void print_array ( int arry [] , int arry_size ) ;
[Code] .....
The output seems like a memory address but is just a very large number, what have I done incorrectly to cause this?
In the below program, When the getline function is called, it passes a char array of size 1000 by VALUE. It must have passed by value because there is no pointer or reference in the argument list of the getline function definition. And if that's the case, when exiting the getline function, isn't the s[] char array destroyed? And if it is destroyed, then when we reference line in the copy function, what are we actually copying?
#include <stdio.h> #define MAXLINE 1000/* maximum input line length */ int getline(char line[], int maxline); void copy(char to[], char from[]); /* print the longest input line */ main() {
how can i pass an array as an argument to the function? in getCoin() fcn, I am supposed to pass coins array as an argument to the function. fcn prompts user to enter coin(Date, Type and Country). values entered by user are read and assigned to the coins array. I tried the code below.
//# include "Coins.h"; #include <iostream> #include <string> using namespace std;
After passing the address of the first element (&array[0][0]) of a multidimensional integer array to a function with a "const int*" parameter, parameter seems to be pointing to the wrong values, which are not the actual elements of the passed array.
First, why does this happen ?
Second, how can I fix this without changing the parameter type into a multidimensional int array ?
