C++ :: Ask User For A Positive Integer Value And Then Prints Out All Perfect Numbers
Sep 17, 2013
Write a program asks the user for a positive integer value and then prints out all perfect numbers from 1 to that positive integer. I have been trying for some time, i found a way to check if its a perfect number or not but could not find a way to prints out all perfect numbers from 1 to that positive integer. I am here so far.
#include<iostream>
#include<iomanip>
using namespace std;
int main(){
int n,i=1,sum=0;
cout<<"Enter a number: ";
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0
if n = 6 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0 6==5==4==3==2==1==0
Design an algorithm using flowchart or pseudo-code to prompt the user for a series of positive integer values. Calculate the average of these values and display the average at the end of the program. Assume that the user types the sentinel value -1 to indicate end of data entry.
Sample input-output: Enter a positive integer (-1 to end) : 5 Enter a positive integer (-1 to end) : 7 Enter a positive integer (-1 to end) : 6 Enter a positive integer (-1 to end) : -1
The average value is: 6
I searched online and found out this solution however it is only for three numbers.Is there any way of modifying this to include the sum of x numbers / number of x(integers) to find the average?
So I have to make a program that allows the user to enter both positive and negative numbers and the program is suppose to calculate the sum of only the positive values while ignoring the negative values. Also it is to be a sentinel-controlled loop with a number ending the set of values.
Find the perfect numbers between a starting value and a finishing value entered by the users. Display the results to the screen.
I've been told that I need to modify things under the void and the calcdiv in my main () but I can't seem to figure it out. It needs display the perfect numbers between the starting and finishing value. e.g. 28 and 429.
#include <cstdio> #include <iostream> #include <cstdlib> #include <cmath> using namespace std; void calcdiv(int number) { for (int i=1;i<=number/2;i++)
The problem that I am having is that , the program outputs numbers that are perfect numbers and im not sure where i can add a statement to make it so that if it isn't a perfect number it doesn't output...
#include<iostream>// allows user input/output #include<conio.h> #include<fstream>//data file / result file #include<iomanip> #include<cmath> // math function #define in_file "data.txt" #define out_file "result.txt"
I have to write a program where the user will input integer numbers. How many numbers they enter is unknown, therefor you should use a repetition structure for the input. When the user is done, they will enter -1 to exit.
Create a dynamic array if the size=2( the initial size must be 2) Repeat until user enters -1.
I have to do this without using vectors.
This is what i have, I cannot figure out what to put in main. I was thinking of a do-while?
Code: #include <iostream> using namespace std; void resize(int *[], int); int main() { int *listDyn; int size=2;
You pros are once newbies like us. Hoped you might take a little time sharing your expertise. Got freaked out when our teacher gave us this activity, where she haven't taught this to us yet. So this is the activity (LOOPING) :
Write a program that accepts a positive integer. The program should be the same from the given output. Use do while to allow the user to continue or not.
OUTPUT must be:
n = 5 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0
if n = 6 0 1==0 2==1==0 3==2==1==0 4==3==2==1==0 5==4==3==2==1==0 6==5==4==3==2==1==0
I have an embedded microcontroller system communicating with a similar system by radio. The api for the radio requires data to be transmitted as an unsigned char array. It will always transmit a positive integer in the range 0 to 255.When I receive the data I am having difficult in extracting this positive integer.
Code: unsigned char rxData[4]={'1','2','3',''}; int inVal=0;
//want to assign inVal whatever number was transmitted
E.g. 123
I've been at this for a week and have tried at least 10 different approaches including the use of the atoi(), copying the absolute value of each element of rxData into another char array, reinterpret_cast, and others.
My question is are there various ways that I can approach this program. I.e. do I have to use switch statements?
/* NumToTxt Creates the appropriate word form of any positive integer up to 999999 */
#include <iostream> using namespace std; //represents the largest array size for the user entered number const int MAXNUMARRAY = 6; /*represents the largest number that can be entered + 1. Used to calculate the first number used to truncate the user entered number and to display an error message to the user that tells the user the largest number that the program will accept. */ const int BIGGESTNUMBER = 1000000;
convert a positive integer code into its english name equivalent for digit. A valid code is of size between four (4) to six (6) digits inclusive. A zero is not allowed in the code.
example : if the input is 234056 the output is : INVALID CODE (PRESENCE OF ZERO) if the input is 23456 the output is : TWO THREE FOUR FIVE SIX if the input is 9349 the output is : NINE THREE FOUR NINE if the input is 245 the output is : INVALID CODE (3 DIGITS) if the input is 2344567 the output is : INVALID CODE (7 DIGITS)
step 1 : input code step 2 : count the number of digits in the code step 3 : if there is a zero in the code, "INVALID CODE (PRESENCE OF ZERO)" go to step 4 step 4 : if number of digits is mode or equal than 4 and less or equal than 6, go to step 5 else display the following message "INVALID CODE (<number of digits> DIGITS) step 5 : call a function called digit_name to convert each digit into its equivalent english name. display the result step 6 : print the digits in reverse order eg; if input is 13453, reverse order is 35431
[code]#include <iostream> #include <time.h> using namespace std;
int main() { srand(time(NULL));
[Code] .....
I am getting these errors when i compile it
random.cpp: In function âint main()â: random.cpp:23: error: expected â,â or â;â before numeric constant random.cpp:24: error: âRâ was not declared in this scope random.cpp:25: error: âRâ was not declared in this scope random.cpp:26: error: âRâ was not declared in this scope random.cpp:27: error: âRâ was not declared in this scope random.cpp:28: error: âRâ was not declared in this scope
I'm trying to create a program that prints a number of dots specified by the user, there 4 options to do any loop type or to exit the menu. i'm having problems making it so that after you enter a value and it displays the specified number of dots it clears the results. Also we have to make it so that if a negative integer is entered it still prints out the appropriate amount of dots ie: user puts -9 it prints 9 dots, i know you use the abs() function but it doesn't seem to be working for me. I'm assuming my problem with the abs function is i'm not using it correctly. Use case 1 as the example for the rest because I'm trying to implement everything on one case at a time
Code:
int main() { //initialization statements int Num1 = 0; char dot = '.';
I am having an error at line 21. Specifically the code where it says "list[num]=x"
How am I able to fix this code to do what I want? The purpose of my program is to enter in positive numbers in an array (and having it end when 0 is typed) My program also accepts negative values but will ignore them when it is outputted. I believe I have all the code right except for line 21.
#include<iostream> using namespace std; const int ARRAY_SIZE(25); void read_list(const int list[],const int ARRAY_SIZE); int main() { int list[ARRAY_SIZE]; read_list(list, ARRAY_SIZE);
Write a C++ program that will input from the user a positive number n and find its factorial. Don’t forget to validate the input. The factorial of a positive integer n (denoted by n!) is defines as the product of the integers from 1 to n.
n! = 1* 2 * 3 * ... * (n - 1) * n
You should allow the user to continue working with your program for additional data sets.
Sample output:
Please enter a number: 5 5! = 120 Would you like to continue (Y/N)?Y Please enter a number: 3 3! = 6
Would you like to continue (Y/N)?N Good Bye!!
My code for what i think I'm doing is as follows:
#include <iostream> using namespace std; int main(){ int i=1; int n;
Write a program which reads a stream of numbers from a file, and writes only the positive numbers to a second file. The user should be prompted to enter the names of both the input file and output file in main(), and then main() will open both files. Another function named process() must then be called to read all the numbers from the input file and write the positive numbers to the output file. Note that you must pass the open stream variables for each file as arguments to the process() function, and that you need to (always) double check that the files opened successfully before using them.
This is what I have so far but its not working out!
#include <iostream> #include <fstream> #include <stdlib.h> using namespace std; int process(ifstream &inf, ofstream &outf);
Write a function that raises an integer to a positive integer power. Call the function x_to_the_n taking two integer arguments x and n. Have the function return a long int, which represents the results of calculating x^n.Here's my code:
Code:
#include <stdio.h> long int x_to_the_n(int x, int n) { int i; long int acc = 1;
for(i = 1; i <= n; ++i) acc *= x; }
[code]...
It compiles OK, but when I run it the program stops after entering the number (x) and power (n).
I need to create a program that prints a certain number of asterisks based on user input. The user inputs 5 and I want my program to output "*****". How would I do this in C? I've tried printf("%#**", myvariable) but this does not work it only prints "*".
I have a program that makes change from an amount. It works fine, but the output is the correct output looped over and over. I have tried everything, but it still doesn't work. For example, a amount of 98 should print
Write a program that calculates the average of a stream of positive numbers. The user can enter as many positive numbers as they want, and they will indicate that they are finished by entering a negative number. For this program, treat zero as a positive number, i.e., zero counts as a number that goes into the average. Of course, the negative number should not be part of the average. You must use a function to read in the numbers, keep track of the running sum and count, compute the average, and return the average to the main() function. Note that you must use a loop to do this, as you don't know how many numbers the user will enter ahead of time. I am having problem writing a loop program for it..
