C :: Create A Program That Prints A Number Of Dots Specified By User
Oct 8, 2013
I'm trying to create a program that prints a number of dots specified by the user, there 4 options to do any loop type or to exit the menu. i'm having problems making it so that after you enter a value and it displays the specified number of dots it clears the results. Also we have to make it so that if a negative integer is entered it still prints out the appropriate amount of dots ie: user puts -9 it prints 9 dots, i know you use the abs() function but it doesn't seem to be working for me. I'm assuming my problem with the abs function is i'm not using it correctly. Use case 1 as the example for the rest because I'm trying to implement everything on one case at a time
Code:
int main() {
//initialization statements
int Num1 = 0;
char dot = '.';
I need to create a program that prints a certain number of asterisks based on user input. The user inputs 5 and I want my program to output "*****". How would I do this in C? I've tried printf("%#**", myvariable) but this does not work it only prints "*".
Im trying to create a program that has the user input a 5 digit number. If it's between 10000 & 99999, it will do one thing..(just saying 'yes' for now. Outside those numbers will prompt the user to input again. However, if the user inputs the exact digits 76087, it should display 'term'.
This current code is displaying 'term' whenever the user inputs the 5 digits.
Code:
#include <iostream> using namespace std; int main() { int pin; cout << "Welcome to Movie Food Enter your 5-digit pin code: " ;
I'm just getting back into the swing of things after a long time of not programming. I'm trying to create a program which takes in command line arguments and prints the last one. My code is as follows:
#include <iostream> #include <vector> #include <string> using namespace std; int main() { string x; vector<string> arguments;
[Code]...
And the error message I receive, a simple but frustrating one, is as follows:
Enter arguments, enter STOP to stop: Segmentation fault...
I have a program that makes change from an amount. It works fine, but the output is the correct output looped over and over. I have tried everything, but it still doesn't work. For example, a amount of 98 should print
I have a program where the user inputs a line of integers, and then all unique ones are outputted. It works fine-almost. It prints the numbers correctly, but prints them more than once and I'm not sure why.
Code: #include <iostream> using namespace std; int main ( ) {
I would like to understand a function on strings. Below is a code that I took from my teacher where the user inputs a string and prints out the length of the string.
Code: #include <stdio.h> #include <string.h> int main() { char str[100]; int i = 0;
[Code] ....
Now I understand that it returns the count in "int" so my question is:
Let's say i declared
Code: int count = 0; at the beginning of the code and then made Code: count = strlen(str); why wouldn't i have the same result? Is there a way to do it also?
i want to create a program that allows a user to list all create new items, list those items, delete an item, modify an item, search for an item how can i do that This is my work so far
I know it would be easier to create an int array, but I want the program to create integers as the user requests. For example, if the user enters 4, the program creates 4 integers with the names input. Each integer is better as an individual integer, not an element in an array.I'm not sure if this is a possibility with C++.
I want to create a grading program that the user inputs a name and then on that value (name) there is a vector of doubles to represent his/her mark and then calculates an average how would I go about doing this?
I need to create a program that will prompt the user for an input, then it will save their input to a file and then it will prompt the user to input "Open" and then the file containing their first input, will open up and show their input.
Create a program that will let the user input an amount in the form (367). The Program should determine the no. of coins for each dominations : 50,25,10,5,1. (using Turbo C)
I have an assignment in which i must create a program which prompts for user input of current and birth date, which will compare said dates and output if its your birthday or not. I've completed a large portion of it, but cannot figure out how to get the user input of month as an integer such a 2 into February.
#include <iostream> using namespace std; class DayOfYear { public: void input();
Write a program asks the user for a positive integer value and then prints out all perfect numbers from 1 to that positive integer. I have been trying for some time, i found a way to check if its a perfect number or not but could not find a way to prints out all perfect numbers from 1 to that positive integer. I am here so far.
#include<iostream> #include<iomanip> using namespace std; int main(){ int n,i=1,sum=0; cout<<"Enter a number: ";
C programming: I want to creat a program that asks the user to input the integer lengths of three sides of a triangle, and if so whether the triangle is a right-angled, acute or obtuse one. i am having some doubts about the if, else if statements. I never seem to know how and in what order to use them.
Code:
#include <stdio.h> #include <stdlib.h> #include <math.h> int main(int argc, char *argv[]){ int SideA; int SideB; int SideC; }
you have to use the brackets to enclose just like I used in my code right here.It is a simple while loop that is a countdown.
#include <iostream> using namespace std; int main() { int n =10; while(n>0){ cout << n << ", ";
[code].....
when I take the brackets away from my while loop, my code will still execute but it just prints out the number "10" repeatedly. I was just wondering why it does this and why the compiler does not throw out an error when I leave off the brackets after the "while()".
So I'm trying to make a program that asks the user for a number and then prints a statement the same number of times the user entered. 3 different statements, using the 3 loops (for, while, and do while). I made the program but for some reason the statement from the do while loop goes off infinitely.
#include <iostream> #include <ctime> #include <cstdlib> //This program prompts the user to select a number between 2 and 12 //computer throws two dices //player win if selected number matches the sum of the two dices thrown by computer
Write a C++ program that asks the user to enter an even number only. If the user enters an odd number the program should use input validation to ask the user to enter another number.
- The user can enter as many numbers as he wants
- The program should also keep a count of how many numbers entered and display how many odd and even numbers entered.
i have only recently got into programming. i have this homework assignment that is frying my brains, the program needs to take a number from the user and give the 'reduced' sum. for example: if the user enters 888 then the sum should be: 6. it takes the number and adds its digits im just looking for a direction to where my problem is
#include "iostream.h" int reduction (int number) { return number/10+number%10; } int main() { int number,loopcount; cout<< "please enter a number"<<endl; cin>>number;
im writing a program that asks the user to input a number 1-10 and will transform it into the roman numeral of that number but it seems that its not after the user inouts the number nothing will output
#include <iostream> #include<iomanip> using namespace std;
The problem that I am having is that , the program outputs numbers that are perfect numbers and im not sure where i can add a statement to make it so that if it isn't a perfect number it doesn't output...
#include<iostream>// allows user input/output #include<conio.h> #include<fstream>//data file / result file #include<iomanip> #include<cmath> // math function #define in_file "data.txt" #define out_file "result.txt"
So I need to write a program which tells the user if the number they input is prime or not. I have done so and included the code below. My problem is that I need to allow the user to input if they want to enter another number after the first one using y or n and I am having trouble figure it out.
#include <cstdlib> #include <iostream> using namespace std;
