C++ :: Simple While Loop - Prints Out Number 10 Repeatedly
Apr 30, 2014
I know for while loops you type
while(argument){
do whatever
}
you have to use the brackets to enclose just like I used in my code right here.It is a simple while loop that is a countdown.
#include <iostream>
using namespace std;
int main() {
int n =10;
while(n>0){
cout << n << ", ";
[code].....
when I take the brackets away from my while loop, my code will still execute but it just prints out the number "10" repeatedly. I was just wondering why it does this and why the compiler does not throw out an error when I leave off the brackets after the "while()".
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Jan 27, 2015
I have a program that makes change from an amount. It works fine, but the output is the correct output looped over and over. I have tried everything, but it still doesn't work. For example, a amount of 98 should print
3 quarters
2 dimes
0 nickles
3 pennies
but instead it prints
3 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
0 quarters
2 dimes
0 nickels
3 pennies
Why it's doing this?
Code:
#include <iostream>
using namespace std;
int coinscount(int& amount, int value) {
int tracker = 0;
int amountdimes = amount;
[Code].....
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Jun 17, 2014
When I run this code
#include <stdio.h>
int main(int argc, char* argv[])
{
int i=0;
int count=0;
while(i<5)
i++;
count++;
printf("The value of count is: %d", count);
return 0;
}
It only prints: The value of count is 1. I'm confused on why it doesnt print the value of the count is 5
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Oct 8, 2013
I'm trying to create a program that prints a number of dots specified by the user, there 4 options to do any loop type or to exit the menu. i'm having problems making it so that after you enter a value and it displays the specified number of dots it clears the results. Also we have to make it so that if a negative integer is entered it still prints out the appropriate amount of dots ie: user puts -9 it prints 9 dots, i know you use the abs() function but it doesn't seem to be working for me. I'm assuming my problem with the abs function is i'm not using it correctly. Use case 1 as the example for the rest because I'm trying to implement everything on one case at a time
Code:
int main() {
//initialization statements
int Num1 = 0;
char dot = '.';
[code]....
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Feb 27, 2014
3. Write a program that reads a sequence of positive integers and prints out their sum, except that if the same number occurs several times consecutively, ignore all but the first. Assume an input of 0 marks the end of the input. For example, if the input is 3 8 5 5 4 9 1 1 1 1 8 0 then you should print 38 (i.e., ignore one of the 5's and three of the 1's).
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Apr 12, 2015
I need to create a program that prints a certain number of asterisks based on user input. The user inputs 5 and I want my program to output "*****". How would I do this in C? I've tried printf("%#**", myvariable) but this does not work it only prints "*".
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Feb 9, 2015
I have a program where the user inputs a line of integers, and then all unique ones are outputted. It works fine-almost. It prints the numbers correctly, but prints them more than once and I'm not sure why.
Code: #include <iostream>
using namespace std;
int main ( ) {
[Code]......
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May 11, 2014
My address book will be simple, and the thing's that I'm expecting to use in it are :
Pointers, Linked Lists
Malloc
Structs
Typedefs
Makefile, header file
Putting functions into different program files
I have started the program trying to create a struct, and getting it working with a couple of entries before going onto user input and splitting it up.
Code:
#include <stdio.h>
#include <stdlib.h>
int main(void) {
// Struct type address book. Just a name, a number and a pointer
[Code] .....
I'm a bit lost at this point... My knee jerk thought is to create a for loop, and cycle through the list.
I'm not sure how this would apply to this though? Without using the familiar type of print loop such as :
Code:
for (i = 0; ;i++) {
printf("%i
", array[i];
}
I'm thinking that I need to create a temporary struct that can be used to assign the value of the next struct in the list, and then somehow print from that....
I'll try and write the logic out :
while temp != NULL (The last node value is assigned NULL to show us where the end of the list is)
create a temporary pointer that can be used to keep track of where we are in the list.
print out the current entry name and number
then assign the temp pointer value to the * next of the current struct. So if we are in entry1 the *next should be the address of entry 2.
Print out entry 2 name and number, assign entry 2 next to the temp value.
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Jun 30, 2013
I have a problem with my simple operations calculator code (using C, in Code::Blocks). I am required to use a while loop statement so the user can execute multiple step operations without re-opening the program. When I launch the program, I get through the first session fine, but when I'm on the second session, when entering the two operands and press enter (to calculate), it just gives me the return and say press any key to continue (exit).Here is the code:
Code:
# include <stdio.h>
int main()
{
int num1, num2;
char op;
int finished = 0;
}
[code]....
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Sep 26, 2014
I started to write a program that repeatedly reads in values for a,b and c and find the root of the polynomial
ax^2 + bx + c = 0
The program should print out for example:
two complex roots: root1 = -1.00000 + i*1.41421
root2 = -1.00000 - i*1.41421
My code:
#include <stdio.h>
#include <math.h>
int main(void){
int a,b,c;
printf("Choose the values of a, b and c for the equation ax^2 + bx + c");
scanf("%d%d%d
",a,b,c);
[code].....
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May 28, 2013
I have a certain piece of code that I want to run every 2 minutes. One of my ideas is to get the time and modules that with whatever number represents 2 minutes. Would this work?
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Oct 2, 2013
Let's assume "person" is a class that has a member "age", and personptr is a pointer to a person object.
doStuff(personptr->age);
doMoreStuff(personptr->age);
andSomethingElse(personptr->age);
andSomethingElse(personptr->age);
Is this bad for performance? Is the following better or doesn't it matter?
int person_age = personptr->age;
doStuff(person_age);
doMoreStuff(person_age);
andSomethingElse(person_age);
andSomethingElse(person_age);
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Nov 29, 2013
I am asking for input for a char by using the _getch() function. The thing is that when a key is pressed multiple times it screws the program because it executes every single key that is entered.
I am asking for the user to enter a letter that will determine an action to be used in battle, like attack, magic, "use item", etc.
char option;
cout<<"Enter your choice for battle: ";
option=getch();
if(option=='a')
//Executes an attack
else if(option=='b')
//Opens magic menu
else if(option=='c')
//Opens item menu
Suppose the user enters a character, then the program executes an action by the enemy monster. This is where the problem arises, if the user entered multiple keys or if he enters input during the time the monster attacks, the next time it is the user's turn it will execute the first attack automatically because it keeps reading the input.
I want to know how to cut it off, so that it doesn't ruin the program like that.
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May 1, 2013
Write a user-friendly C++ program that allows a user to select repeatedly an operation to be performed from a displayed menu of actions. The menu includes the following items:
1. Simple Statistics
2. Vector Addition
3. Dot Product
4. Exit
The menu actions are described by the following points:
Simple Statistics: This action includes finding the average, and standard deviation of a list of data items. The option should allow the user to specify the name of a file from which the data are read into an array. All the results of this option are displayed on the screen.
Vector Addition: This action allows the user to enter the name of a file from which two vectors, V1 and V2, of equal size N are read. Accordingly, the two vectors are added, and displayed along with the resultant vector on the screen. Your program should check that the two added vectors are of the same size. Otherwise, the program should display a message and allow the user to make another choice from the menu.
Dot Product: This action is similar to the Vector Addition in terms of input, output, and checking validity of the vector operands.
Exit: This action terminates the program.
Your program should include at least the following functions:
1. A function, called ReadVector(), which reads a vector of any size from a given file name, and returns the vector and its size to the caller. The function prototype is defined as follows:
void ReadVector(double V[], int &size, ifstream infile);
2. A function, called DisplayMenu(), which displays the menu and returns the user’s choice as an integer value between 1 and 4. The function prototype is defined as follows:
int DisplayMenu (void);
3. A function, called VectorAdd(), which performs the addition of two vectors, A and B, and returns the resultant vector, C. The function prototype is defined as follows:
void VectorAdd(const double A[], const double B[], double C[], int size);
The sum of two vectors, A = (a1, a2, …, an) and B = (b1, b2, …, bn) of size n, is defined as: C = A + B.
Where, C = (c1, c2, …, cn), and ci = ai + bi, for1 i n .
4. A function, called DotProduct(), which performs the dot product of two vectors, A and B, and returns the result. The function prototype is defined as follows:
void DotProduct(const double A[], const double B[], int size, double &result);
The dot-product of two vectors A = (a1, a2, …, an) and B = (b1, b2, …, bn) of size n is defined as
n n
n
i
i i b a ....... b a b a b a B . A
1 1 2 2
1
5. A function, called Simple_Stat(), which finds the maximum, minimum, average, and standard deviation of a list of data items passed to it by a one-dimensional array. The function returns the average and standard deviation values. The function prototype is defined as follows:
void Simple_Stat(const double list[], int size, double &average, double
&std_dev);
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Oct 29, 2013
I have been trying to make a program that asks for username and password, and if it is wrong it will loop back to the top. But i only want it to loop a set number of times, how can i do this? This is my code so far
string username;
string password;
cout << "Enter username: ";
getline(cin, username, '
[Code] ....
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May 20, 2014
I'm doing some exercises in c and i have to do one which shows me this output:
Quote
I=0 J=1
I=0 J=2
I=0 J=3
I=0.2 J=1.2
I=0.2 J=2.2
I=0.2 J=3.2
.....
I=2 J=?
I=2 J=?
I=2 J=?
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Oct 7, 2014
I am supposed to have a loop that terminates when the difference between two successive values of 'e' differ by less than 0.0000001 (6 zeroes). So far I have written this much of the code:
#include <stdio.h>
double eCalc(int terms, double e);
int main() {
int dummy;
int terms;
double e;
[Code] ...
It will not even run. Compiler code errors are as such:
error C4700: uninitialized local variable 'e' used
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Nov 25, 2013
how i can find the 5 without loop?
vector<int>i;
vector<int>j;
i.push_back(1);
i.push_back(2);
j.push_back(3);
j.push_back(4);
j.push_back(5);
[Code]...
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Jan 2, 2014
I've researched this quite a bit and the overwhelming answer I've been seeing for a loop generating the same pseudo-random number is that you're seeing the random number generator inside the loop, but that is not the case with me . . . At least not that I can see.
Basically, as I mentioned, I have a loop "birthing" new bunnies in a loop. And all the new bunnies are being created with the same name and other details.
Here is the code:
void BunnyGraduation::breed() {
for (unsigned int male = 0; male < colony.size(); male++) {
if (colony.at(male).getSex() == Bunny::Sex::MALE && colony.at(male).getRadioactiveMutantVampireBunny() != true && colony.at(male).getAge() >= AGEOFCONSENT) {
for (unsigned int female = 0; female < colony.size(); female++) {
[Code] ....
srand(time(0)); is seeded ONCE in the constructor of the bunny object itself. . . Now, come to think of it, the constructor is called every time an object is created . . . And the constructor contains the srand() . . . and the constructor is being called in a loop. . . So therefore, yes, the srand() is being called inside the loop.
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Feb 10, 2014
I need to calculate the expected time it takes to do an activity using a formula provided and after the loop is broken it needs to show the number of projects processed and the project with the longest expected time. I've got everything working except for finding the the project with the longest expected time. What I have here just keeps displaying the number of the last project processed regardless of if it was the largest or not, specifically lines 54-61 is what i can't seem to figure out.
#include <stdio.h>
int main( void ) {
unsigned int counter;
int projectnumber;
int optimistictime;
int realistictime;
[Code] .....
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Nov 15, 2013
I've been working on a program on and off for around a week now and I've been struggling towards the end of the program.First of all, the program is a maths quiz which generates two random numbers per question.I'll give you one part of my code:
Code:
srand ( time(NULL) ); //seeds the random number generator
int score = 0;
int a = rand()%12 +1; //generates a random num between 1-12
int b = rand()%12 +1;
int c = a+b;
int d;
}
[code]....
I've basically copied the above code 10 times and changed the variables by going through the alphabet e.g.
Code:
int a = rand()%12 +1; //generates a random num between 1-12
int b = rand()%12 +1;
int c = a+b;
int d; all the way to
Code:
int an = rand()%12 +1;
int ao = rand()%12 +1;
int ap = rand()%12 +1;
int aq = an+ao-ap;
int ar;
Now what I'm going to do is remove all the declared variables and create a loop. But my problem is; If I wanted to declare four variables for e.g.
Code:
int a = rand()%12 +1;
int b = rand()%12 +1;
int c = rand()%12 +1;
int d = a+b-c;
Would I place the srand( time(NULL)); inside the loop? it's confusing because I know an example of a basic loop with an array would be:
Code:
#include <stdio.h>
#include <conio.h>
int main(void)
{
int test[5]={21,18,47,21,4};
int I;
int total=0;
for (I=0;i<5;i++)
total += test[I];
}
[code]....
how or where to include the random number generator in the loop and to make it ask 10 questions at random.
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Sep 18, 2014
I want to create a specific number of for loops each in another loop, as in example:
for(i=0;i<9;i++)
{
for(j=0;j<9;j++)
{
for(k=0;k<9;k++)
{
//some stuff
}
}
}
In this example there are 3 loops, but what if i want to create e.g. 10 such loops, and program reads a number of loops from a txt? It is needed for checking numbers.
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Dec 11, 2013
Something that does something like this
at this point run a loop for all players, in this loop use random to determine the face and depending on the face run a loop (for roll again etc) or give next user the chance.
And this loop is 2-12 people, all rolling die.
They draw 3 die out of a cup of 12.
Then they roll the 3 die, getting fish, hook, or boot on each die.
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Feb 21, 2014
My program asks me to write a C++ program that generates a random number between 1-100, and lets the user guess the number until he/she guesses correctly.
I have every thing done but my loop will not end. I know I have to "update" the loop to end it but I don't know what that means.
#include <iostream>
#include <iomanip>
#include <ctime>
using namespace std;
int main() {
srand(time(NULL)); //the function that generates random numbers
[Code] .....
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Oct 24, 2014
I have to write a C++ program that picks a random number between 0 and 49. If the number is even lets say 30, then the computer will display 30, 32, 34, 36... all the way till 100, if its odd lets say 17, then the computer will display 17, 19.. till 99. I got the computer picking a random number, I just can't figure out how to display every other number using a for loop statement. Here's my code for random number generator:
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
[Code] ....
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Dec 4, 2014
I am unable to find why my code is going into infinite loop as below. This works perfectly fine if I keep entering just the integer values but if I enter a float number it ends up in an infinite loop
int main() {
int x;
while(1){
cin>>x;
cout <<x;
}
return 0;
}
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